Answer: 0.8
Explanation:
The efficiency is defined as the ratio of total imput energy that is actually utilized to the end of the device.
So if we have a total transfer of 1500j of energy, and 1200j are used to heat the thing inside the kettle, 300j are not used to the actual function of the kettle.
So the efficiency is n = 1200j/1500j = 0.8
This means that a 80% of the energy imput is actually used to heat the kettle.
To calculate the efficiency of the kettle, divide the useful output energy (1200 J) by the total input energy (1500 J) and multiply by 100%. This results in an efficiency of 80%, meaning 80% of the energy was converted into useful thermal energy.
In order to find the efficiency of the kettle, we need to compute the ratio of the useful output energy to the total input energy and then multiply by 100% to convert the decimal to a percentage. In this case, the useful output energy is the 1200 J transferred to the thermal energy store. The total input energy is the total energy transferred by the kettle which is 1500 J. So, the efficiency of the kettle is (1200 J / 1500 J) * 100% = 80%.
The remaining 20% energy is wasted and was transferred to the vibrational (sound) energy store, which is a non-useful energy output. An efficient appliance is one which converts a higher proportion of the input energy into useful output energy, with less of it wasted. In this case, 80% of the energy from the kettle was converted into useful thermal energy, hence the kettle is quite efficient.
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EXPLANATION :
As per the question, the electron has jumped from ground state to higher energy level.
From Bohr's postulate, we know that electron can only move to higher excited state when the energy equivalent to excitation energy has been given to it. Otherwise, the electron can not move from ground state to the excited state.
Hence, it is obvious that the electron might have excited to higher energy level by providing sufficient energy from outside.
The external source might be light of suitable frequency or any electric or thermal source.
sitting 25.0 m from the orchestra?
According to her friends, with what speed was ball 2 thrown?
In the context of relative velocity, Ball 1 was thrown with a speed of 21 m/s and Ball 2 was thrown with a speed of 11 m/s according to her friends.
The problem presented involves the concept of relative velocity. The speed of the balls relative to Anita is 16 m/s and she is running at a speed of 5 m/s.
If ball 1 is thrown in the same direction as Anita is running, then the friends on ground would see the speed of the ball as the sum of its velocity relative to Anita and the speed of Anita. So, the speed of ball 1 would be 16 m/s + 5 m/s = 21 m/s. Ball 1 was thrown with a speed of 21 m/s according to her friends.
For Ball 2, if it's thrown in the opposite direction to which Anita is running, then according to her friends the speed of Ball 2 would be 16 m/s (speed of the ball relative to Anita) - 5 m/s (Anita's speed) = 11 m/s. Therefore, Ball 2 was thrown with a speed of 11 m/s according to her friends.
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