CHEMISTRY HIGH SCHOOL

Which of the following compounds would be most effective in lowering the melting point of ice on roads?

a) CaCl2

b) NaCl

C) K3PO4

d) K2SO4

Answers

Answer 1
Answer: I'm not 100% sure on this, but I would go with C) NaCl. 
NaCl is a salt, and that is used to melt the ice on the roads. Hope this helps!

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Describe the crystallization process as applied in salt preparation

Answers

Explanation:

The principle used in the preparation of these salts is to dissolve

the cystine in an alcoholic alkali solution to which just sufficient

water to effect solution has been added, and, after filtering from

excess cystine, to precipitate the salt by addition of a suitable

indifferent solvent. While various solvents, such as acetone,

ether, or large amounts of alcohol caused precipitations, these were

either oily or amorphous. Only acetonitrile was found to possess

the power of initiating regular crystallization in the salt solutions.

While the solutions of the different salts require different amounts

of the solvent for complete precipitation, a partial substitution of

absolute ether for acetonitrile was found expedient in the case

of the most soluble of the salts, the K salt.

Answer:

It is simply a process of forming crystal.

Explanation:            When salt is heated and dissolve in the liquid mainly water then its called saturated solution. When we further add salt and increase heat in order to dissolve it then it forcibly dissolve in liquid it's called supersaturated solution. After we slowly cool down the temperature then the salt we have put in supersaturated solution arises in the form of crystal. Hence its called crystalization.

Which substance cannot be broken down by a chemical change?1) ammonia
2) ethanol
3) propanol
4) zirconium

Answers

Zirconium cannot be broken down by a chemical change, because it is an element. The others are all molecules. Hope ive helped :)

Answer:

Zirconium

Explanation:

This is because if you look it up in the periodic table you cannot break it apart by a chemical.

Gold’s natural state has a definite shape and a definite volume. What is gold’s natural state(s)?

Answers

Gold’s natural state has a definite shape and a definite volume. Gold's natural state is solid.
In nature, gold most often occurs in metallic form, alloyed with silver.

Answer:

SOLID

Explanation:

How many gram of nitrogen are needed to produce 325 gram of ammonia? n2(g) + 3h2(g) → 2nh3(g)

Answers

Answer : The mass of nitrogen needed are, 267.68 grams

Explanation :

Mass of NH_3 = 325 g

Molar mass of NH_3 = 17 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate the moles of NH_3.

\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}=(325g)/(17g/mole)=19.12moles

Now we have to calculate the moles of N_2.

The balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the balanced reaction we conclude that

As, 2 moles of NH_3 obtained from 1 mole of N_2

So, 19.12 moles of NH_3 obtained from (19.12)/(2)=9.56 moles of N_2

Now we have to calculate the mass of N_2.

\text{Mass of }N_2=\text{Moles of }N_2* \text{Molar mass of }N_2

\text{Mass of }N_2=(9.56mole)* (28g/mole)=267.68g

Therefore, the mass of nitrogen needed are, 267.68 grams
Molar mass :

N₂ = 28.0 g/mol   
NH₃ = 17.0 g/mol

N₂(g) + 3 H₂(g) = 2 NH₃(g)

28.0 g  (N₂)---------> 2 x 17 g NH₃
 ? g    ------------> 325 g NH₃

Mass N₂ = ( 325 x 28.0 ) / ( 2 x 17 )

Mass N₂ = 9100 / 34

= 267.64 g of N₂

hope this helps!

Compared to the atoms of nonmetals in period 3, the atoms of metals in period 3 have1. fewer valence electrons
2. more valence electrons
3. fewer electron shells
4. more electron shells

Answers

Compared to the atoms of nonmetals in period 3, the atoms of metals in period 3 have fewer valence electrons.

Option 1 is correct.

In the periodic table, the period runs from left to right on the table while the group runs from top to bottom on the table.

In period 3, the period starts with Sodium Na(alkali metal), Magnesium Mg(alkaline earth metals), Aluminium Al(other non metals), Silicon Si (non metals), Phosphorus (non-metals), Sulfur (non-metals). etc.

From left to right across period 3, the valence electrons in the outermost increase.

Hence, the metals will have fewer valence electrons since the metals start period 3.

Therefore, we can conclude that compared to the atoms of nonmetals in period 3, the atoms of metals in period 3 have fewer valence electrons.

Learn more about the periodic table here:

brainly.com/question/11155928?referrer=searchResults

Answer : Option A) Fewer valence electrons

Explanation : Compared to the atoms of non metals in period 3, atoms of metals in period 3 have fewer valence electrons.

There are 8 elemental members in third period which are eight: sodium, magnesium, aluminium, silicon, phosphorus, sulfur, chlorine, and argon.

The first 2 elements belong to s-block whereas the other elements belong to p-block. The atomic radius is found to decrease across the period.

The electrons in the valence shell increases as we go from left to right in the period, which means when we move from metal to non-metal side the number of valence electrons also increases. This clearly shows that metals have fewer valence electrons as compared to the non-metals.

Rank the following structures in order of decreasing electrophilic strength.

Answers

Electrophiles are positively charged or neutral species having empty orbitals that are attracted to an electron rich center. Examples of these are the Bronsted acid. Bronsted acid accepts an electron pair for hydrogen.
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