Write a balanced chemical equation for the standard formation reaction of gaseous dinitrogen tetroxide

Answers

Answer 1
Answer:

Answer:

N_2(g)+2O_2(g)\rightarrow N_2O_4(g)

Explanation:

Hello,

In this case, considering the required product which is dinitrogen tetroxide whose molecular formula is N₂O₄, by considering its formation reaction which is starting by both gaseous nitrogen and oxygen as shown below:

N_2(g)+O_2(g)\rightarrow N_2O_4(g)

Nevertheless, it should be balance since four oxygen atoms are present at the right side, thus, we obtain:

N_2(g)+2O_2(g)\rightarrow N_2O_4(g)

Best regards.


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Which of the following shows the abbreviation for an SI unit of density?

Is 3.5:Aqueous solutions of iron(III) bromide and ammonium carbonate react to form a precipitate. Answer the follwing
questions with regards to this reaction.
a) Write the molecular equation for this reaction by
Translating the two reactants into their chemical formulae.
Predict the products.
Label all the states.
Balance the reaction.

Answers

Answer:

2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)

Explanation:

Aqueous solutions of iron(III) bromide and ammonium carbonate react. This is a double displacement reaction that gives place to ammonium bromide and iron (III) carbonate. Iron (III) carbonate is insoluble so it precipitates. The corresponding molecular equation is:

2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)

A compound contains only carbon, hydrogen, and oxygen. Combustion of 139.1 g of the compound yields 208.6 g of CO2 and 56.93 g of H2O. The molar mass of the compound is 176.1 g/mol. *Each part of this problem should be submitted separately to avoid losing your work* 1. Calculate the grams of carbon (C) in 139.1 g of the compound: grams 2. Calculate the grams of hydrogen (H) in 139.1 g of the compound. grams 3. Calculate the grams of oxygen (O) in 139.1 g of the compound. grams

Answers

Answer:

1. Mass of Carbon is 56.89g

2. Mass of Hydrogen is 6.33g

3. Mass of Oxygen is 75.88

Explanation:

The following were obtained from the question.

Mass of the compound = 139.1g

Mass of CO2 produced = 208.6g

Mass of H2O produced = 56.93

1. Determination of mass of Carbon (C). This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 208.6

Mass of C = 56.89g

2. Determination of the mass of Hydrogen (H). This is illustrated below:

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H = 2/18 x 56.93

Mass of H = 6.33g

3. Determination of the mass of oxygen (O).

This is illustrated below:

Mass of the compound = 139.1g

Mass of C = 56.89g

Mass of H = 6.33g

Mass of O = Mass of compound - (mass of C + Mass of H)

Mass of O = 139.1 - (56.89 + 6.33)

Mass of O = 139.1 - 63.22

Mass of O = 75.88

The diameter of an atom is approximately 1 * 10 ^ - 10 * m . What is the diameter in decimeters?

Answers

Answer:

d=1x10^(-9)dm

Explanation:

Hello,

In this case, considering that 1 m equals 10 dm, the required diameter of the atom in decimetres is:

d=1x10^(-10)m*(10dm)/(1m) \n\nd=1x10^(-9)dm

Best regards.

Final answer:

The diameter of an atom is approximately 1 * 10^-10 * m, which translates to 1 * 10^-11 decimeters by multiplying the meter measurement by 10.

Explanation:

The subject of this question is a unit conversion. We are trying to convert the diameter of an atom from meters to decimeters.

The process is as follows:

  • First, we need to understand that 1 meter equals 10 decimeters because the prefix 'deci-' means one-tenth.
  • So, if the diameter of an atom is approximately 1 * 10^-10 * m, then in decimeters the diameter would be 1 * 10^-11 * dm

In essence, to convert meters to decimeters, we need to multiply the meter measurement by 10. But because the meter measurement of the atom is in the power of -10, the decimeter equivalent would be in the power of -11.

Learn more about Unit Conversion here:

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The activiation energy required for a chemical reaction can be decreased by? A) increasing the surface area of the reactant.
B) increasing the temperature of the reactant.
C) adding a catalyst to the reaction.
D)adding more reactant​

Answers

Answer:

C)

Explanation:

C) adding a catalyst to the reaction.

The ratio of oxygen-16 and oxygen-18 isotopes in plankton fossils in deep-sea sediments can be used to determine ________.

Answers

The ratio of oxygen-16 and oxygen-18 isotopes in plankton fossils in deep-sea sediments can be used to determine past temperatures.

Answer;

-past temperatures

The ratio of oxygen-16 and oxygen-18 isotopes in plankton fossils in deep-sea sediments can be used to determine past temperatures.

Explanation;

-O-16 will evaporate more readily than O-18 since it is lighter, therefore; during a warm period, the relative amount of O-18 will increase in the ocean waters since more of the O-16 is evaporating.

-Hence, looking at the ratio of O16 to O18 in the past can give clues about global temperatures.

Could someone pls help me :)

Answers

liquid 1 and 2 have the same color and mass so the answer would be liquid 1 and 2

Explanation:

hope this is helpful