CHEMISTRY HIGH SCHOOL

Click on the diagram to choose which atom is more reactive.

Answers

Answer 1

Answer:

Answer:

Second graph is more reactive.

Explanation:

I just did the lesson myself, chose the first graph, and obviously got it wrong.

Therefore I can tell you with 100% certainty that the correct answer is graph #2 in this case. Hope this helps.

Answer 2

Answer: The first diagram is the atom that is more reactive

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Which among the following will make lime water look milky?Immersive Reader(1 Point)
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Answers

Which among the following will make lime water look milky

option C) Ca(OH)₂

What is the molar mass of ph

Answers

30.973762 u ± 0.000002 u Hope this Helps >>

What is the oxidation number of Mn in KMnO₄? a. -7
b. -3
c. 0
d. +3
e. +7

Answers

I think the answer is e? That's if o is -2 if not it will be a

Please help ASAP ty :)

Answers

Answer:

c or d it measures smallest to biggest and biggest to smallest

Answer:

your answer is a

Explanation:

Find the volume of 20.0 g of benzene

Answers

(d) Density of Benzene: 0.8786 g/cm cubed
(m) Mass: 20.00g
Formula to solve (v) volume of benzene: V=m/d
V=20g / 0.8786g/cm cubed
Answer: Volume of benzene is: 22.8 cm cubed

Explanation: Well, density is mass divided volume. In this, it is what the volume is. All you need is mass divided by density. Hope this helps!

Final answer:

To calculate the volume of 20.0 g of benzene, use the formula volume = mass/density. Given that the density of benzene is 0.879 g/mL, the volume is approximately 22.75 mL when you divide 20.0 g by 0.879 g/mL.

Explanation:

To find the volume of 20.0 g of benzene, we need to use the density of benzene because density is defined as mass per unit volume (density = mass/volume). The formula to calculate the volume from the mass and density is volume = mass/density.

In this case, we are given:

Mass of benzene = 20.0 g
Density of benzene = 0.879 g/mL (from the provided information)

To calculate the volume, we divide the mass by the density:

Volume = Mass / Density = 20.0 g / 0.879 g/mL

We can now perform the calculation:

Volume = 20.0 g / 0.879 g/mL ≈ 22.75 mL

Therefore, the volume of 20.0 g of benzene is approximately 22.75 mL.

Learn more about Volume Calculation here:

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Under conditions when glucose oxidation is elevated, the acetyl-CoA produced will allosterically activate which of the following enzymes leading to an increase in the production of oxaloacetate?a. Pyruvate carboxylase

b. Citrate lyase

c. Acetyl-CoA carboxylase

d. Malate dehydrogenase

Answers

The correct answer is ( a. Pyruvate carboxylase).

When glucose oxidation is elevated, the acetyl-CoA produced will allosterically activate the enzyme pyruvate carboxylase, leading to an increase in oxaloacetate production.