PHYSICS COLLEGE

Q.1- Find the distance travelled by a particle moving in a straight line with uniform acceleration, in the 10th unit of time.

Answers

Answer 1

Answer:

Answer:

If the acceleration is constant, the movements equations are:

a(t) = A.

for the velocity we can integrate over time:

v(t) = A*t + v0

where v0 is a constant of integration (the initial velocity), for the distance traveled between t = 0 units and t = 10 units, we can solve the integral:

$\int\limits^(10)_0 {A*t + v0} \, dt = ((A/2)10^2 + v0*10) = (A*50 + v0*10)$

Where to obtain the actual distance you can replace the constant acceleration A and the initial velocity v0.

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If 3.00 ✕ 10−3 kg of gold is deposited on the negative electrode of an electrolytic cell in a period of 2.59 h, what is the current in the cell during that period? Assume the gold ions carry one elementary unit of positive charge.
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Why are certain things obligations of citizenship instead of responsibilities? atleast 5 sentences please

Answers

Answer:

Please find the answer in the explanation

Explanation:

Responsibilities of citizens are those things citizens are to take care of.

While obligations are those things that are compulsory for the citizens to observe and adhere to.

Why are certain things obligations of citizenship instead of responsibilities?

1.) Because of law and order of the community. It is mandatory for all citizens to obey the law of the land.

2.) Because of the progress and peaceful coexistence of the citizens in the community.

3.) Because of the protection of constitution of the land

4.) To support and defend the constitution

5.) To maintain orderliness and eschew violence.

We had a homework problem in which the Arrhenius equation was applied to the blinking of fireflies. Several other natural phenomena also obey that equation, including the temperature dependent chirping of crickets. A particular species, the snowy tree cricket, has been widely studied. These crickets chirp at a rate of 178 times per minute at 25.0°C, and the activation energy for the chirping process is 53.9 kJ/mol. What is the temperature if the crickets chirp at a rate of 126 times per minute?

Answers

Answer:

Temperature = 20.35°C

Explanation:

Arrhenius equation is as follows:

k = A*exp(-Ea/(R*T)), where

k = rate of chirps

Ea = Activation Energy

R = Universal Gas Constant

T = Temperature (in Kelvin)

A = Constant

Given Data

Ea = 53.9*10^3 J/mol

R = 8.3145 J/(mol.K)

T = 273.15 + 25 K

k = 178 chirps per minutes

Calculation

Using the Arrhenius equation, we can find A,

A= 4.935x10^11

Now we can apply the same equation with the data below to find T at k=126,

k = A*exp(-Ea/(R*T))

Ea = 53.9*10^3

R = 8.3145

k = 126

T = 20.35°C

Which of the following expressions is equivalent to the expression 2(x + 5)? x + 7 x + 10 2x + 5 2x + 10

Answers

Answer:

d) 2x+10

Explanation:

$2(x+5)\n=2x+10$

Question:-

Which of the following expressions is equivalent to the expression 2(x + 5)?

x + 7
x + 10
2x + 5
2x + 10

Answer:-

2x+10

Explanation:-

take 2 as common from both the terms :-

$: \implies \sf 2x + 10$

$: \implies \sf 2(x + 5)$

Hope u got what u were looking for

A rock is pulled back in a slingshot as shown in the diagram below. The elastic on the slingshot is displaced 0.2 meters from its initial position. The rock is pulled back with a force of 10 newtons.When the rock is released, what is its kinetic energy?

Answers

The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.

What will be the speed of the rock?

Initial speed of the rock, u = 40m/s

Final position of the rock s = 0m taking the release point as reference. The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.

Nuclear energy is a useful source of power but has disadvantages. The disadvantage of nuclear energy is it produces dangerous waste.

Initial speed of the rock, u = 40m/s

Final position of the rock s = 0m taking the release point as reference

From the second equation of motion:

solving above we get:

t = 0s or t = 8.16s, t =0 seconds is neglected since it represents the initial position which is the same as the final position at t = 8.16s

So, the rock takes 8.16 seconds to return to the release point.

Therefore, The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.

