Draw a line-bond structure for CBrN. Explicitly draw all H atoms. You do not have to include lone pairs in your answer. In cases where there is more than one answer, just draw one.

Answers

Answer 1

Answer:

Answer:

Br - C ≡ N

Explanation:

To draw the Lewis line-bond structure we need to bear in mind the octet rule, which states that in order to gain stability each atom tends to share electrons until it has 8 electrons in its valence shell.

C has 4 e⁻ in its valence shell so it will form 4 covalent bonds.

Br has 7 e⁻ in its valence shell so it will form 1 covalent bond.

N has 5 e⁻ in its valence shell so it will form 3 covalent bonds.

The most stable structure that respects these premises is:

Br - C ≡ N

It does not have any H atom.

Related Questions

The half-life of a pesticide determines its persistence in the environment. A common pesticide degrades in a first-order process with a rate constant of 6.5 1/hours. What is the half-life in hours of the breakdown reaction? Enter to 4 decimal places.
Which of the following statements about moles is FALSE?SELECT AN ANSWEROne mole of carbon would contain 6.02 x 1023 carbon atoms, but one mole of chlorine would contain 6.02 x 1023 diatomic chlorine molecules.For ionic compounds, the representative particle is the formula unit of the compound (eg. NaCl).One mole of water (H2O) contains 6.02 x 1023 atoms.Avogadro's number is the number of discrete, representative units found in one mole of a substance.
What mass of CO2 (in kilograms) does the combustion of a 16-gallon tank of gasoline release into the atmosphere? Assume the gasoline is pure octane (C8H18) and that it has a density of 0.70 g/mL.Express your answer in kilograms to two significant figures.
Iron has density of 7.9g/cm3. What is the mass of a cube with the length of one side equal to 1.64x10squared cm3?
A generic solid, X, has a molar mass of 78.2 g/mol. In a constant-pressure calorimeter, 12.6 g of X is dissolved in 337 g of water at 23.00 °C.X(s) yeilds X(aq)The temperature of the resulting solution rises to 24.40 °C. Assume the solution has the same specific heat as water, 4.184 J/(g·°C), and that there\'s negligible heat loss to the surroundings. How much heat was absorbed by the solution?What is the enthalpy of the reaction?

Which best describes a codon?

Answers

Answer:

The Correct answer is C

Explanation:

The sequence of three bases which codes for a specified amino acid.

Answer:

Which best describes a codon? 1. a cell structure that gives the master instructions for an organism 2. a segment of DNA that is the basis of heredity in organisms 3. the sequence of three bases that codes for a specific amino acid 4. the basic unit of structure and function of all living things

The steps in a reaction mechanism are as follows. Which species is acting as a catalyst? Step 1: Ag+(aq) + Ce4+(aq) <-----> Ag2+(aq) + Ce3+(aq) Step 2: Tl+(aq) + Ag2+(aq) -----> Tl2+(aq) + Ag+(aq) Step 3: Tl2+(aq) + Ce4+(aq) -----> Tl3+(aq) + Ce3+(aq)

Answers

The specie which is acting as a catalyst is; Ag+(aq).

Discussion:

The catalyst is a specie that exists in the same form at the beginning and end of the reaction.

The reaction's mechanism is as follows;

Step 1: Ag+(aq) + Ce⁴+(aq) <-----> Ag²+(aq) + Ce³+(aq)

Step 2: Tl+(aq) + Ag²+(aq) -----> Tl²+(aq) + Ag+(aq)

Step 3: Tl²+(aq) + Ce⁴+(aq) -----> Tl³+(aq) + Ce³+(aq)

Evidently, although Ag+(aq) was converted to Ag²+(aq) in Step 1 of the reaction; the Ag²+(aq) is reverted back to Ag+(aq) in Step 2 of the reaction.

brainly.com/question/22498090

Answer:

Ag⁺ acts as the catalyst.

Explanation:

Hello,

In this case, each step is reorganized:

- Step 1:

$Ag^+(aq) + Ce^(4+)(aq) \rightleftharpoons Ag^(2+)(aq) + Ce^(3+)(aq)$

- Step 2:

$Tl^+(aq) + Ag^(2+)(aq) \rightarrow Tl^(2+)(aq) + Ag^+(aq)$

- Step 3:

$Tl^(2+)(aq) + Ce^(4+)(aq) \longrightarrow Tl^(3+)(aq) + Ce^(3+)(aq)$

In such a way, Ag⁺ is converted to Ag²⁺ in the first step, but then it is regenerated to simple Ag⁺, therefore, Ag⁺ acts as the catalyst.

