PHYSICS COLLEGE

A person is pushing a lawnmower of mass m D 38 kg and with h D 0:75 m, d D 0:25 m, `A D 0:28 m, and `B D 0:36 m. Assuming that the force exerted on the lawnmower by the person is completely horizontal and that the mass center of the lawnmower is at G, and neglecting the rotational inertia of the wheels, determine the minimum value of this force that causes the rear wheels (labeled A) to lift off the ground. In addition, determine the corresponding acceleration of the mower.

Answers

Answer 1

Answer:

Answer:

The acceleration of the mower will be "4.7 m/s²".

Explanation:

Balance of vertical force will be:

⇒ $Ra + Rb = mg$

For wheel to take off at A,

⇒ $Ra = 0$

Hence,

$Rb=mg$

Balancing moments about G will be:

⇒ $F* h = Rb* LB$

As we know,

Force, F = $(Rb* LB )/(h)$

On putting the values, we get

⇒ = $(38* 9.81* 0.36)/(0.75)$

⇒ = $178.9 \ N$

Now,

Acceleration, a = $(F)/(m)$

⇒ = $(178.9)/(38)$

⇒ = $4.7 \ m/s^2$

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1. A mass suspended from a spring oscillates vertically with amplitude of 15 cm. At what distance from the equilibrium position will the speed of the mass be 25% of its maximum speed?

Answers

Answer:

The value of the distance is $\bf{14.52~cm}$ .

Explanation:

The velocity of a particle(v) executing SHM is

$v = \omega \sqrt{A^(2) - x^(2)}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~`~(1)$

where, $\omega$ is the angular frequency, $A$ is the amplitude of the oscillation and $x$ is the displacement of the particle at any instant of time.

The velocity of the particle will be maximum when the particle will cross its equilibrium position, i.e., $x = 0$ .

The maximum velocity( $\bf{v_(m)}$ ) is

$v_(m) = \omega A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)$

Divide equation (1) by equation(2).

$(v)/(v_(m)) = \frac{\sqrt{A^(2) - x^(2)}}{A}~~~~~~~~~~~~~~~~~~~~~~~~~~~(3)$

Given, $v = 0.25 v_(m)$ and $A = 15~cm$ . Substitute these values in equation (3).

$&& (1)/(4) = \frac{\sqrt{15^(2) - x^(2)}}{15}\n&or,& A = 14.52~cm$

A lead ball is dropped into a lake from a diving board 5.0 m above the water. After entering the water, it sinks to the bottom with a constant velocity equal to the velocity with which it hit the water. The ball reaches the bottom 3.0 s after it is released. How deep is the lake

Answers

Answer:

$|D_(depth) |=19.697m$

Explanation:

To find Depth D of lake we must need to find the time taken to hit the water.So we use equation of simple motion as:

Δx=vit+(1/2)at²

$x_(f)-x_(i)=v_(i)t+(1/2)at^(2)\n -5.0m=(o)t+(1/2)(-9.8m/s^(2) )t^(2)\n -4.9t^(2)=-5.0\n t^(2)=5/4.9\nt=√(1.02) \nt=1.01s$

As we have find the time taken now we need to find the final velocity vf from below equation as

$v_(f)=v_(i)+at\nv_(f)=0+(-9.8m/s^(2) )(1.01s) \nv_(f)=-9.898m/s$

So the depth of lake is given by:

first we need to find total time as

t=3.0-1.01 =1.99 s

$|D_(depth) |=|vt|\n|D_(depth) |=|(-9.898m/s)(1.99s)|\n|D_(depth) |=19.697m$

If the intensity of a loud car horn is 0.005 W/m^2 when you are 2 meters away from the source. Calculate the sound intensity level. A. 1.6 WB. 0.06 W
C. 97 dB
D. 223 dB
E. 179 dB

Answers

Answer:

Explanation:

We have given the intensity of the loud car horn $I=0.005w/m^2$

We know that $I_O=10^(-12)w/m^2$

Now the sound intensity level is given by $\beta =10log(I)/(I_0)=10log(0.005)/(10^(-12))=96.98dB$ , which is nearly equal to 97

So the sound intensity level will be 97 dB

So option (c) will be the correct option

Calculate the slope of the 25-coil line and the 50-coil line to determine the average number of paper clips that a 1 V battery would pick up.

Answers

Answer:

For 25-turn electromagnet, Number of clips = 4.1

For 50-turn electromagnet number of clips = 9.6

Explanation:

To calculate the slope of the 25-coil line and the 50-coil line to determine the average number of paper clips that a 1 V battery would pick up.

Hence;

Using the equations gotten from the graph in the previous question and 1.0 V as the value for x, we get

For 25-turn electromagnet y = 3.663x * 0.5

(rounded to one decimal place) Number of clips = 4.1

For 50-turn electromagnet y = 7.133x 2.5

(rounded to one decimal place) Number of clips = 9.6

Help me with my physics, please

Answers

The right answer would be

-20t+ 80

What is displacement?

Answers

Displacement means when you move something from its original position. Let's say you want to sit on a chair. You move the chair from where it was originally placed. That's displacement.

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