The gravitational force law, deduced by Newton in the 1660's, is remarkably similar to Coulomb's law. Recall that the universal law of gravitation states that the magnitude of the gravitational force between two masses M1 and M2 separated by a distance R is given by the following equation:________. F = G (M1 x M2) / R2
G = 6.67 x 10-11 Nm2/kg2
a. Calculate the value of the gravitational force between an electron (mass = 9.11 x 10-31 kg) and a proton (mass is 1836 times greater than the mass of an electron) if the two particles are separated by 3.602 nanometers. (1 nanometer or 1 nm = 1 x 10-9 m)
F= ______ N
b. The force created in the above question is:
1. repulsive
2. attractive

Answer:

When the jet reaches a speed of 181 m/s, its displacement is 296 m.

Explanation:

Hi there!

The equation of position and velocity of an object traveling with constant acceleration along a straight line are the following:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

v = velocity of the object at time t.

If we place the origin of the frame of reference at the point where the jet starts moving, then, x0 = 0. Since the jet starts from rest, v0 is also zero. Then the equations get reduced to the following:

x =  1/2 · a · t²

v = a · t

We know the acceleration and the final velocity of the jet. So, using the equation of velocity, we can find the time it takes the jet to reach that velocity. Then, we can calculate the position of the jet at that time. Since the initial position is zero, the final position of the jet will be equal to the displacement (because displacement = final position - initial position).

v = a · t

v/a = t

181 m/s / 55.3 m/s² = t

t = 3.27 s

The final position of the jet will be:

x =  1/2 · a · t²

x = 1/2 · 55.3 m/s² · (3.27 s)²

x = 296 m

When the jet reaches a speed of 181 m/s, its displacement is 296 m.

The displacement of the F-35 jet when it reaches a speed of 181 m/s is 16515 m.

To find displacement using constant acceleration,

we can use the following equation:

displacement = (final velocity)^2 - (initial velocity)^2 / 2 * acceleration.

In this case, the initial velocity is 0 m/s and the final velocity is 181 m/s.

The acceleration is given as 55.3 m/s^2.

Plugging in these values, we get:

displacement = (181)^2 - (0)^2 / 2 * 55.3 = 16515 m.

The displacement of the F-35 jet when it reaches a speed of 181 m/s is 16515 m.

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Answer:

Path 3 and Path 1

Explanation:

Along Path1andPath3, the distance travelled will be different than the displacement.

In Path1 and Path3 the distance travelled will be more than the displacement. Whereas, in Path2, the displacement will be as same as the distance travelled because in path 2, the distance travelled itself is the shortest distance from initial point ( A ) to final point ( B ).

But, inPath1 and Path3, the total distance travelled isn't the shortest distance from initial point ( A ) to final point ( B ), hene displacement and distance travelled will be different.

Along Path 1 and path 3 your distance traveled be different than your displacement.

Distance is the total length of the path traveled by an object. It is a scalar quantity, meaning it has only magnitude and no direction.

Displacement is the change in the object's position from its initial to its final position. It is a vector quantity, meaning it has both magnitude and direction.

For example, if an object moves in a circle, the distance traveled will be equal to the circumference of the circle, but the displacement will be zero, since the object returns to its initial position.

Another example is if an object moves back and forth along a straight line, the distance traveled will be twice the length of the line, but the displacement will be zero, since the object returns to its initial position.

In general, the distance traveled will always be greater than or equal to the displacement. This is because the distance traveled includes all of the path that the object takes, while the displacement only includes the change in the object's position.

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Answer:

Acceleration=24.9ft^2/s^2

Angular acceleration=1.47rads/s

Explanation:

Note before the ladder is inclined at 30° to the horizontal with a length of 16ft

Hence angular velocity = 6/8=0.75rad/s

acceleration Ab=Aa +(Ab/a)+(Ab/a)t

4+0.75^2*16+a*16

0=0.75^2*16cos30°-a*16sin30°---1

Ab=0+0.75^2sin30°+a*16cos30°----2

Solving equation 1

(0.75^2*16cos30/16sin30)=angular acceleration=a=1.47rad/s

Also from equation 2

Ab=0.75^2*16sin30+1.47*16cos30=24.9ft^2/s^2

Answer:

The magnitude and direction of the magnetic field is 0.009014 T in the negative y direction.

Explanation:

Given that,

Speed

Acceleration

We need to calculate the magnetic field

Using formula of magnetic field

....(I)

Using newton's second law

....(II)

From equation (I) and (II)

Put the value into the formula

We need to calculate the direction of the field

Using the right hand rule, point the right hand fingers along the velocity which is in the positive z direction.

Now, if we curl the fingers along the direction of magnetic field that is in the negative y direction, then the thumb will point in the positive x direction.

Hence, The magnitude and direction of the magnetic field is 0.009014 T in the negative y direction.

Answer:

I = 0.0025 kg.m²

Explanation:

Given that

m= 2 kg

Diameter ,d= 0.1 m

Radius ,

R=0.05 m

The moment of inertia of the cylinder about it's axis same as the disc and it is given as

Now by putting the all values

I = 0.0025 kg.m²

Therefore we can say that the moment of inertia of the cylinder will be  0.0025 kg.m².