Best regards.

The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentration of 0.086 M, calculate the concentration of NOBr after 22 s. (b) Calculate the half-lives when [NOBr]0 5 0.072 M and [NOBr]0 5 0.054 M.

Answers

Explanation:

2NOBr(g) --> 2NO(g) 1 Br2(g)

Rate constant, k = 0.80

a) Initial concentration, Ao = 0.086 M

Final Concentration, A = ?

time = 22s

These parameters are connected with the equation given below;

1 / [A] = kt + 1 / [A]o

1 / [A] = 1 / 0.086 + (0.8 * 22)

1 / [A] = 11.628 + 17.6

1 / [A] = 29.228

[A] = 0.0342M

b) t1/2 = 1 / ([A]o * k)

when [NOBr]0 5 0.072 M

t1/2 = 1 / (0.072 * 0.80)

t1/2 = 1 / 0.0576 = 17.36 s

when [NOBr]0 5 0.054 M

t1/2 = 1 / (0.054 * 0.80)

t1/2 = 1 / 0.0432 = 23.15 s

Answer:

(a)

$0.0342M$

(b)

$t_(1/2)=17.36s\nt_(1/2)=23.15s$

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

$(1)/([NOBr])=kt +(1)/([NOBr]_0)\n(1)/([NOBr])=(0.8)/(M*s)*22s+(1)/(0.086M)=(29.3)/(M)\n$

$[NOBr]=(1)/(29.2/M)=0.0342M$

(b) Now, for a second-order reaction, the half-life is computed as shown below:

$t_(1/2)=(1)/(k[NOBr]_0)$

Therefore, for the given initial concentrations one obtains:

$t_(1/2)=(1)/((0.80)/(M*s)*0.072M)=17.36s\nt_(1/2)=(1)/((0.80)/(M*s)*0.054M)=23.15s$

Best regards.

When radioactive uranium decays to produce thorium, it also emits a particle. As seen in the balanced nuclear equation, this particle can BEST be described asA) a helium atom.
B) an alpha particle or a helium atom.
C) a beta particle or a hydrogen nucleus.
D) an alpha particle or a helium nucleus.

Answers

The radioactive uranium decays to produce thorium and it emits an alpha particle or helium atom. Thus, option A is correct.

What is radioactive decay?

Unstable heavy isotopes of elements undergo nuclear decay to produce stable atoms by the emission of charged particle such as alpha or beta particles.

Based on the emitted particle, there are two types of decay process namely alpha decay and beta decay. In alpha decay atoms emits alpha particles which are helium nuclei and the atom losses its mass number by 4 units and atomic number by two units,

In beta decay, electrons are emitted by the atom, where no change occurs in mass number and atomic number increases by one unit. Uranium undergo alpha decay by emitting alpha particle or helium nuclei.

To find more on alpha decay, refer here:

brainly.com/question/27870937

#SPJ6

You’re answer would be D love!

The salinity of sea water represents the amount of NaCl (salt) dissolved in the water.True
False

Answers

True because the sea water is mostly salt

16. Which of the following properties of the elements remain unchanged across#period
A lonivation energy
C Electro negativity
13. Number of shells
D. Nuclear charge

Answers

Answer:

Number of shells

Explanation:

Across the period on the periodic table, the number of shells remains the same. There is no variation or trend for the number of shells on a period.

The number of shell is the energy level corresponding to an atom.
As we go from period to period, the energy level increases by 1.
The period number corresponds to the number of shells.
Elements in period 4 will have 4 shells.
There is no variation of any sort in the number of shell across a period.

Other Questions

Classify each of the following as a compound, a homogeneous mixture, or a heterogeneous mixture: (a) orange juice; (b) vegetable soup; (c) cement; (d) calcium sulfate; (e) teas

WORTH A LOT OF POINTS! just copy what on the picture for notes so i can copy and paste i do not feel like writing all of that down

Some people argue that a policy of putting out wildfires is having a negative long-term effect on the number and strength of wildfires. Suggest why this could be the case.

How to atoms share more than one pair of electrons?