which of the following describes a neutral atom of oxygen?. a.6 protons. 6 neutrons, 6 electrons. b. 6 protons, 6 neutrons, 8 electrons. c. 8 protons, 8 neutrons, 10 electrons. d. 8 protons, 8 neutrons, 8 electrons

Answers

Answer 1

Answer: the one that describe a neutral atom of oxygen would be : D. 8 protons, 8 neutrons, and 8 electrons

In periodic table, oxygen has a mass number of 16 and 8 electrons

In order to get neutrons, we just need to subtract 16 with 8 , and we get 8 neutrons

hope this helps

Answer 2

Answer:

D. 8 protons, 8 neutrons, 8 electrons

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Hydrogen bonding occurs in molecules when a _____________. (1 point)hydrogen atom forms a covalent bond with one other atom. hydrogen atom forms covalent bonds with more than one atom. hydrogen atom of a polarized molecule bonds with an electronegative atom hydrogen atoms form an ionic bond with one other atom
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Based on the Periodic Table, explain why Na and Khave similar chemical properties

Your tongue and nose work separately.
True
False

Answers

false, our tongue and nose work together

yes your tongue and nose work together

Mg(s) + Cu(NO3)2(aq) → Mg(NO3)2(aq) + Cu(s)
what is the oxidizing agent and the reducing agent

Answers

1. The reaction is:

Mg(s) + Cu(NO3)2(aq) → Mg(NO3)2(aq) + Cu(s)

The oxidizing agent is the one that is being reduced which is copper where the charge changed from +2 to neutral while the reducing agent is the on being oxidized which is magnesium where the charge change from neutral to +2.

Final answer:

In the chemical reaction given, the oxidizing agent is Copper Nitrate (Cu(NO3)2) and the reducing agent is Magnesium (Mg).

Explanation:

In this chemical reaction, Magnesium (Mg) undergoes oxidation and Copper Nitrate (Cu(NO3)2) undergoes reduction. The oxidizing agent is the substance that causes oxidation by accepting electrons, hence the oxidizing agent here is Copper Nitrate (Cu(NO3)2). Likewise, the reducing agent is a substance that reduces another by providing electrons. In this case, Magnesium (Mg) is the reducing agent as it donates electrons to Copper Nitrate (Cu(NO3)2).

Learn more about Oxidizing and Reducing Agents here:

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If you were asked to describe metals and magnetism you could say. A. non–paired electrons spin in opposite directions in all metals, creating a magnetic field. B. metals are magnets because they have more electrons than non–magnetic materials. C. metals can become magnetic if they have many spinning electrons that create magnetic fields. D. the electrons in some metals pair up to create a magnetic field.

Answers

Answer : Option D) the electrons in some metals pair up to create a magnetic field.

Explanation : Most of the metalsare magnetic in nature including some exceptions. When the unpaired electrons get aligned with the magnetic field they posses magnetism. Also there are some paired electrons in metals which align themselves according to the magnetic field and create magnetism in them.

The correct answer is C; Metals can become magnetic if they have many spinning electrons that create magnetic fields.

Further Explanation;

As long as there are many spinning electrons anything metal will become magnetic. Ferromagnetic is when there are only some certain types of metals that are attracted to magnetic. If you were to make an electromagnet, you would only need to take an insulated wire and wrap it around the metal that has ferromagnetic properties.

Learn more about magnetism at brainly.com/question/1228801

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Matt's cube, after 5 trials, had an average density of 7.40 g/cm3 . His group's cube was made ofA) aluminum.
B) gold.
C) nickel.
D) zinc.

Answers

The right answer for the question that is being asked and shown above is that: "B) gold." Matt's cube, after 5 trials, had an average density of 7.40 g/cm3 . His group's cube was made of B) gold.

its d zinc if your using usa test this dummy got me wrong trust me sis the answer is d

Which particles are gained and lost during a redox reaction?(1) electrons (3) neutrons
(2) protons (4) positrons

Answers

Electrons are Loss (Oxidation) and Gain (Reduction) in a Reduction-Oxidation (Redox) reaction.

How would you solve this problem??

Answers

Calculate the pOH where [OH⁻]=4.7×10⁻³M:
pOH=-log[OH⁻]
pOH=-log(4.7×10⁻³)
pOH=2.33

Calculate [OH⁻] if the pOH is 1.34:
pOH=-log[OH⁻]
10^(-pOH)=[OH⁻]
[OH⁻]=10^(-pOH)
[OH⁻]=10^(-1.34)
[OH-]=0.0457M or [OH⁻]=4.57×10⁻²M

Calculate pH if the [OH⁻] is 1.74×10⁻²M:
[H⁺]=K(w)/[OH⁻] or pOH=-log[OH⁻]
[H⁺]=(1×10⁻¹⁴)/(1.57×10⁻²) pOH=-log(1.74×10⁻²)
[H⁺]=6.369×10⁻¹³M pOH=1.759
pH=-log[H⁺] pH=14-pOH
pH=-log(6.369×10⁻¹³) pH=14-1.759
pH=12.2 pH=12.2

I hope this helps. Let me know if anything is unclear.

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