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Answer:

Explanation:

i don't know

A piston-cylinder device initially contains 1.4 kg saturated liquid water at 200oC. Now heat is transferred to the water until the volume quadruples and the cylinder contains saturated vapor only. Determine (a) the volume of the cylinder, (b) the final temperature.

Answers

Answer:

Explanation:

Given

mass of saturated liquid water $m=1.4\ kg$

at $200^(\circ)$ specific volume is $\nu =0.001157\ m^3\kg$ (From Table A-4,Saturated water Temperature table)

$V_1=m\nu _1$

$V_1=1.4* 0.001157$

$V_1=1.6198* 10^(-3)\ m^3$

Final Volume $V_2=4V_1$

$V_2=4* (1.6198* 10^(-3))$

$V_2=6.4792* 10^(-3)\ m^3$

Specific volume at this stage

$\nu _2=(V_2)/(m)$

$\nu _2=(6.4792* 10^(-3))/(1.4)$

$\nu _2=0.004628\ m^3/kg$

Now we see the value and find the temperature it corresponds to specific volume at vapor stage in the table.

$T_2=T_1^(*)+(T_2^(*)-T_1^(*))/(\alpha _2^(*)-\alpha _1^(*))* (\alpha _2-\alpha _1^(*))$

$T_2=370^(\circ)+(373.95-370)/(0.003106-0.004953)* (0.004628-0.004953)$

$T_2=370.7^(\circ) C$

Final answer:

The problem in the question is solved using the principles of thermodynamics. The volume of the device after the heat transfer is 6311.2 cm³. The final temperature inside the cylinder, when the water reached the state of saturated vapor, is approximately 240°C.

Explanation:

The subject question is a thermodynamics problem; more specifically dealing with changes of state, volume, and temperature in a system under certain conditions.

For solving part (a), one would first need to find the specific volume (v) at the initial state, which is saturated liquid at 200°C. Looking up in the property tables, we see that v = 1.127 cm³/g for saturated water at 200°C. Then, the initial volume (V) is mass times specific volume, so V = 1.4 kg x 1.127cm³/g x 1000g/kg = 1577.8 cm³. Because volume quadrupled, the final volume is 4 x 1577.8 cm³ = 6311.2 cm³.

For part (b), at the final state, the water is a saturated vapor. The specific volume at the final state is the final volume divided by the mass, which equals to 6311.2 cm³ / 1.4kg / 1000g/kg = 4.507 cm³/g. Look this value up in the property table to find the corresponding temperature. We get a final temperature of about 240°C.

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A child is sitting on the outer edge of a merry-go-round that is 18 m in diameter. if the merry-go-round makes 5.9 rev/min, what is the velocity of the child in m/s?

Answers

Answer: The velocity of the kid is 5.6 m/s

Explanation: Ok, the velocity of the kid will be:

v = w*r

where r is the radius, and w is the frequency.

We know that the diameter is 18m, and the diameter is equal to two times the radius. So r = 18m/2 = 9m

Now, we know that the circumference of a circle is equal to c = 2pi*r, so each revolution has this length, if the kid does 5.9 revolutions in one minute, then the kid spins at v = 5.9*2pi*9m/min

But we want to write this in meters per second, this means that we need to divide it by 60.

v = (5.9*2pi*9/60)m/s = 5.56 m/s

Velocity of the child= 20008.1 m/s

Explanation;

diameter= 18 m

the linear velocity v is given by

v= r ω

r= radius=18/2= 9 m

ω= 5.9 rev/ min = 5.9 rev/min* [2π rad/ 1 rev] *[60 s/ 1 min]=2223.1 rad/s

so V= 9 (2223.1)

V= 20008.1 m/s

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A centrifuge is a common laboratory instrument that separates components of differing densities in solution. This is accomplished by spinning a sample around in a circle with a large angular speed. Suppose that after a centrifuge in a medical laboratory is turned off, it continues to rotate with a constant angular deceleration for 10.0s before coming to rest.Part AIf its initial angular speed was 3890rpm , what is the magnitude of its angular deceleration? (|?| in revs/s^2 )Part BHow many revolutions did the centrifuge complete after being turned off?