Chem help due in 2 hours. please help. problem 14.
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Answer 1
Answer: 14 )

a) 1 HBr + 1 NaHCO = 1 CO + 1 HO + 1 NaBr

b) 
2 HNO + 1 K₂SO₃ = 1 HO + 2 KNO + 1 SO

c) 2 HI + 1 Na₂S = 1 H₂S + 2 NaI

d) 1 
(NH)SO + 1 Ca(OH) = 1 CaSO + 2 HO + 2 NH

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The periodic table displaysOA. all of the known elements that exist in the world today.
OB. only the important elements that exist in the world.
OC. only the important compounds that exist in the world.

Answers

OA. all the known elements that exist in the world today.

assume in a different experiment, you prepare a mixture containing 10.0 M FeSCN2+, 1.0 M H+, 0.1 MFe3+ and 0.1 M HSCN. Is the initial mixture at equilibrium? If not, in what direction must the reactionproceed to reach equilibrium? (Hint: You will need to use the value of Kc you determined in the lab

Answers

Answer:

The mixture is not in equilibrium, the reaction will shift to the left.

Explanation:

Based on the equilibrium:

Fe³⁺+ HSCN ⇄ FeSCN²⁺ + H⁺

kc = 30 = [FeSCN²⁺] [H⁺] / [Fe³⁺] [HSCN]

Where [] are concentrations at equilibrium. The reaction is in equilibrium when  the ratio of concentrations = kc

Q is the same expression than kc but with [] that are not in equilibrium

Replacing:

Q = [10.0M] [1.0M] / [0.1M] [0.1M]

Q = 1000

As Q > kc, the reaction will shift to the left in order to produce Fe³⁺ and HSCN untill Q = Kc

Final answer:

The mixture's equilibrium status can be determined by comparing the reaction quotient (Q) with the equilibrium constant (Kc). If Q < Kc, the reaction proceeds to the right (products) to achieve equilibrium. If Q > Kc, the reaction proceeds to the left (reactants) to achieve equilibrium.

Explanation:

To determine if the mixture is initially at equilibrium, we need to calculate and compare the reaction quotient (Q) and the equilibrium constant (Kc) of the reaction. The reaction quotient is a measure of the relative concentrations of products and reactants at any point in time, whereas Kc, is the measure of these concentrations only at equilibrium.

Assuming that the reaction in question is: Fe3+ + HSCN ↔ FeSCN2+ + H + . In this case,

Q = [FeSCN2+]/[Fe3+][HSCN] = 10 / (0.1 * 0.1) = 1000. If Kc is less than 1000, the reaction is not at equilibrium and will need to proceed to the left (reactants) to reach equilibrium. Conversely, if Kc is greater than 1000, the reaction is not at equilibrium and will need to proceed to the right (products).

Learn more about Chemical Equilibrium here:

brainly.com/question/32227445

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When a chemical reaction occurs blank happens

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Answer:

In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Explanation:

In an attempt to prepare n−propylbenzene, a chemist alkylated benzene with 1−chloropropane and aluminum chloride. However, two isomeric hydrocarbons were obtained in a ratio of 2:1, the desired n−propylbenzene being the minor component. What do you think was the major product? How did it arise?

Answers

Answer:

2-Phenylpropane (Cumene)

Explanation:

Famous Friedel Craft Alkylation.

Aluminum Chloride grasped the 1-chloropropane forming an intermediate product composed of Aluminum tetrachloride and n-propylcation. It is well understood that primary carbocations are unstable and therefore undergo hydrogen shifting to attain stability. n-Propylcarbocation undergone hydrogen shifting, forming isopropylcarbocation which reacted with benzene forming 2-Phenylpropane as the major product and HCl as a byproduct.

AlCl3 + CH3CH2CH2Cl --> AlCl4-   +   CH3CH2CH2+

CH3CH2CH2+  ---> CH3CH(+)CH3

C6H6 + CH3CH(+)CH3 ---> C6H5CH(CH3)2   + H+

AlCl4- + H+ ---> HCl + AlCl3

Answer:

From the given problem statement,he was attempting to prepare n−propylbenzene by alkylation benzene with 1−chloropropane and aluminum chloride,but 1-propyle benze was a major product in result.

A mixture contains N a H C O 3 together with unreactive components. A 1.68 g sample of the mixture reacts with H A to produce 0.561 g of C O 2 . What is the percent by mass of N a H C O 3 in the original mixture

Answers

There is 65% of NaHCO3 in the sample.

The equation of the reaction is;

HA + NaHCO3 -----> NaA + CO2 + H2O

Amount of CO2 formed = mass/molar mass

mass of CO2 = 0.561 g/44 g/mol = 0.013 moles

From the balanced reaction equation;

1 mole of NaHCO3 yields 1 mole of CO2

0.013 moles of Na2CO3 yields 0.013 moles of CO2

Hence, mass of NaHCO3 in the sample = 0.013 moles × 84 g/mol = 1.092 g of NaHCO3

Percentage by mass of NaHCO3 = 1.092 g/1.68 g ×100/1

= 65%

Learn more: brainly.com/question/25150590

Answer:

63.75%.

Explanation:

The first step here is to write out the reaction showing the chemical reaction between the two chemical species. Thus, we have;

HA(aq) + NaHCO3 --------------> CO2(g) + H20(l) + NaA(aq).

Therefore, the mole ratio is 1 : 1 : 1 : 1 that is go say one mole of HA reacted with one mole of NaHCO3 to give one mole of CO2 and one .ole of NaA.

Hence, the number of moles of CO2 = mass/molar mass = 0.561/44 = 0.01275 moles.

Thus, the number of moles of NaHCO3 = number of moles of CO2 = 0.01275 moles.

Therefore, we have ( 0.01275 moles × 84 g/mol) grams = 1.071 g NaHCO3 in the mixture.

Therefore, the percent by mass of N a H C O 3 in the original mixture = 1.071/1.68 × 100 = 63.75%.

What is the difference between solid, liquid and ice? Use ice, water and steam as examples.

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Answer: A solid is something that can hold its own shape and is hard to compress (squash). However, ice is different from most solids because its molecules are less densely packed than in liquid water so ice takes up a little more space than the same amount of liquid water. This is why ice floats.

Explanation: Hope it works!!!!!

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