A woman lifts her 100-newton child up one meter and carries her for a distance of 50 meters to the 3.2child’s bedroom. How much work does the woman do?

Answers

Answer 1
Answer: (100 N) x (1 m) == 100 J

 hope that helps


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What does the red shift suggest about the universe?

Answers

So far, the only way we know to explain the red shift is
as an effect of the light sources moving away from us. 
That's the basis of the whole idea of the expanding universe,
and ultimately, the big bang theory. 

If we ever find another mechanism that can produce the same
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If an object is not accelerating what can you determine about the sum of all the forces on the object

Answers

If object is not accelerating, the sum of all forces on the object will be equal to ZERO...

Please help ASAP!! According to the condensation theory, the most important factor for the formation of our planets was _____.
A.) the gravitational pull of the Sun
B.) the interstellar dust attracting heat away from the protosun
C.) the process of nuclear fusion
D.) the nebular cloud condensing

Answers

A.. The gravitational pull of the sun

Please help me find the answers!

Answers

Answer:

1. T₁ is approximately 100.33 N

T₂ is approximately -51.674 N

2. 230°F is 383.15 K

3. Part A

The total torque on the bolt is -4.2 N·m

Part B

Negative anticlockwise

Explanation:

1. The given horizontal force = 86 N

The direction of the given 86 N force = To the left (negative) and along the x-axis

(The magnitude and direction of the 86 N force = -86·i)

The state of the system of forces = In equilibrium

The angle of elevation of the direction of the force T₁ = 31° above the x-axis

The direction of the force T₂ = Downwards, along the y-axis (Perpendicular to the x-axis)

Given that the system is in equilibrium, we have;

At equilibrium, the sum of the horizontal forces = 0

Therefore;

T₁ × cos(31°) - 86 = 0

T₁ = 86/(cos(31°)) ≈ 100.33

T₁ ≈ 100.33 N

Similarly, at equilibrium, the sum of the vertical forces = 0

∴ T₁×sin(31°) + T₂ = 0

Which gives;

100.33 × sin(31°) + T₂ = 0

T₂ = -100.33 × sin(31°) ≈ -51.674

T₂ ≈-51.674 N

2. 230° F to Kelvin

To convert degrees Fahrenheit (°F) to K, we use;

Degrees \ in  \ Kelvin, K = (x^(\circ) F + 459.67) * (5)/(9)

Pluggining in the given temperature value gives;

Degrees \ in  \ Kelvin, K = (230^(\circ) F + 459.67) * (5)/(9) = 383.15

230°F = 383.15 K

3. Part A

Torque = Force × perpendicular distance from the line of action of the force

Therefore, the clockwise torque = 9 N × 0.4 m = 3.6 N·m (clocwise)

The anticlockeisre torque = 13 N × 0.6 m = 7.8 N·m (anticlockwise)

The total torque o the bolt = 3.6 N·m - 7.8 N·m = -4.2 N·m (clockwise) = 4.2 N·m anticlockwise

Part B

The torque is negative anticlockwise.

What term describes the rate at which charge passes a point in a circuit

Answers

Current - APEX :) lol it said my answer wasn't long enough so yeah Hi

That's electric "current", usually described in 'Amperes'.

1 Ampere = 1 Coulomb per second ... "the rate at which
charge passes a point in the circuit".

Suppose nuclear physicists discovered a fission process that always produced two smaller nuclei and only one neutron. Would this eliminate the danger of meltdown in a nuclear power plant? Why or Why not- ? Explain.(Thanks to anyone who helps :)

Answers

Running that process in a power plant would not only eliminate the
danger of a core meltdown, it would also pretty much eliminate the
possibility of getting any nuclear power out of the plant.

The understanding behind your question is correct . . . Neutrons coming
out of one fission go on to get absorbed in other nuclei, and cause the
other ones to fiss.  BUT . . . NOT every free neutron whizzing around in
the core material gets absorbed.  Some of them enter another nucleus
and immediately get spit out.  And some of them never get near another
nucleus at all.  Of all the neutrons produced in one fission, only some
percentage go on to stimulate another one.  So if each fission produced
only one neutron, then the whole process would completely run out of gas
in some amount if time, as the number of free neutrons dwindled and shrank.