Answers
Answer:
139.33 g of magnesium chloride, MgCl2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(aq)
Next, we shall determine the mass of Mg that reacted and the mass of MgCl2 from the balanced equation.
This is illustrated below:
Molar mass of Mg = 24 g/mol
Mass of Mg from the balanced equation = 1 x 24 = 24 g
Molar mass of MgCl2 = 24 + (2x35.5) = 95 g/mol
Mass of MgCl2 from the balanced equation = 1 x 95 = 95 g
From the balanced equation above,
24 g of Mg reacted to produce 95 g of MgCl2.
Finally, we shall determine the mass of MgCl2 produced by reacting 35.2 g of Mg.
This can be obtained as follow:
From the balanced equation above,
24 g of Mg reacted to produce 95 g of MgCl2.
Therefore, 35.2 g of Mg will react to produce = (35.2 x 95)/24 = 139.33 g of MgCl2.
From the calculations made above, 139.33 g of magnesium chloride, MgCl2 were produced.
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Answers
Answer:
False
Explanation:
Magnesium is the element of second group and third period. The electronic configuration of magnesium is - 2, 8, 2 or
There are 2 valence electrons of magnesium.
Only the valence electrons are shown by dots in the Lewis structure.
As, stated above, there are only two valence electrons of magnesium, so in the Lewis structure, two dots are made around the magnesium symbol.
Given that the electronic configuration is:- .
Orbital s cannot accommodate 3 electrons and also in magnesium it has . Hence, the statement is false.
Answers
Answer:
3 > 2> 1
Explanation:
Aromatic compounds undergo electrophilic substitution reaction which passes through a positively charged intermediate to yield the product.
Substituted benzenes may be more or less reactive towards electrophilic aromatic substitution than benzene molecule depending on the nature of the substituent.
Certain substituents increase the ease of reaction of benzene towards aromatic substitution.
If we look at the compounds closely, we will notice that toluene reacts readily with CH3Cl / AlCl3. This is because, the methyl group is electron donating hence it stabilizes the positively charged intermediate produced in the reaction.
Carbonyl compounds are electron withdrawing substituents hence they decrease the magnitude of the positive charge and hence decrease the rate of electrophilic aromatic substitution.
Answers
Answer:
a) D = 33.44 Lbmol/h
⇒ B = 62.56 Lbmol/h
b) D = 16.848 Kmol/h
⇒ B = 28.152 Kmol/h
Explanation:
global balance:
- F = D + B........................(1)
∴ F = 100 Lbmol/h
balance per component:
A: 0.4*F = 0.9*D + 0.1*B = 0.4*100 = 40 Lbmol/h..............(2)
B: 0.6*F = 0.1*D + 0.9*B = 0.6*100 = 60 Lbmol/h..............(3)
from (2):
⇒ 0.9*D = 40 - 0.1*B
⇒ D = ( 40 - 0.1*B ) / 0.9............(4)
(4) in (3):
⇒ 0.1*((40-0.1*B)/0.9) + 0.9*B = 60
⇒ B = 62.56 Lbmol/h............(5)
(5) in (1):
⇒ D = 100 - B
⇒ D = 37.44 Lbmol/h
∴ Lbmol = 0.45 Kmol
⇒ B = 62.56 Lbmol/h * ( 0.45 Kmol/ Lbmol ) = 28.152 Kmol/h
⇒ D = 37.44 Lbmol/h * ( 0.45 Kmol/h ) = 16.848 Kmol/h
Answers
Answer:but-1-ene
Explanation:This is an E2 elimination reaction .
Kindly refer the attachment for complete reaction and products.
Sodium tert-butoxide is a bulky base and hence cannot approach the substrate 2-chlorobutane from the more substituted end and hence major product formed here would not be following zaitsev rule of elimination reaction.
Sodium tert-butoxide would approach from the less hindered side that is through the primary centre and hence would lead to the formation of 1-butene .The major product formed in this reaction would be 1-butene .
As the mechanism of the reaction is E-2 so it will be a concerted mechanism and as sodium tert-butoxide will start abstracting the primary hydrogen through the less hindered side simultaneously chlorine will start leaving. As the steric repulsion in this case is less hence the transition state is relatively stabilised and leads to the formation of a kinetic product 1-butene.
Kinetic product are formed when reactions are dependent upon rate and not on thermodynamical stability.
2-butene is more thermodynamically6 stable as compared to 1-butene
The major product formed does not follow the zaitsev rule of forming a more substituted alkene as sodium tert-butoxide cannot approach to abstract the secondary proton due to steric hindrance.
Answers
Answer:
(a) The rate constant is 3.61×10^-3 s^-1
(b) 7.12×10^4 s
Explanation:
(a) Log (K2/K1) = Ea/2.303R × [1/T1 - 1/T2]
K1 = 8.33×10^-6 s^-1
Ea = 245 kJ = 245,000 J
R = 8.314 J/mol.K
T1 = 427°C = 427+273 = 700 K
T2 = 545°C = 546+273 = 818 K
Log (K2/8.33×10^-6) = 245,000/2.303 × [1/700 - 1/818]
Log (K2/8.33×10^-6) = 2.637
K2/8.33×10^-6 = 10^2.637
K2 = 8.33×10^-6 × 433.51 = 3.61×10^-3 s^-1
(b) The relationship between temperature and the time required for reactants to be consumed is inverse
t2 = T1t1/T2
T1 = 427 °C = 700 K
t1 = 8.32×10^4 s
T2 = 545 °C = 818 K
t2 = 700×8.32×10^4/818 = 7.12×10^4 s
Answers
Answer:
The value of Keq is 4e-9. See the solution below
Explanation:
We need to balanced rhe equation and use the formula of the Keq