Answers
Answer:
The reason for this is that putting out the fires only postpones the fire outbreak to a later date, and there is the fear of the fire outbreak being more sever when it actually comes.
When wildfires burn, they clean up the forest off dead trees and falling logs. Also dried leaves and twigs and unnecessarily dense vegetation is cleared up by the fire. These materials are the main fuel of these wildfires. Putting out these fires, especially those that start naturally means that these fuel that should be cleaned up are allowed to accumulate so that when the fire actually happens, it does so with an unnatural intensity. Also, when fire burns, the ashes that are left act as nutrition for the forest, and the forest is allowed to regrow; reborn from the ashes. The only cases that might need human intervention is when the fire is human caused or due to human activities. Natural causes of fire can be due to a very high temperature, lightning striking a tree, etc.
Related Questions
Chem help due in 2 hours. please help. problem 14.
A buffer solution contains 0.11 mol of acetic acid and 0.13 mol of sodium acetate in 1.00 L. What is the pH of this buffer?What is the pH of the buffer after the addition of 2?
5.0 liters of a gas are at an initial pressure of 5.0 atmospheres. If the temperature and amount of a gas are kept constant, what is the new volume of the gas when pressure is increased to 7.0 atmospheres?
Which of the following is an example of a compound? water - H2Ooxygen-O2 hydrogen - H2 helium - He
B.) Kinetic energy decreases during exothermic changes and increases during endothermic changes.
C.) Kinetic energy does not change, but the potential energy does.
D.) Kinetic energy changes in the opposite way that the potential energy changes.
Answers
Answer:
C
Explanation:
Answer: A. Kinetic energy increases during exothermic changes and decreases during endothermic changes
Explanation: During an exothermic change potential energy is converted to kinetic energy. I hope this is correct. :)
Answers
Answer:
1 litre of 1.0 M NaCl
Explanation:
When an ionic compound dissolves in water, it dissociates into ions. Consider the dissolution of sodium chloride in water;
NaCl(s) ------> Na^+(aq) + Cl^-(aq)
Hence, two solute particles are obtained from each formula unit of NaCl, a greater concentration of NaCl will contain a greater number of sodium an chloride ion particles.
Glucose is a molecular substance and does not dissociate in solution hence it yields a lesser number of particles in solution even at the same concentration as NaCl
Final answer:
The solution with the greatest number of solute particles is 1 litre of 1.0 M NaCl, as ionic compounds dissociate into individual ions, thus providing more particles per litre.
Explanation:
Given the details of the question, the solution that would be expected to contain the greatest number of solute particles would be 1 litre of 1.0 M NaCl. This is because when ionic compounds like sodium chloride are placed in water, they dissociate into individual ions. In the case of NaCl, it splits into two ions, sodium (Na+) and chloride (Cl-). Thus, a 1.0 M solution of NaCl would actually contain 2.0 moles of particles per litre because each formula unit of NaCl gives two particles. Covalently bonded molecules like glucose do not dissociate in solution, therefore, a 1.0 M glucose solution would have 1.0 mole of particles per litre.
Learn more about Solute Particles in Solutions here:
#SPJ3
Answers
Answers
Answer:
Mass of CO2 produced = 944.43 -lb/year
Since 944.43 -lb is close to 1000 -lb, it is a reasonable statement.
Explanation:
Assumptions:
Car mileage = 20 miles/gallon:
Density of gasoline = 0.702 g/ml
Volume of gallons per week = (20 miles/week) / (20 miles/gallon) = 1 gallon/week
Volume of gasoline per year = 52 weeks * 1 gallon/week = 52 gallons
1 gallon = 3.8 litres or 3800 ml
52 gallons = 52 * 3800 = 197600 ml
Mass of gasoline = volume *density
Mass of gasoline = 197600 ml * 0.702 g/ml
Mass of gasoline = 138715.2 g
Equation of reaction:
2C8H18 + 25O2 ---> 16CO2 + 18H2O
2 moles of octane produces 16 moles of CO2
Molar mass of octane = 114 g/mol; molar mass of CO2 = 44 g/mol
114 * 2 g of octane = 44 * 16 g of CO2
138715. 2 g of octane produces = (138715.2 * 44 * 16) / 114 * 2 of CO2
Mass of CO2 produced = 428313.6 g of CO2 = 428.3136 Kg
Mass of CO2 produced in -lb weight = 428.3136 * 2.205
Mass of CO2 produced per year = 944.43 -lb CO2
Since 944.43-lb is close to 1000 -lb, therefore, it is a reasonable statement.
5.83
B.
3.67
C.
2.08
D.
1.66
Answers
Answer:
B) pH = 3.67
Explanation:
How many grams in one mole of B2?
__g
Answers
Final answer:
The number of grams in one mole of B2 can be calculated using the atomic mass of element B. This is found on the periodic table and then doubled for B2 since it's diatomic. If B is Oxygen for instance, 1 mole of B2 (O2) weighs 32 grams.
Explanation:
To find the number of grams in one mole of B2, we need to know the atomic mass of element B, which isn't provided in your question. However, you can find this information on the periodic table. Once you have the atomic mass of B, you can calculate the molar mass of B2 (which is two times the atomic mass of B) since 1 mole of a substance corresponds to its molar mass in grams.
For example, if element B is Oxygen (O), its atomic mass is approximately 16 g/mol. Therefore, the molar mass of B2 (O2 in this case) would be 32 g/mol. Hence, 1 mole of B2 (or O2) would weigh 32 grams.
Learn more about Molar Mass here:
#SPJ12