MATHEMATICS COLLEGE

What is the y-coordinate of the point that divides the directedline segment from J to K into a ratio of 2:3?

K(8,11)

J(-3,1)


*7

*-6

*5

*-5

Answers

Answer 1
Answer:

Answer:

(D)5

Step-by-step explanation:

Given the point J(-3,1) and K(8,11).

The line segment that divides the segment from J to K in any given ratio can be determined using the formula.

P(x,y)=\left((mx_2+nx_1)/(m+n) ,(my_2+ny_1)/(m+n)\right)

In the given case:

(x_1,y_1)=(-3,1), (x_2,y_2)=(8,11), m:n=2:3

Since we are to determine the y-coordinate of the point that divides JK into a ratio of 2:3, we have:

(my_2+ny_1)/(m+n)=(2*11+3*1)/(3+2)\n\n=(22+3)/(5)\n\n=(25)/(5)\n\n=5

The y-coordinate of the point that divides the directed  line segment from J to K into a ratio of 2:3 is 5.

The correct option is D.
Answer 2
Answer:

Answer:

The answer is actually C(5) not D

Step-by-step explanation:

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A binomial experiment consists of 16 trials. The probability of success on trial 9 is 0.48. What is the probability of success on trial 13?

Answers

Answer:

p = 0.48

Step-by-step explanation:

A binomial experiment is and experiment with n trials, every trial is identical and independent and every trial has the same probability p of success and 1-p of fail.

Then, we have a binomial experiment of 16 trials. it means that every trial has the same conditions. So, if the probability of success on trial 9 is 0.48, the probability of success on trial 13 is also 0.48.

What is 6 8th plus 7 8th​

Answers

Answer:

13/8

Step-by-step explanation

Since the denominator is the same, you keep it. Then you just add 6 and 7 which is 13.

An entrepreneur is considering the purchase of a coin-operated laundry. The current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75. A sample of 30 days reveals a daily average revenue of $625. If you were to test the null hypothesis that the daily average revenue was $675, which test would you use?

a. Z-test of a population mean

b. Z-test of a population proportion

c. t-test of population mean

d. t-test of a population proportion

Answers

The Z-test of a population mean is used here because it is given that the population standard deviation is $75. The correct option is a).

Given :

  • The current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75.
  • A sample of 30 days reveals a daily average revenue of $625.

Let \mu is the daily average revenue. So:

Null Hypothesis is, \rm H_0:\mu=$675

The Alternate Hypothesis is, \rm H_a : \mu\neq $675

Here, the Z-test of a population mean is used because it is given that the population standard deviation is $75.

\rm Test \;Statistics = \frac{\bar{X}-\mu}{(\sigma)/(√(n) )}

where \rm \bar {X} is the sampleaverage revenue, \sigma is the standard deviation and n is the sample size.

Therefore, the correct option is a).

For more information, refer to the link given below:

brainly.com/question/13245779

Answer:

We would use Z-test of a population mean.

Step-by-step explanation:

We are given that an entrepreneur is considering the purchase of a coin-operated laundry. The current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75. A sample of 30 days reveals a daily average revenue of $625.

And we have to test the hypothesis that the daily average revenue was $675.

Firstly, as we know that testing is always done on the population parameter.

So, let \mu = daily average revenue over the pat 5 years

So, Null Hypothesis, H_0 : \mu = $675

Alternate Hypothesis,H_a : \mu \neq $675

Here, null hypothesis states that the owner's claim of average daily revenue was $675 over the past 5 years is correct.

And alternate hypothesis states that the owner's claim of average daily revenue was $675 over the past 5 years is not correct.

The test statistics that will be used here is Z-test of a population mean because here we have knowledge of population standard deviation of $75.

   Test statistics = (\bar X-\mu)/((\sigma)/(√(n) ) )  ~ N(0,1)

where, \bar X = sample average revenue = $625

            \sigma = population standard deviation = $75

             n = sample of days = 30

Therefore, to test the null hypothesis that the daily average revenue was $675, we should use Z-test of a population mean.

Find the area of this circle. Use 3 for pi

Answers

Answer:

area = 108 cm^2

Step-by-step explanation:

area = Pi(r^2)

using Pi = 3

r = D/2 = 12/2 = 6

area = 3(6^2) = 3(36) = 108 cm^2

Write a simplified expression for the area of the rectangle below

Answers

Answer:

= 12x + 40

Step-by-step explanation:

area = l * b \n = 20 * ((3)/(5) x + 2) \n = (60x)/(5) + 40 \n = 12x + 40

hope this helps

brainliest appreciated

good luck! have a nice day!

A survey of the mean number of cents off that coupons give was conducted by randomly surveying one coupon per page from the coupon sections of a recent San Jose Mercury News. The following data were collected: 20¢; 75¢; 50¢; 65¢; 30¢; 55¢; 40¢; 40¢; 30¢; 55¢; $1.50; 40¢; 65¢; 40¢. Assume the underlying distribution is approximately normal. (a) Determine the sample mean in cents (Round to 3 decimal places)

Answers

Answer:

53¢

Step-by-step explanation:

First, I'll put these in order.

20¢;30¢; 30¢;75¢;40¢;40¢;40¢;40¢;50¢;55¢55¢65¢;65¢; $1.50;  

Then, I'll combine like terms.

30+30=60

40+40+40+40(or 40 x 4)=160

55+55=110

65+65=130

60+160+110+130+20+75+50+$1.50=$7.55/14=53¢

PLZ correct me if i'm wrong :-D
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