In the following reaction 2C6H6 + 15O2 12CO2 + 6H2O how many grams of oxygen will react with 10.47 grams of benzene (C6H6)?

Answers

Answer 1
Answer: 2 C_(6)H_(6) + 15O_(2) ----->\ \textgreater \ 12CO_(2) + 6H_(2)O

mol of benzene = (mass)/(Mr)
                                = <span>(10.47g)/((6 * 12) (6 * 1) g/mol)
                                = 0.134 mol

mol of oxygen: 
                 ratio of C_(6) H_(6) : O_(2)
                 =  2 : 15
                 =  1 : 7.5

: . mol of O_(2) = 0.134mol * 7.5
                                         = 1.01 mol

Mass of Oxygen = mol * Mr
                           = 1.01 mol * (16*2) g/mol
                           = 32.22g 

Note: Mr is molar mass

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Explain the reason for sodiums location in the periodic table , explaining both location in its group and in its period

Answers

Explanation:

It is known that the atomic number of sodium is 11 and its electronic distribution is 2, 8, 1.

As the number of rows (called periods) in the periodic table represent the number of shells present in an element.

Since, sodium element have only two shells. Therefore, sodium lies in row 2 of the periodic table.

Also, the elements which contain same number of valence electrons lie in the same group.

Therefore, sodium belongs to group 1 and elements of the group 1 are also known as alkali metals.

Thus, we can conclude that in the periodic table sodium lies in period 2 and group 1.

Sodium is part of the alkali metal group because it has properties that have periodic patterns relating to the rest of the group. It is in it's period because of it's energy level and the amount of electrons on that level. It is also apart of it's group because of how many valence electrons it has.

Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium nitrite (KNO2). The acid dissociation constant of nitrous acid is 4.5 × 10^-4. Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium nitrite (KNO2). The acid dissociation constant of nitrous acid is
4.5 × 10^-4.

Answers

HNO2 =====> H+ + NO2-
Initial concentration = 0.311
C = -x,x,x 
E = 0.311-x,x,x

KNO2 ====>K+ + NO2- 
Initial concentration = 0.189 
C= -0.189,0.189,0.189 
E = 0,0.189,0.189
 

What is the ground state electron configuration for sodium (Na)?

Answers

Answer: Na has a ground-state electronic configuration of 1s2 2s2 2p6 3s1. Removing the 3s electron leaves us with the noble gas configuration 1s2  so a sodium ion is Na+.

Explanation: I HOPE THAT HELPED!

Final answer:

The ground state electron configuration for sodium (Na) is 1s²2s²2p63s¹. The electron in the outermost shell (3s orbital) is the valence electron, with the rest being core electrons. It can be abbreviated as [Ne]3s¹.

Explanation:

The ground state electron configuration for sodium (Na), an alkali metal with atomic number 11, is 1s²2s²2p63s¹. This configuration includes one electron in the outermost shell, or 3s orbital, and the rest in the core electron shells. To abbreviate this, we look at the noble gas that matches the core configuration, in this case neon (Ne), and the configuration becomes [Ne]3s¹. The outermost electron, in the 3s orbital, is known as a valence electron, while the others are core electrons.

Learn more about Electron configuration here:

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What does the molecular formula of a compound describe?

Answers

Answer: Molecular Formulas. Molecular formulas are a compact chemical notation that describe the type and number of atoms in a single molecule of a compound. Identify the molecular formula of a compound given either its name or structural formula.

Explanation:

Unknown compounds can usually be identified based solely on their _____. A. chemical properties
B. reactivity
C. volatility
D. physical properties

Answers

B reactivity  because compounds are made of atoms and molecules and you need to know what they react to to know what they are made up of. 
hysical proprerties i think

A solution contains 72.0 g of HCl and 468 g of (C6H6). What is the mole fraction of benzene

Answers

In order to calculate for the mole fraction of benzene, you will need to convert all mass into moles. This can be done through dividing the mass with the elements’ molar mass. Since the molar mass of HCl is 36, the number of moles of HCl in the solution is 2 moles. Meanwhile Benzene has a molar mass of 78 thus having 6 moles in the solution. Dividing 6 moles with the total number of moles which is 8 moles, you would get 0.75 mole fraction of Benzene.