Rate at which electric energy is converteto another form (2 words)
Rate at which electric energy is converteto another form (2 - 1

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Answer 1
Answer: electric power!!!!!!!

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During a very cold winter, water pipes sometimes burst. Why?

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Water pipes can burst during very cold winters due to a phenomenon known as "freeze-thaw cycle." When temperatures plummet, water inside the pipes can freeze, causing it to expand and exert pressure on the pipe walls.

Water molecules expand as they freeze, creating a buildup of pressure within the pipe. Pipes are designed to withstand a certain amount of pressure, but when it exceeds their capacity, they can rupture or burst. Furthermore, pipes made of materials like metal or plastic can become brittle in extremely cold temperatures. The cold causes the material to contract, reducing its flexibility and making it more susceptible to cracks and breaks. This can weaken the structural integrity of the pipe, making it more likely to rupture when subjected to the internal pressure from the frozen water. Preventing pipe bursts during cold winters involves insulating pipes, maintaining a constant flow of water, and keeping indoor spaces adequately heated to mitigate the freezing and expansion of water within the pipes.

Additionally, stagnant water in pipes is more prone to freezing than flowing water. Pipes that aren't used frequently, like those in less-used areas of a building, may freeze more easily during extended cold periods.

To know more about freeze-thaw cycle:

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The tip of a fan blade is 0.61 m from the center of the fan. The fan turns at a constant speed and completes 2 rotations every 1.0 second. What is the centripetal acceleration of the tip of the fan blade? Option 1: 6.0 m/s² Option 2: 48 m/s² Option 3: 53 m/s² Option 4: 96 m/s²

Answers

Answer: Here's my answer, I made it step-by-step so you can understand it! <3

Explanation:

To find the centripetal acceleration of the tip of the fan blade, we can use the formula for centripetal acceleration:

a = (v^2) / r

where:

a is the centripetal acceleration,

v is the linear velocity, and

r is the radius of the circular path.

Given that the fan completes 2 rotations every 1.0 second, we can find the angular velocity (ω) using the formula:

ω = (2π * n) / t

where:

ω is the angular velocity,

π is a constant (approximately 3.14),

n is the number of rotations (2),

and t is the time taken (1.0 second).

Substituting the values into the formula, we have:

ω = (2π * 2) / 1.0 = 4π rad/s

Next, we can calculate the linear velocity (v) using the formula:

v = r * ω

Substituting the given radius value (0.61 m) and the angular velocity we found earlier, we have:

v = 0.61 * 4π = 2.44π m/s

Finally, we can calculate the centripetal acceleration (a) using the formula:

a = (v^2) / r

Substituting the linear velocity and the radius, we have:

a = (2.44π)^2 / 0.61 = 5.88π^2 / 0.61 ≈ 96 m/s²

Therefore, the centripetal acceleration of the tip of the fan blade is approximately 96 m/s² (Option 4).

In a closed system, glider A with a mass of 0.40 kg and a speed of 2.00 m/s collides with glider B at rest with a mass of 1.20 kg. The two interlock and move off. What speed are they moving at?

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The speed are they moving at will be 0.5 m/sec.Law of conservation of momentum is applied.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of 1st gilder=  0.40 kg

(u₁) is the initial velocity = 2 m/s

(m₂) is the mass of 2nd gilder = 1.20 kg

(u₂) is the initial velocity of 2nd gilder = 0 m/s

(v) is the velocity after collision =.?  

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\n\n(0.40* 0.25) + (1.2 * 0) = v * (0.40+1.20) \n\n 125 + 0 = v * (1250) * 125 \n\n \rm v= (0.8)/(1.6) \n\n \rm v= 0.5 \ m/sec

Hence, the speed are they moving at will be 0.5 m/sec

To learn more about the law of conservation of momentum refer;

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Conservation of momentum.
m1*u1 + m2*u2 =m1*v1 + m2*v2
here u2=0 body at rest, v1=v2=v both interlock and move together
0..4*2+1.2*0 = 0.4*v+1.2*v
v= 0.8/1.6 = 0.5 m/sec

A piston above liquid in a closed container has an area of 1m2. The piston carries a load of 350 kg. What will be the external pressure on the upper surface of the liquid in KPA

Answers

Answer:

3.43 kPa

Explanation:

Pressure is defined as the ratio between the force applied and the area of the surface on which the force is applied:

p=(F)/(A)

in this problem, the force corresponds to the weight of the load, which is given by the product between its mass (350 kg) and the acceleration due to gravity (9.8 m/s^2):

F=mg=(350 kg)(9.8 m/s^2)=3430 N

And since the area on which this force is applied is A=1 m^2, the pressure exerted on the upper surface of the liquid is

p=(F)/(A)=(3430 N)/(1 m^2)=3430 Pa = 3.43 kPa

Pressure = force / area

I assume that 350kg is the mass 
Therefore, 

350 x 9.8 (gravity) = 3430N

3430 / 1 = 3430Pa

3.43 KPa


I need help on this, please tell me what it is.

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Answer:

maria is right.

Explanation:

The way the brain perceives the intensity of a sound is

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The way the sound waves hit your eardrums and they are moved by the sound pressure. Then your brain takes over from there.
The way the brain perceives the intensity of sound is called loudness