MATHEMATICS HIGH SCHOOL

Using the laws of indices, simplify the following:-

√h × √h³ =

Answers

Answer 1
Answer: \sqrt h\cdot√(h^3)=\nh^{(1)/(2)}\cdot \left(h^3\right)^{(1)/(2)}=\nh^{(1)/(2)}\cdot h^{(3)/(2)}=\nh^{(1)/(2)+(3)/(2)}=\nh^{(4)/(2)}=\nh^2

or other way

\sqrt h\cdot√(h^3)=\n √(h^4)=\n √((h^2)^2)=\n |h^2|=\n h^2

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What is the domain of the function below?
{0,2 3,1 5,2 8,4

Answers

The choices are the below that can be found elsewhere:

a. { 1, 2, 4 }
b. { 0, 3, 5, 8 }
c. { 0, 1, 2, 3, 4, 5, 8 }
d. { ( 0, 2 ), ( 3, 1 ), ( 5, 2 ), ( 8, 4 ) }

The answer is B because the domain is just the X-values of the ordered pairs and you cant repeat them.

There is a 0.23 probability that a typical convenience store customer buys gasoline. The probability that a customer buys groceries is 0.76 and the conditional probability of buying groceries given that the customer buys gasoline is 0.85.a) Find the probability that a typical customer buys both gasoline and groceries.

Answers

Answer:

The probability that a typical customer buys both gasoline and groceries, P(Ga n Gr) = 0.1955

Step-by-step explanation:

Let the probability that a customer guys groceries be represented by P(Gr) and that of buying gasoline be P(Ga)

Given

P(Gr) = 0.76

P(Ga) = 0.23

P(Gr|Ga) = 0.85

For mutually exclusive events,

P(B|A) = (P(B n A))/P(A)

P(Gr|Ga) = (P(Gr n Ga))/P(Ga)

P(Gr n Ga) = P(Gr|Ga) × P(Ga)

P(Gr n Ga) = 0.85 × 0.23 = 0.1955

Hope this Helps!!!!

Solve a magic square of 3 by 3 squares
numbers are- 20  21  22  23  24  25  26  27  28

Answers

[27]  [20]  [25]
[22]  [24]  [26]
[23]  [28]  [21]

The constant sum is 72.

I need urgent help with this. please write out the working and the answer thank you

Answers

1.         C = ⁵/₉F - 32
          9C = 9(⁵/₉F - 32)
          9C = 9(⁵/₉F) - 9(32)
          9C = 5F - 288
        - 5F  - 5F
  9C - 5F = -288
- 9C           - 9C
         -5F = -9C - 288
          -5           -5
            F = 1⁴/₅C + 57.6

2. H = w + (50)/(m^(2))
    m^(2)(H) = m^(2)((50)/(m^(2)))
    Hm^(2) = 50
    (Hm^(2))/(H) = (50)/(H)
    m^(2) = (50)/(H)
    \sqrt{m^(2)} = \sqrt{(50)/(H)}
    m = (√(50))/(√(H))
    m = (5√(2))/(√(H))
    m = (5√(2))/(√(H)) * (√(H))/(√(H))
    m = (5√(2H))/(H)

3.                    A = 5 + 4√x
                     - 5  - 5
                  A - 5 = 4√x
              (A - 5)² = (4√x)²
    A² - 10A + 25 = 16x
             16             16
¹/₆A² - ⁵/₈A + 1⁹/₁₆ = x

4. A = (b + c)/(b)
    Ab = b((b + c)/(b))
    Ab = b + c
    Ab - b = c
    b(A) - b(1) = c
    b(A - 1) = c
    (b(A - 1))/(A - 1) = (c)/(A - 1)
    b = (c)/(A - 1)

Find the unknown marked angles​

Answers

30° I think.........

Which of the following sets of numbers could be the lengths of the sides of a triangle?a. 2 in., 4 in., 6 in.
b. 2 in., 4 in., 5 in.
c. 2 in., 6 in., 12 in.
d. 2 in., 8 in., 14 in.

Answers

ok
longest side measure must be less than the sum of the other 2 sides
basically
longestside<otherside1+otherside2

a.
longest is 6
6<4+2
6<6
false, cannot

b.
 longest is 5
5<4+2
5<6
true, can be a triangle

c. longest is 12
12<6+2
12<8
false, cannot

d. longest is 14
14<8+2
14<10
false, cannot


B is only possible
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