Select all the true statements. Group of answer choices The +3 oxidation state is characteristic of the actinides. All actinides are radioactive. Cerium (Ce) rnakes 100th in abundance (by mass %). Valence-state electronegativity is when a metal with a positive oxidation state has a greater attraction for the bonded electrons (thus a higher electronegativity) than it does when it has a 0 oxidation state. The actinides are silvery and chemically reactive. The lanthanides are in Period 7.

Answers

Answer 1
Answer:

In the periodic table,the The +3 oxidation state is characteristic of the actinides. All actinides are radioactive.The actinides are silvery and chemically reactive.

What is periodic table?

Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.

It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.

Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.

Learn more about periodic table,here:

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Answer 2
Answer:

Answer:

The +3 oxidation state is characteristic of the actinides.

All actinides are radioactive.

Cerium (Ce) rnakes 100th in abundance (by mass %).

The actinides are silvery and chemically reactive.


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The amount of I − 3 ( aq ) in a solution can be determined by titration with a solution containing a known concentration of S 2 O 2 − 3 ( aq ) (thiosulfate ion). The determination is based on the net ionic equation 2 S 2 O 2 − 3 ( aq ) + I − 3 ( aq ) ⟶ S 4 O 2 − 6 ( aq ) + 3 I − ( aq ) Given that it requires 29.4 mL of 0.380 M Na 2 S 2 O 3 ( aq ) to titrate a 30.0 mL sample of I − 3 ( aq ) , calculate the molarity of I − 3 ( aq ) in the solution.

Answers

Answer:

The molarity of I₃⁻ (aq) solution: M₂ = 0.186 M

Explanation:

Given net ionic equation:  

2S₂O₃²⁻ (aq) + I₃⁻ ( aq ) ⟶ S₄O₆²⁻ (aq) + 3I⁻ (aq)

Number of moles of S₂O₃²⁻: n₁ = 2, Number of moles of I₃⁻: n₂ = 1

Given- For S₂O₃²⁻ solution: Molarity: M₁ = 0.380 M, Volume: V₁ = 29.4 mL;

For I₃⁻ (aq) solution: Molarity: M₂ = ? M, Volume: V₂ = 30.0 mL

         

To calculate the molarity of I₃⁻ (aq) solution, we use the equation:

(M_(1)V_(1))/(n_(1))=(M_(2)V_(2))/(n_(2))

((0.380 M)* (29.4 mL))/(2)=(M_(2)* (30.0 mL))/(1)

\Rightarrow M_(2) = ((0.380 M)* (29.4 mL))/((30.0 mL)* 2) = 0.186 M

Therefore, the molarity of I₃⁻ (aq) solution: M₂ = 0.186 M

Which of the two aqueous solutions will be a better conductor of electricity in the following examples? Explain why in each case.a)1.0M NaCl vs. 0.010 M Nacl
b)0.10 M NaCl vs. 0.10 M Al2(SO4)3 (assume complete dissociation of both salts).
c) 1.0 mole of NaCl added to water vs. 1.0 mole of pbCl2 added to water (hint: remember the solubility rules).

Answers

a) The solution with a concentration of 1.0 M NaCl will be a better conductor of electricity since it has a higher number of electrolytes
b) The 0.10 M Al2(SO4)3 will be a better conductor since more ions are formed per mole of the salt dissociated
c) 1.0 mol of NaCl in water because NaCl is very soluble in water

The federal limit for cadmium in drinking water is 0.010 mg per liter of solution. What is the molar concentration of a Cd solution that has reached the limit?

Answers

Thank you for posting your question here. The molar concentration of a Cd solution that has reached the limit is  8.89x10^-8 mols/L. The equation to be used  M=n/L to solve the above problem. Below is the solution:

.010mg/L = .00001g/L 
.00001g / 112.41g/mol = 8.89x10^-8 mols/L 

Answer:

M=8.9x10^(-8)M

Explanation:

Hello,

In this case, one can assume 1L as the volume of the solution, so we've got 0.010mg of cadmium. Now, as we're asked to know its molarity, one computes the moles of cadmium as follows:

n_(Cd)=0.010mg*(1x10^(-3)gCd)/(1mgCd)*(1molCd)/(112.4gCd)=8.9x10^(-8)molCd

Now, one obtains the molar concentration (molarity) as shown below:M=(8.9x10^(-8)molCd)/(1L)\n M=8.9x10^(-8)M

Best regards.

If you keep adding sugar to water and there comes a point that you cannot dissolve any more sugar to it then this is called

Answers

Answer:

.

Explanation:

Find the mole ratio of H2SO4 and H20 in the equation Fe2O3 + H2SO4 → Fe2(SO4)3 + H20.

Answers

Explanation:

Fe2O3 +3 H2SO4 → Fe2(SO4)3 + 3H20.

Therefore the ratio is 3:3

If a student weighs out 0.744 g Fe ( NO 3 ) 3 ⋅ 9 H 2 O , what is the final concentration of the ∼0.2 M Fe ( NO 3 ) 3 solution that the student makes?

Answers

Answer:

Molar concentration of Fe(NO3)3 . 9H2O = 0.12M

Explanation:

Fe(NO3).9H2O --> Fe(NO3)3 + 9H2O

By stoichiometry,

1 mole of Fe(NO3)3 will be absorb water to form 1 mole of Fe(NO3)3 . 9H2O

Therefore, calculating the mass concentration of Fe(NO3)3;

Molar mass of Fe(NO3)3 = 56 + 3*(14 + (16*3))

= 242 g/mol

Mass concentration of Fe(NO3)3 = molar mass * molar concentration

= 242 * 0.2

= 48.4 g/L

Molar mass of Fe(NO3)3 . 9H2O = 56 + 3*(14 + (16*3)) + 9* ((1*2) + 16)

= 242 + 162 g/mol

= 404g/mol

Concentration of Fe(NO3)3 . 9H2O = mass concentration/molar mass

= 48.4 /404

= 0.12 mol/l

Molar concentration of Fe(NO3)3 . 9H2O = 0.12M