The vertical _____ of a function secant are determined by the points that are not in the domain.

Answers

Answer 1

Answer: The vertical asymptotes of a function secant are determined by the points that are not in domain.
Thank you.

Answer 2

Answer:

Answer:

The vertical asymptote of a function secant are determined by the points that are not in the domain.

Step-by-step explanation:

The domain of a function is the set of x values for which the function is defined.

Secant function is not defined at $x=(\pi)/(2)+n\pi$

It means we cannot include these points in the domain.

At these points, we must have a vertical line which do not touch the graph. These lines are called "Vertical asymptotes"

Vertical asymptotes are not included in the domain of the function.

Hence, the correct word should be "Asymptote"

The vertical asymptote of a function secant are determined by the points that are not in the domain.

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Seven hundred thirty-one and six thousand two hundred sixty-four ten-thousandths in numbers
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when asked to factor the trinomial 8x^2 -8x-16, a student gives the answer (x-2)(x+1). what is wrong with this answer?

Solve 3x+1
(not on a graph do it using algebra)
no jokes you will be deleted

Answers

Final answer:

To solve the equation 3x + 1 algebraically, subtract 1 from both sides and then divide both sides by 3. The solution is x = -1/3.

Explanation:

To solve the equation 3x + 1 algebraically, you need to isolate the variable x. Let's go step-by-step:

Subtract 1 from both sides of the equation: 3x + 1 - 1 = 0 - 1. This simplifies to 3x = -1.
Divide both sides of the equation by 3 to solve for x: $\frac{3x}{3} = \frac{-1}{3}$. This simplifies to x = -\frac{1}{3}.

So, the solution to the equation 3x + 1 = 0 is x = -\frac{1}{3}. This means that when you substitute x = -\frac{1}{3} into the equation, both sides will be equal.

Learn more about Algebraic Equation Solving here:

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If you sleep 7 hours every night how many hours are you awake in a year?

Answers

24h - 7h = 17h. 17 * 365= 6 205 h a year. In a leap year, it is 6 222 h a year.

Discriminant of 9x^2+12x+4=0

Answers

$the\ discriminant\ of\ ax^2+bx+c=0:\ \ \ \ \Delta=b^2-4\cdot b\cdot c \n---------------------------\n9x^2+12x+4=0\ \ \ \Rightarrow\ \ \ \Delta=12^2-4\cdot9\cdot4=144-144=0\n\n\Delta=0\ \ \ \Rightarrow\ \ \ x_0=- (b)/(2a) =- (12)/(2\cdot9) =- (2\cdot2\cdot3)/(2\cdot3\cdot3)= - (2)/(3) \n\nAns.\ The\ discriminant\ is\ \Delta=0$

$9x^2+12x+4=0\n\n(3x)^2+2\cdot3x\cdot2+2^2=0\n\n(3x+2)^2=0\iff3x+2=0\n\n3x=-2\ \ \ /:3\n\nx=-(2)/(3)\n\n-------------------------------\n\n(a+b)^2=a^2+2ab+b^2$

The quilt shown has a border made of righta. Graph one triangle with vertices at D(-4, 0), E(0, 0), and F(0, -8). To locate
another triangle, follow these steps:
Reflect ADEF across the y-axis to form AD'E'F'.
Translate AD'E'F' 8 units up to form AD"E"F".
Is ADEF the same size and shape as AD"E"F"? Show your
.
.
x
work.

Answers

Answer:

To determine if triangles ADEF and AD"E"F" are the same size and shape, we need to compare their corresponding sides and angles. Let's go through the steps and analyze each transformation.

1. Reflecting ADEF across the y-axis:

When we reflect a point across the y-axis, the x-coordinate changes sign while the y-coordinate remains the same. Applying this reflection to each vertex of triangle ADEF, we get D'(-4, 0), E'(0, 0), and F'(0, -8).

2. Translating AD'E'F' 8 units up:

To translate a point, we add or subtract a constant value to its coordinates. Shifting each vertex of triangle AD'E'F' 8 units up gives us D"( -4, 8), E"(0, 8), and F"(0, 0).

Now let's compare the corresponding sides and angles of triangles ADEF and AD"E"F".

Corresponding Sides:

Side DE in triangle ADEF corresponds to side D'E' in triangle AD'E'F'. Since both sides lie on the x-axis, they have the same length.

Side EF in triangle ADEF corresponds to side E'F' in triangle AD'E'F'. Again, both sides lie on the y-axis, so they have the same length.

Side FD in triangle ADEF corresponds to side F'D' in triangle AD'E'F'. These sides are vertical lines with equal lengths.

Corresponding Angles:

Angle D in triangle ADEF corresponds to angle D' in triangle AD'E'F'. Both angles are right angles (90 degrees).

Angle E in triangle ADEF corresponds to angle E' in triangle AD'E'F'. These angles are also right angles (90 degrees).

Angle F in triangle ADEF corresponds to angle F' in triangle AD'E'F'. Once again, these angles are right angles (90 degrees).

From the above analysis, we can conclude that triangles ADEF and AD"E"F" are indeed the same size and shape. They have corresponding sides of equal length and corresponding angles of equal measure.

In conclusion, triangles ADEF and AD"E"F" are congruent.

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Is 7 divided by 8 equal to, greater then, or less then 3 divided by 4

Answers

7 divided my 8 is greater than 3 divided by 4

For all real numbers x and y, if x # y = x(x-y), then x # (x # y) =My question is, how does x # (x # y) = 8 and how does it also equal to x(squared) - x(cubed) + x(squared) y?

Is there a rule of the function that I have forgotten?

Thanks

Answers

$x\#y=x(x-y)\n\nx\#(x\#y)\n\nx\#y=x(x-y)=x^2-xy\n\nx\#(x\#y)=x\#(x^2-xy)=x[x-(x^2-xy)]=x(x-x^2+xy)\n\n=x^2-x^3+x^2y$

$x^2-x^3+x^2y=8\n\nx^2(1-x+y)=8\n\nx^2(1-x+y)=2^2\cdot4\iff x^2=2^2\ and\ 1-x+y=4\n\nx=2\ and\ y=4-1+x\n\nx=2\ and\ y=3+2\n\nx=2\ and\ y=5$

if x # y = x(x-y) => x # (x # y) = x # [x(x-y)] =x[ x - x(x-y)] = x( x - x^2 +x*y ) = x^2 - x^3 + ( x^2 ) * y;

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