Guys, please help me and tell me how you found the answer! If a gas has a pressure of 1.69 atm at a temperature of 300 K, what will the pressure change to if the container is cooled to 100 K?

Also

If a gas has a pressure of 715 mm Hg at the temperature of 500 K, what will the pressure change to if the container is heated to 900 K?

Answers

Answer 1

Answer:

The pressure has been reduced with the cooling of the container, and the change in pressure has been 1.06 atm. The pressure has been increased with the heating of the container and the change in pressure has been 572 mm Hg.

Assuming the gas has been following the ideal behavior. According to the ideal gas equation,

PV =nRT

If the same gas has been heated, the n and R will be constant, as well as with the constant volume of initial and final pressure, the relationship to the P and T can be given as:

$\rm (Initial\;pressure)/(Initial\;temperature)\;=\;(Final\;pressure)/(Final\;temperature)$

(a) For the gas with an initial pressure of 1.69 atm, the final pressure will be:

$\rm (1.69)/(300)\;=\;(Final\;Pressure)/(100)$

Final pressure = 0.563 atm.

The change in pressure = Initial pressure - Final pressure

The change in pressure = 1.63 - 0.563 atm

The change in pressure = 1.06 atm.

The pressure has been reduced with the cooling of the container, and the change in pressure has been 1.06 atm.

(b) For the gas at initial pressure 715mm Hg, the final pressure will be:

$\rm (715)/(500)\;=\;(Final\;Pressure)/(900)$

Final pressure = 1,287 mm Hg.

The change in pressure = Final pressure - Initial pressure

The change in pressure = 1,287 - 715 mm Hg

The change in pressure = 572 mm Hg

The pressure has been increased with the heating of the container and the change in pressure has been 572 mm Hg.

For more information about the change in pressure, refer to the link:

brainly.com/question/12152879

Answer 2

Answer:

Answer:

The First one is: 0.563atm

The second one is: 1.692atm

Hope this helps!

Explanation: Look at Photo Attached

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Ob
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Answers

Answer:

0.23 mol

Explanation:

3. For the following reaction, calculate how many grams of each product are formed when 4.05 gof water is used.
2 H2O → 2 H2 + O2

Answers

Answer:

$\large \boxed{\text{0.453 g of H$_(2)$; 3.60 g of O$_(2)$}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

MM: 2.016 32.00

2H₂O ⟶ 2H₂ + O₂

m/g: 4.05

1. Mass of hydrogen

(a) Moles of H₂O

$\text{Moles of H$_(2)$O} = \text{4.05 g H$_(2)$O}* \frac{\text{1 mol H$_(2)$O}}{\text{18.02 g H$_(2)$O }}= \text{0.2248 mol H$_(2)$O}$

(b) Moles of H₂

$\text{Moles of H$_(2)$} = \text{0.2248 mol H$_(2)$O } * \frac{\text{2 mol H$_(2)$}}{\text{2 mol H$_(2)$O }} = \text{0.2248 mol H$_(2)$}$

(c) Mass of H₂

$\text{Mass of H$_(2)$} =\text{0.2248 mol H$_(2)$} * \frac{\text{2.016 g H$_(2)$}}{\text{1 mol H$_(2)$}} = \textbf{0.453 g H$_(2)$}\n\n\text{The reaction produces $\large \boxed{\textbf{0.453 g}}$ of H$_(2)$}$

2. Mass of oxygen

(a) Moles of O₂

$\text{Moles of O$_(2)$} = \text{0.2248 mol H$_(2)$O } * \frac{\text{1 mol O$_(2)$}}{\text{2 mol H$_(2)$O}} = \text{0.1124 mol O$_(2)$}$

(b) Mass of O₂

$\text{Mass of O$_(2)$} =\text{0.1124 mol O$_(2)$} * \frac{\text{32.00 g O$_(2)$}}{\text{1 mol O$_(2)$}} = \textbf{3.60 g O$_(2)$}\n\n\text{The reaction produces $\large \boxed{\textbf{0.453 g of H$_(2)$ and 3.60 g of O$_(2)$}}$}$

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Answers

Answer:5

Explanation:The pnictogen group, or nitrogen group, is located in column 15 of the periodic table. This family consists of the elements nitrogen, phosphorus, arsenic, antimony, bismuth, and ununpentium (N, P, As, Sb, Bi, and Uup, respectively). Each member of this family contains five valence electrons.

Nitrogen is found to have either 3 or 5 valence electrons and lies at the top of Group 15 on the periodic table. It can have either 3 or 5 valence electrons because it can bond in the outer 2p and 2s orbitals.

See if that helps

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Answers

Answer:

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Explanation:

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Answers

Answer:

Option (C) from a vacuum to air

Explanation:

Speed of light in any media depends on the refractive index(n) of the medium in which light is travelling.The medium having least refractive index have the fastest speed of the light.As the refractive index of the vacuum is less(1.0000) than that of the air(1.0003), so the speed of light will slows down while moving from vacuum to air.The refractive index 'n' is the ratio between speed of light in vacuum(c) to the speed at which the light is travelling i.e v, (n = c / v).

As far as we know, the speed of light is faster in a vacuum than in any other medium. Therefor C is correct. The speed of light would slow down going from a vacuum to air.

Which term describes the role of fungi in this food chain?A.
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Answers

The term describes the role of fungi in this food chain is decomposer. Therefore, option B is correct.

What is the role of fungi ?

In forest, fungi are known as the important decomposers. Some kinds of fungi, such as mushrooms, look like plants. But fungi do not have chlorophyll, it is the pigment that green plants use to make their own food with the help of sunlight.

Fungi have the ability to convert nutrients so that they are available to plants. Some fungi are decomposers, which means they decompose plant and animal waste, cycling nutrients and increasing their availability in the soil.

Decomposers like fungi and bacteria are complete the food chain. They turn organic wastes that are decaying plants into the inorganic materials, such as nutrient-rich soil.

Thus, option B is correct.

To learn more about the fungi, follow the link;

brainly.com/question/1261179

#SPJ3

Fungai is a decomposer because it decomposes rotting, or dead materials, like a dead tree log.

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