Calculate the wavelength of a wave if 5 complete waves occupy a length of 20m

Answers

Answer 1

Answer:

The wavelength of the wave will be 4 meters. when 5 complete waves occupy a length of 20m.

What is wavelength?

Wavelength is defined as the space between waves' crests, particularly between electromagnetic or sound wave points. A recurring event's frequency is measured by how many times it occurs in a unit of time. To underline the difference from spatial frequency, it is also occasionally referred to as temporal frequency.

There is an inverse relationship between the frequency and the wavelength of the waves as the wavelength increases the frequency decreases and if the wavelength decreases the frequency increases.

Given that a wave has 5 complete waves occupying a length of 20m. The wavelength of the wave will be calculated as below:-

λ = Distance / frequency

λ = 20 / 5

λ = 4 meters

Therefore, the wavelength of the wave will be 4 meters. when 5 complete waves occupy a length of 20m.

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Answer 2

Answer: the answer is 20 / 5 = 4

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An unbalanced force of 40. newtons keeps a5.0-kilogram object traveling in a circle of radius 2.0 meters. What is the speed of the object? (1) 8.0 m/s (3) 16 m/s (2) 2.0 m/s (4) 4.0 m/s
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.If you are working as a forensic scientist and are given an unknown powder from a crime scene, what would you hope to find out about the powder?

Answers

what the powder contains if its drugs a poison or anything bad

Answer:

you will hope to find out that it is nothing dangerous so anyone who came into contact with it would not be harmed.

Explanation:

The temperature of a system must increase when heat energy is added true or false?

Answers

False.

In fact, the temperature T of a system is directly proportional to the internal energy U of the system, and the first law of thermodynamics states that the variation of internal energy of a system is given by
$\Delta U = Q-W$
where
Q is the heat added to the system
W is the work done by the system on the surroundings

We see from the formula that we have 2 possible cases:
1) the heat added to the system (Q) is greater than the work done by the system (W) --> $\Delta U$ is positive, this means that the temperature of the system increases
2) the heat added to the system (Q) is less than the work done by the system (W) --> $\Delta U$ is negative, this means that the temperature of the system decreases

Therefore, it's not true that when heat is added to the system, its temperature must increase: it depends on the value of the work done, W. So, the original statement is false.

Ideally, when a thermometer is used to measure the temperature of an object, the temperature of the object itself should not change. However, if a significant amount of heat flows from the object to the thermometer, the temperature will change. A thermometer has a mass of 33.0 g, a specific heat capacity of c = 804 J/(kg C°), and a temperature of 15.4 °C. It is immersed in 149 g of water, and the final temperature of the water and thermometer is 56.0 °C. What was the temperature of the water in degrees Celsius before the insertion of the thermometer?

Answers

Answer : The temperature of water is, $57.7^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1* c_1* (T_f-T_1)=-m_2* c_2* (T_f-T_2)$

where,

$c_1$ = specific heat of thermometer = $804J/kg.^oC=0.804J/g^oC$

$c_2$ = specific heat of water = $4.18J/g.^oC$

$m_1$ = mass of thermometer = 33.0 g

$m_2$ = mass of water = 149 g

$T_f$ = final temperature = $56.0^oC$

$T_1$ = initial temperature of thermometer = $15.4^oC$

$T_2$ = initial temperature of water = ?

Now put all the given values in the above formula, we get:

$33.0g* 0.804J/g^oC* (56.0-15.4)^oC=-149g* 4.18J/g.^oC* (56.0-T_2)^oC$

$T_2=57.7^oC$

Therefore, the temperature of water is, $57.7^oC$

A sea breeze occurs because warm air rises on land and moves toward the ocean to cool. The cool air then moves from the ocean to be warmed by the land. a. True
b. False

Answers

im going to go with a. True

The answer is A, true.

An automobile covered the distance of 240 km between A and B with a certain speed. On its way back, the automobile covered half of the distance at the same speed and for the rest of the trip he increased his speed by 10 km/hour. As a result, the drive back took him 2 5 of an hour less than the drive from A to B. What was the automobile’s speed when it was driving from A to B?

Answers

Answer:

Therefore the speed of automobile when it was driving from A to B was 50 km/ h.

Explanation:

Given that,

An automobile covered the distance of 240 km between A and B with a certain speed.

Let the speed of the automobile be x km/hour.

We know that,

$Time =(distance)/(speed)$

Time taken to travel from A to B point is $=(240)/(x)$ hours.

On its back, the automobile covered half of distance= 120 km at the same speed and for the trip he increased his speed 10 km/hour.

Time taken to complete the trip is

$=((120)/(x)+(120)/(x+10))$ hours

The driver took $\frac25$ of an hour less when he come back.

According to problem,

$(240)/(x)-((120)/(x)+(120)/(x+10))=\frac25$

$\Rightarrow(240)/(x)- (120)/(x)-(120)/(x+10)=\frac25$

$\Rightarrow(240-120)/(x)-(120)/(x+10)=\frac25$

$\Rightarrow(120)/(x)-(120)/(x+10)=\frac25$

$\Rightarrow(120(x+10)-120x)/(x(x+10))=\frac25$

$\Rightarrow(120x+1200-120x)/(x^2+10x)=\frac25$

$\Rightarrow(1200)/(x^2+10x)=\frac25$

$\Rightarrow 2(x^2+10x)=1200* 5$

$\Rightarrow (x^2+10x)=(1200* 5)/(2)$

$\Rightarrow (x^2+10x)=3000$

$\Rightarrow x^2+10x-3000=0$

$\Rightarrow x^2+60x-50x-3000=0$

⇒x(x+60)-50(x+60)=0

⇒(x+60)(x-50)=0

⇒x= -60, 50

The speed could not negative.

So, x=50

Therefore the speed of automobile when it was driving from A to B was 50 km/ h.

When Emma pushes a bag with a force of 27 newtons, the coefficient of kinetic friction between the bag and the floor is 0.23. What is the normal force acting on the bag by the floor?

Answers

Normal force(N) is always equal and opposite to the weight.
The floor is exerting an upward force upon the bag in order to support the weight of the bag.
Friction force is proportional to the normal force:
f = k * N
In this case: f=27 N, k=0.23
27 N = 0.23 * N
N= 27 N : 0.23 = 117.39 N

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