An isotope contains 26 protons, 24 electrons, and 32 neutrons. What is the identity of the isotope

Answers

Answer 1
Answer:

Answer:

58fe+2

Explanation:

Answer 2
Answer: 26
protons equal identity

Related Questions

Essentially all of the mass of an atom is due to the ______.(A) electrons.(B) neutrons.(C) nucleons.(D) protons.
What is the concentration of hydronium ion ( [H3O+]) in a solution with a PH of _1,3?
What is colloidal solutions ​
Which of the following species is amphoteric? A)HCO32- B) HF O C) NH4+ D) P042-
Write a balanced chemical equation for the standard formation reaction of gaseous dinitrogen tetroxide

When the chemical equation is balanced what is the ratio of the coefficient of Ag(s) to the cofficient of H2O(l)?___Ag(s)+____NO3-(aq)+____H+(aq)→ ___Ag+(aq)+____NO(g)+______H2O(l)a. 1:1b. 2:1c. 3:1d. 3:2

Answers

Answer:

Ag(s):H2O(l)  = 3:2

For 3 moles Ag(s) we'll have 2 moles H2O(l)

Option D is correct

Explanation:

Step 1: Balancing the equation

3 Ag (s) + 4 HNO3 (aq) → 3 AgNO3 (aq) + NO (g) + 2 H2O (l)

3Ag(s)  +  4NO  ^3-  +  4H+  →3Ag+ +3NO3- +  +NO  +  2H2O

3Ag(s)  +  NO  ^3-(aq)  +  4H+(aq)  →3Ag+(aq)  +NO(g)  +  2H2O(l)

Step 2: The ratio between Ag(s) and H2O(l)

Ag(s):H2O(l)  = 3:2

For 3 moles Ag(s) we'll have 2 moles H2O(l)

Option D is correct

Choose the correct statement(s) for the following reaction: 8Fe(s) + S8 (s) → 8 FeS (s) (a) Iron is being oxidized. (b) Iron is being reduced. (c) Sulfur is being oxidized. (d) Sulfur is being reduced

Answers

Answer:

(a) Iron is being oxidized.

(d) Sulfur is being reduced.

Explanation:

Let's consider the following redox reaction.

8 Fe(s) + S₈(s) → 8 FeS(s)

Iron is being oxidized according to the following oxidation half-reaction:

Fe(s) → Fe²⁺(s) + 2 e⁻

Sulfur is being reduced according to the following reduction half-reaction:

S₈(s) + 16 e⁻ → 8 S²⁻(s)

NEED HELP!
C=46.67%, H=4.48%, N=31.10%, O=17.76%.
The molecular weight is 180.16g/mol.

Answers

Answer:

C_7H_8N_4O_2

Explanation:

Hello!

In this case, since the determination of an empirical formula is covered by first computing the moles of each atom as shown below:

n_C=(46.47g)/(12g/mol)=3.9mol\n\n n_H=(4.48g)/(1g/mol) =4.5mol\n\nn_N=(31.10g)/(14g/mol) =2.2mol\n\nn_O=(17.76g)/(16g/mol) =1.1mol

Now, we divide each moles by the fewest moles (those of oxygen), to obtain the subscripts in the empirical formula:

C:(3.9)/(1.1)=3.5 \n\nH:(4.5)/(1.1)=4 \n\nN:(2.2)/(1.1) =2\n\nO:(1.1)/(1.1) =1

Thus, the empirical formula, taken to the nearest whole subscript is:

C_7H_8N_4O_2

Whose molar mass is 180.16, therefore the empirical formula is the same to the molecular one.

Best regards!

Draw a Lewis structure for [H3O]+. Show all unshared pairs and the formal charges, if any.

Answers

Answer: Formal Charges: Hydrogen = 0 and Oxygen = +1

Unshared Pair of electrons: Hydrogen = 0 and Oxygen = 2

Explanation:

The attachment below shows the Lewis structure and the calculations

Which one of the following compounds will NOT be soluble in water? Which one of the following compounds will NOT be soluble in water? LiOH BaSO4 NaNO3 MgCl2 K2S

Answers

Answer:

BaSO_(4) will be not soluble in water

Explanation:

LiOH is a strong base. Hence it gets completely dissociated in aqueous solution.

NaNO_(3) is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

MgCl_(2) is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

K_(2)S is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

BaSO_(4) is a sparingly soluble salt. Hence it is not dissociated and hence dissolved in water. This is due to the fact that both Ba^(2+) and SO_(4)^(2-) ions are similar in size. Hence crystal structure of BaSO_(4) is quite stable. Hence BaSO_(4) is reluctant to undergo any dissociation in aqueous solution.

In which orbitals would the valence electrons for carbon (C) be placed? s orbital and d orbitals s orbital only p orbitals only s orbital and p orbitals

Answers

Answer:

p orbitals only

Explanation:

Carbon has an atomic number of 6 so its electron configuration will be 1s² 2s² 2p². It has two orbitals as indicated with the 2 as its period number with the outer orbital have 4 valence electrons. So carbon is in the p-orbital, period 2 and in group 4.

Final answer:

Carbon's valence electrons reside in the 2s and 2p orbitals. These orbitals hybridize during bond formation to create equivalent sp3 hybrid orbitals, as evidenced in the methane molecule. Carbon's valence electrons are not placed in d orbitals.

Explanation:

Carbon (atomic number 6) has a total of six electrons. Two of these fill the 1s orbital. The next two fill the 2s orbital, and the final two are in the 2p subshell. According to Hund's rule, the most stable configuration for an atom is one with the maximum number of unpaired electrons. Therefore, carbon has two electrons in the 2s subshell and two unpaired electrons in two separate 2p orbitals. When discussing valence electrons, the electrons in the outermost shell are the ones considered, which for carbon are the electrons in the second shell namely 2s and 2p.

The geometry of the methane molecule (CH4) illustrates that in the bonding process, the s and p orbitals hybridize to allow the formation of four equivalent bonds with hydrogen atoms. Without hybridization, we would expect three bonds at right angles (from the p orbitals) and one at a different angle (from the s orbital). Nonetheless, through orbital hybridization, all four bonds in methane are identical, which is explained by the concept of sp3 hybridized orbitals.

Therefore, the valence electrons for carbon would be placed in the s orbital and p orbitals, not in the d orbitals, because carbon does not have electrons in the d subshell in its ground state. Additionally, the s and p orbitals are the only ones involved in bonding for carbon in most of its compounds, such as methane.

Learn more about Orbital Placement of Valence Electrons here:

brainly.com/question/14104411

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