PHYSICS COLLEGE

A uniform, 4.5 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its upper edge. A 1.3 kg raven flying horizontally at 4.5 m/s flies into this door at its center and bounces back at 2.5 m/s in the opposite direction. (a) What is the angular speed of the gate just after it is struck by the unfortunate raven? (b) During the collision, why is the angular momentum conserved but not the linear momentum?

Answers

Answer 1
Answer:

Answer:

a) Angular speed(w) = 2.02rad/sec

b) 73J ( It is Inelastic Collision)

Explanation:

Given:

Mass=45kg

Length on each side = 1.5m side which is hangs vertically from a frictionless pivot at the center of its upper edge.

We need to calculate

(a) What is the angular speed and

(b) To know why the angular momentum conserved but not the linear momentum

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

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Before 1960, people believed that the maximum attainable coefficient of static friction for an automobile tire on a roadway was ?s = 1. Around 1962, three companies independently developed racing tires with coefficients of 1.6. This problem shows that tires have improved further since then. The shortest time interval in which a piston-engine car initially at rest has covered a distance of one-quarter mile is about 4.43 s. (A) Assume the car's rear wheels lift the front wheels off the pavement as shown in the figure above. What minimum value of ?s is necessary to achieve the record time?
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A sound wave travels with a velocity of 330 m/s and has a frequency of 500 Hz. What is itswavelength?

Answers

Answer:

Wavelength = 0.66 meters

Explanation:

Given the following data;

Speed = 330 m/s

Frequency = 500 Hz

To find the wavelength;

Mathematically, wavelength is calculated using this formula;

Wavelength = \frac {speed}{frequency}

Substituting into the equation, we have;

Wavelength = \frac {330}{500}

Wavelength = 0.66 meters

What force causes oppositely charged particles to attract each other? A. Magnetic force B. Compression
C. Electrical Force D. Gravity

Answers

Answer:

It is electrical force

Explanation:

i got it wrong on A P E X  with magnetic hope this helps!

Answer:

The electromagnetic force.

What kind of exercise should you do when you're cooling down after an
intense workout?

Answers

Answer:

Planks?

Explanation:

It's kinda resting

Answer:

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A laser (electromagnetic wave) has the maximum electric field strength of 1.0x1011 V/m. What is the force the laser applies on a mirror (totally reflective) of 5.0 mm2 area? A. 2.76 x105N B. 1.21 x106N C. 1.94 x106N D.4.43 x105 N E. 7.82 x104N

Answers

Answer:

The correct option is  D

Explanation:

From the question we are told that

  The maximum electric field strength is  E = 1.0 *10^(11) \ V/m

   The  area is  A = 5.0 \ mm^2 = 5.0 *10^(-6) \ m^2

Generally the force the laser applies is mathematically represented as

       F = \epsilon_o * E ^2 * A

Here  \epsilon_o = 8.85*10^(-12) C/(V \cdot m)

      F = 8.85*10^(-12) * (1.0 *10^(11)) ^2 * 5.00*10^(-6 )

=>   F = 4.43 *10^(5) \ N

Light emitted by element X passes through a diffraction grating that has 1200 slits/mm. The interference pattern is observed on a screen 75.0 cm behind the grating. First-order maxima are observed at distances of 56.2 cm, 65.9 cm, and 93.5 cm from the central maximum. What are the wavelengths of light emitted by element X?

Answers

Answer:

Explanation:

Width of slit = 10⁻³ / 1200

d  = 8.3 x 10⁻⁷ m

First order maxima will be observed at

x = λD/d

D = 75 cm = 75 x 10⁻² m

56.2 x 10⁻² = λ₁D/d

= λ₁ x 75 x 10⁻² / 8.3 x 10⁻⁷

λ₁ = 56.2 x 8.3 x 10⁻⁷ / 75

= 6.219 x  10⁻⁷ m

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λ₂ = 65.9 x 8.3 x 10⁻⁷ / 75

= 7293 A

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A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle are both traveling at the same speed of 19.0m/s , and the distance between them is 52.0m . After t1 = 5.00s , the motorcycle starts to accelerate at a rate of 5.00m/s^2. a. How long does it take from the moment when the motorcycle starts to accelerate until it catches up with the car? In other words. b. Find t2−t1

Answers

Answer:

t\approx4.561\ s

Explanation:

Given:

  • initial speed of car and motorcycle, v=19\ m.s^(-1)
  • initial distance between the car and motorcycle, s=52\ m
  • time after which the motorcycle starts to accelerate, t_1=5\ s
  • rate of acceleration of motorcycle, a=5\ m.s^(-2)

The initially the relative velocity of the motorcycle is zero with respect to car.

Now using the equation of motion in the relative quantities:

s=u.t+(1)/(2) .a.t^2

here:

s = relative distance of motorcycle with respect to the car

u= initial relative velocity of the motorcycle with respect to the car

t= time taken to cover the distance gap from the car.

52=0+0.5* 5* t^2

t\approx4.561\ s
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