MATHEMATICS HIGH SCHOOL

P is a point on the terminal side of θ in standard position. Find the exact value of the six trigonometric functions for θ.18. P(-3, 2)
19. P(4, -2)
20. P(0, -6)
21. P(-3, -4)

Answers

Answer 1
Answer:

Answer:

  see below

Step-by-step explanation:

When you're doing a bunch of these, it is helpful to make a table with reminders as to how they're calculated. That table is shown below.

__

In the attached, we have used ...

  r² = x² +y²

  √20 = 2√5

  √36 = 6

  √25 = 5

and 1/(2√5) = √5/10. (The division is outside the radical.)

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What is 5-1???????????????????????????????

Answers

Answer : 4


I hope that's help !
Oh i know this, its 4!!

A student received a 75% on an exam. If there were 20 questions on the exam, which ratio would show the number of questions answered correctly?A. 15:20
B. 20:15
C. 5:20
D. 20:5

Answers

Assuming the question is asking for the ratio of questions answered correctly to the number of questions, A is the correct answer. 75% of 20 is 15 ((20/4) x 3), so 15:20 is correct, though this can be cancelled to 3:4. If the question asks for the ratio of correct to incorrect answers, the ratio would be 15:5, or 3:1.

Compare the graphs of the inverse variations y=-0.2/x and y=-0.3/x. Provide at least 3 comparisons

Answers

- both are not defined for x = 0

- both have the same symmetry axis: y = x

- both are hyperbolas

- both have the same asymptotes: the y-axis, i.e. y = 0

- both have the same limits when x approaches 0 by the right and by the left: positive and negative infinity.

-  both have the same limits when x approaches + and - infinity: zero.

- they never touch one to each other
 

(OFFERING ALL THE POINTS I HAVE) Word Problem. Please help!! Part 1 of problem: The main tank has a radius of 70 feet. What is the volume of the quarter-sphere sized tank? Round your answer to the nearest whole number and use 3.14 for Pi. (Use sphere volume formula) Part 2: The theme park company is building a scale model of the killer whale stadium main show tank for an investor's presentation. Each dimension will be made 6 times smaller to accommodate the mock-up in the presentation room. How many times smaller than the actual volume is the volume of the mock-up? Part 3: Using the information from part 2, answer the following question by filling in the blank: The volume of the actual tank is __% of the mock-up of the tank.

Answers

Answer:

Part 1: 359,007 ft³

Part 2: 216 times smaller

Part 3: 21600%

Step-by-step explanation:

Part 1:

The parameters for the tank are;

The radius of the tank = 70 feet

The volume of a sphere = 4/3·π·r³

Therefore, the volume of a quarter sphere = 1/4×The volume of a sphere

The volume of a quarter sphere = 1/4×4/3·π·r³ = π·r³/3

Plugging in the value for the radius gives

Volume = π×70³/3 = 114,333.33×3.14 = 359,006.7≈ 359,007 ft³.

Part 2:

The dimension of the scale model  = 1/6 × Actual dimension

Therefore, we have the radius of the sphere of the scale model = 1/6 × 70

Which gives;

The radius of the sphere of the scale model = 35/3 = 11.67 feet

The volume of the scale model = π·r³/3 = (3.14×11.67³)/3 = 1662.07 ≈ 1662 ft³

The number of times smaller the scale model is than the actual volume = (Actual volume)/(Scale model) = (359,007 ft³)/(1662 ft³) = 216 times

The number of times smaller the scale model is than the actual volume =  216 times = (1/Scale of model)³ = (1/(1/6))³ = 6³.

Part 3:

The percentage of the mock-up, x, to the volume of the actual tank is given as follows

x/100 ×  1662  = 359,007

∴ x = 216 × 100 = 21600%

The percentage of the mock-up, to the volume of the actual tank is 21600%.

Answer:

Part 1: 359,007 ft³

Part 2: 216 times smaller

Part 3: 21600%

Step-by-step explanation:

Part 1:

The parameters for the tank are;

The radius of the tank = 70 feet

The volume of a sphere = 4/3·π·r³

Therefore, the volume of a quarter sphere = 1/4×The volume of a sphere

The volume of a quarter sphere = 1/4×4/3·π·r³ = π·r³/3

Plugging in the value for the radius gives

Volume = π×70³/3 = 114,333.33×3.14 = 359,006.7≈ 359,007 ft³.

Part 2:

The dimension of the scale model  = 1/6 × Actual dimension

Therefore, we have the radius of the sphere of the scale model = 1/6 × 70

Which gives;

The radius of the sphere of the scale model = 35/3 = 11.67 feet

The volume of the scale model = π·r³/3 = (3.14×11.67³)/3 = 1662.07 ≈ 1662 ft³

The number of times smaller the scale model is than the actual volume = (Actual volume)/(Scale model) = (359,007 ft³)/(1662 ft³) = 216 times

The number of times smaller the scale model is than the actual volume =  216 times = (1/Scale of model)³ = (1/(1/6))³ = 6³.

Part 3:

The percentage of the mock-up, x, to the volume of the actual tank is given as follows

x/100 ×  1662  = 359,007

∴ x = 216 × 100 = 21600%

The percentage of the mock-up, to the volume of the actual tank is 21600%.

the Mclntosh family went apple picking. they picked a total of 115 apples. The family ate a total of 8 apples each day. after how many days did they have 19 apples left?

Answers

In the given question, all the information's that are required is already provided. based on these information's the correct answer can be easily deduced. The McIntosh family picked a total of 115 apples. the family ate a total of 8 apples per day. It is required to find the day after which there will be 19 apples left from the total of 115. Then firstly let us subtract 19 apples from the total of 115.
Number of apples left after deducting 19 apples = 115 - 19
                                                                             = 96
Now
8 apples are eaten by the McIntosh family in = 1 day
96 apples will be eaten by the McIntosh family in = 96/8
                                                                               = 12 days
So after 12 days, 19 apples will be left with the McIntosh family.

Answer:

19 apples will be left with the McIntosh Family

Step-by-step explanation:

Use long division to find the quotient. 

(x²+6x-27) ÷ (x-3)

Answers

( x^2+6x-27 )/(x-3) = ( x^2+6x +3x-3x-27 )/(x-3) = ( x^2+9x-3x-27 )/(x-3) = \n \n =( x(x +9 )-3(x+9) )/(x-3) = ( (x +9 ) (x-3) )/(x-3) = x+9 \n \n \n x-3\neq 0 \nx\neq 3\nD=R\setminus \left \{ 3 \right \}
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