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The temperature of a solution will be estimated by taking n independent readings and averaging them. Each reading is unbiased, with a standard deviation of σ = 0.5°C. How many readings must be taken so that the probability is 0.90 that the average is within ±0.1◦C of the actual temperature? Round the answer to the next largest whole number.

Answers

Answer 1

Answer:

Answer:

68 readings.

Explanation:

We need to take this problem as a statistic problem where the normal distribution table help us.

We can start considerating that X is the temperature of the solution, then

$0.9 = P(|\bar{x}-\mu|<0.1)$

$0.9 = P(\frac{|\bar{x}-\mu|}{(\sigma)/(√(n))}<(0.1)/((\sigma)/(√(n))))$

$0.9 = P(|Z|<(0.1)/((\sigma)/(√(n))))$

For a confidence level of 90% our $Z_(critic)$ is 1.645

Therefore,

$(0.1)/((\sigma)/(√(n))) = 1.645$

Substituting for $\sigma = 5$ and re-arrange for n, we have that n is equal to

$n=((1.645\sigma)/(0.1))^2$

$n=((1.645)^2(0.5)^2)/(0.1^2)$

$n=67.65$

$n=68$

We need to make 68 readings for have a probability of 90% and our average is within $0.1\°\frac$

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If the solution described in the introduction is cooled to 0 ∘c, what mass of kno3 should crystallize? enter your answer numerically in grams.

Answers

14 g is the solubility per 100 g water, since it is difficult to read the graph.
Then, in 130 g H20 the solubility would be 14 g KNO3/100 g H2O x 130 g H2O = 18 g KNO3
The question asks how much crystallizes.
Initial 34.0 g minus 18.0 g still dissolved = 16.0 g crystallizes.

KNO3 of 10g will undergo crystallization at 0 °

Because the heavier the KNO3 mass will require a higher temperature in the dissolution process.

Further explanation

Potassium nitrate is a nitrate salt compound from potassium with the molecular formula KNO3. Potassium nitrate salt can be made by reacting potassium chloride with sodium nitrate. If the saturated solution each of the solution is mixed with each other, then it will form sodium chloride salt because NaCl in water is small, the salt will settle. By cooling the filtered filtrate KNO3 will undergo crystallization

This compound decomposes with oxygen evolution at 500 ° C according to the reaction equation:

2 NaNO3 (s) -> 2NaNO 2 (s) + O2 (g)

Crystallization is separation by forming crystals so that the mixture can be separated. A gaseous or liquid substance can cool or condense and form crystals because it undergoes a crystallization process. Crystals will also form from a solution that will be saturated with a certain solvent. The more the number of crystals, the better, because the less likely to be polluted by dirt.

Potassium Nitrate has a physical white powder that is easily soluble in water and odorless. Meanwhile, to analyze the structure and characteristics of Potassium Nitrate MM2 data processing is used in the Chemoffice 15.0 application. This data processing is used to determine the shape of compounds, types of bonds in molecular movement compounds and other parts that can not be observed directly by the eye without the aid of tools. And for the form of compounds in 2 dimensions and 3 dimensions used Chemdraw 15.0 and Chem3D 15.0 applications

Learn more

Potassium nitrate brainly.com/question/10847775

Crystallization brainly.com/question/2575925

Details

Grade: High School

Subject: Chemistry

Keyword: kno3, nitrate, crystallization

wo balls have the same mass of 5.00 kg. Suppose that these two balls are attached to a rigid massless rod of length 2L, where L = 0.550 m. One is attached at one end of the rod and the other at the middle of the rod. If the rod is held by the open end and rotates in a circular motion with angular speed of 45.6 revolutions per second,

Answers

Answer:

$T_1 =677224.40\ N$

Explanation:

given,

mass of the both ball = 5 Kg

length of rod = 2 L

where L = 0.55 m

angular speed = 45.6 rev/s

ω = 45.6 x 2 π

ω = 286.51 rad/s

v₁ = r₁ ω₁

v₁ =0.55 x 286.51 = 157.58 m/s

v₂ = r₂ ω₂

v₂ = 1.10 x 286.51 = 315.161 m/s

finding tension on the first half of the rod

r₁ = 0.55 r₂ = 2 x r₁ = 1.10

$T_1 = m ((v_1^2)/(r_1)+(v_2^2)/(r_2))$

$T_1 = 5 ((157.58^2)/(0.55_1)+(315.161^2)/(1.1))$

$T_1 =677224.40\ N$

Question Part Points Submissions Used A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.30 m/s in 0.812 s. (a) What is the magnitude of the linear impulse experienced by a 62.0-kg passenger in the car during the time the car accelerates? kg · m/s (b) What is the magnitude of the average total force experienced by a 62.0-kg passenger in the car during the time the car accelerates? N

Answers

(a) 328.6 kg m/s

The linear impulse experienced by the passenger in the car is equal to the change in momentum of the passenger:

$I=\Delta p = m\Delta v$

where

m = 62.0 kg is the mass of the passenger

$\Delta v$ is the change in velocity of the car (and the passenger), which is

$\Delta v = 5.30 m/s - 0 = 5.30 m/s$

So, the linear impulse experienced by the passenger is

$I=(62.0 kg)(5.30 m/s)=328.6 kg m/s$

(b) 404.7 N

The linear impulse experienced by the passenger is also equal to the product between the average force and the time interval:

$I=F \Delta t$

where in this case

$I=328.6 kg m/s$ is the linear impulse

$\Delta t = 0.812 s$ is the time during which the force is applied

Solving the equation for F, we find the magnitude of the average force experienced by the passenger:

$F=(I)/(\Delta t)=(328.6 kg m/s)/(0.812 s)=404.7 N$

PLEASE HELP QUICKLY!A volleyball player jumps to hit a ball horizontally at 7.0 m/s straight on. If the
height at which the ball was hit is 3.0 m tall, how far did the ball go horizontally
before it hit the ground?
5.5 m
3.6 m
O 4.3 m
4.2 m

Answers

Answer:

5.5 is the correct answer

please keeps as Brainly list

A physicist is creating a computational model of a falling person before and after opening a parachute. What boundary conditions would be important here?the air resistance encountered as the person falls

the speed at which the person falls

the change in kinetic and potential energy

the location where potential energy is zero