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2(x + 25) =100 hellppppppp meee

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Answer 1

Answer:

Answer:

x=25

Step-by-step explanation:

2(x+25)=100

2x+50=100

2x=50

x=25

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Plz help me

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Answer:

its most likey 4 the answer is 4

PLEASE HELPP MEE ASAPP!!

Answers

Answer:

Step-by-step explanation:

each zero of the function will have a factor of (x - x₀)

h(x) = a(x + 3)(x + 2)(x - 1)

h(x) = a(x + 3)(x² + x - 2)

h(x) = a(x³ + 4x² + x - 6)

or the third option works if a = 1

however this equation gives us the points (0, -6) and (-1. -4), so "a" must be -2

h(x) = -2x³ - 8x² - 2x + 12

to fit ALL of the given points as it fits the three zeros and also h(0) and h(-1) so I guess that is why the given group is a partial set of solution sets

A portrait without its frame has a height 1.5 times its width w, in inches. The width of the frame is 3 inches. Which of the following is an expression for the area of the framed portrait in terms of w

Answers

Answer:

Area = $1.5w^2+15w+36$

Step-by-step explanation:

Let the width of portrait be 'w'

Given:

Height of portrait without frame (h) = 1.5 times its width = $1.5w$

Width of the frame is 3 inches on all sides.

Area of the framed portrait is the total area of the portrait plus the area of the frame.

The figure representing the above scenario is shown below.

From the figure, area of rectangle ABCD is the area of the framed portrait.

From the figure,

AB = $3 + w + 3 = w + 6$

BC = $3 + h + 3 = h + 6 = 1.5w + 6$

Now, area of the rectangle ABCD is given as the product of the length AB and width BC. Therefore,

$Area=AB* BC\n\nArea=(w+6)(1.5w+6)\n\nArea=(w* 1.5w)+(w* 6)+(6* 1.5w)+(6* 6)\n\nArea=1.5w^2+6w+9w+36\n\nArea=1.5w^2+15w+36$

Therefore, the expression for the area of the framed portrait in terms of the width 'w' is given as:

Area = $1.5w^2+15w+36$

The area of the portrait without the frame will be $A=13.5=1.5w^2$ .

Given information:

A portrait without its frame has a height 1.5 times its width w, in inches.

The width of the frame is 3 inches.

Length of the frame will be,

$l=1.5w\nl=1.5* 3\nl=4.5$

So, the area of portrait without frame will be,

$A=l* w\nA=1.5w* w\nA=1.5w^2\nA=1.5* 9=13.5=1.5w^2$

Therefore, the area of the portrait without the frame will be $A=13.5=1.5w^2$ .

For more details, refer to the link:

brainly.com/question/15218510

Directions: Solve the multi-step equation showing your work!

Answers

If I remember how to do these I’m really sorry if it’s wrong

Evaluate the given integral by making an appropriate change of variables, where R is the region in the first quadrant bounded by the ellipse 64x2 + 81y2 = 1. $ L=\iint_{R} {\color{red}9} \sin ({\color{red}384} x^{2} + {\color{red}486} y^{2})\,dA $.

Answers

$\displaystyle\iint_R\sin(384x^2+486y^2)\,\mathrm dA$

Notice that Given that $R$ is an ellipse, consider a conversion to polar coordinates:

$\begin{cases}x(r,\theta)=\frac r8\cos\theta\ny(r,\theta)=\frac r9\sin\theta\end{cases}$

The Jacobian for this transformation is

$J=\begin{bmatrix}\frac18\cos\theta&-\frac r8\sin\theta\n\frac19\sin\theta&\frac r9\cos t\end{bmatrix}$

with determinant $\det J=\frac r{72}$

Then the integral in polar coordinates is

$\displaystyle\frac1{72}\int_0^(\pi/2)\int_0^1\sin(6r^2\cos^2t+6r^2\sin^2t)r\,\mathrm dr\,\mathrm d\theta=\int_0^(\pi/2)\int_0^1r\sin(6r^2)\,\mathrm dr\,\mathrm d\theta=\boxed{(\pi\sin^23)/(864)}$

where you can evaluate the remaining integral by substituting $s=6r^2$ and $\mathrm ds=12r\,\mathrm dr$ .

Final answer:

To evaluate the integral, we make a change of variables using the transformation x=u/8 and y=v/9 to transform the region into a unit circle. Then we convert the integral to polar coordinates and evaluate it.

Explanation:

To evaluate the given integral, we can make the appropriate change of variables by using the transformation x = u/8 and y = v/9. This will transform the region R into a unit circle. The determinant of the Jacobian of the transformation is 1/72, which we will use to change the differential area element from dA to du dv. Substituting the new variables and limits of integration, the integral becomes:

L = \iint_{R} 9 \sin (612 u^{2} + 768 v^{2}) \cdot (1/72) \,du \,dv

Next, we can convert the integral from Cartesian coordinates(u, v) to polar coordinates (r, \theta). The integral can be rewritten as:

L = \int_{0}^{2\pi} \int_{0}^{1} 9 \sin (612 r^{2} \cos^{2}(\theta) + 768 r^{2} \sin^{2}(\theta)) \cdot (1/72) \cdot r \,dr \,d\theta

We can then evaluate this integral to find the value of L.

Learn more about Evaluation of Integrals here:

brainly.com/question/32205191

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Please show you're work! THANKS! Need help asap

Answers

9514 1404 393

Answer:

2a. (x, y) = (2, 2)

2b. (x, y) = (3, -1)

3. -5, 3, y, 5, 1

Step-by-step explanation:

2A.

The first equation defines an expression for x, so it is convenient to use that to substitute for x in the second equation.

2(3y-4) -y = 2 . . . . . substitute for x

6y -8 -y = 2 . . . . . . eliminate parentheses

5y = 10 . . . . . . . . . add 8, collect terms

y = 2 . . . . . . . . . . divide by 5

x = 3(2) -4 = 2 . . . find x using the first equation

The solution is (x, y) = (2, 2).

2B.

Add 3 times the second equation to the first.

(3x +2y) +3(-x +y) = (7) +3(-4)

5y = -5 . . . . . simplify

y = -1 . . . . . . . divide by 5

x = y +4 = -1 +4 = 3 . . . . rearrange the second equation

The solution is (x, y) = (3, -1).

3.

The slope of this equation is -5 [the x-coefficient]. I would start at +3 [the y-intercept] on the y axis and then drop down 5 and run over 1 .

[The slope is the ratio of rise to run. A slope of -5 means the "rise" is a drop of 5 for each "run" of 1 unit to the right.]

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