The two cylinders are similar. If the ratio of their surface areas is 9/1.44, find the volume of each cylinder. Round your answer to the nearest hundredth. A.small cylinder: 152.00 m3
large cylinder: 950.02 m3
B.
small cylinder: 972.14 m3
large cylinder: 12,924.24 m3
C.
small cylinder: 851.22 m3
large cylinder: 13,300.25 m3
D.
small cylinder: 682.95 m3
large cylinder: 13,539.68 m3

Answers

Answer 1

Answer: r1² π : r2² π = 9 : 1.44
r1 : r 2 = 3 : 1.2
r2 = 1.2 · r1 / 3
r 2 = 0.4 · r1
If the two cylinders are similar than also: h 2 = 0.4 · h 2
V 1 = r1² · π · h1
V 2 = ( 0.4 r1)² π · 0.4 · h1 = 0.064 r1² · π · h1
V 2 ( small cylinder )= 0.064 · V 1 ( large cylinder )
851.22 m³= 13.300.25 m³ · 0.064
Answer: C )

Answer 2

Answer: The two cylinders are similar. If the ratio of their surface areas is 9/1.44, find the volume of each cylinder. Round your answer to the nearest hundredth.

Answer: out of all the available options the one that shows the correct volumes for each cylinder is answer choice C) small cylinder: 851.22 m³ & large cylinder: 13,300.25 m³.

I hope it helps, Regards.

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Answers

The height of the football after 4 seconds is 80 feet

The height in feet of the punted football is a function of time the ball is in the air.

The function is represented as follows:

h(t) = -7t² + 48t

The height of the football after 4 seconds can be calculated as follows:

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Therefore,

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h(4) = 80 feet

learn more about function: brainly.com/question/23136370?referrer=searchResults

Answer:

The height of the football after 4 seconds is 80 feet.

Step-by-step explanation:

You know that the height (in feet) of punted football is a function of the time the ball is in the air and it is defined by:

h(t) = -7*t²+48*t

To calculate the height of the ball after 4 seconds, you must replace the time t by the time of 4 seconds:

h(4) = -7*4²+48*4

Solving, you get:

h(4) = -7*16+48*4

h(4) = -112+192

h(4)= 80

The height of the football after 4 seconds is 80 feet.

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