If the enthalpy change of a reaction in a flask is δh = +67 kj, what can be said about the reaction?

Answers

Answer 1
Answer: Answer : Normally in any chemical reaction, if the enthalpy change i.e. ΔH is positive which means it is greater than zero then it can be called as an Endothermic Reaction.

Whereas, the system under study is absorbing heat that is produced during the reaction. So if  ΔH  is found to be positive then it can be called as endothermic reaction.
Answer 2
Answer:

The enthalpy change of the reaction indicates that it is an endothermic process.

FURTHER EXPLANATION

Enthalpy (ΔH) is the amount of heat absorbed or released in a reaction. It is based on the amount of energy needed to break the bonds and the energy released during bond formation. Enthalpy change is the difference in the enthalpy of the reactants and the products. The positive or negative sign for an enthalpy value indicates the direction of the heat flow: a positive ΔH indicates that the reaction is endothermic while a negative value for ΔH means that the reaction is exothermic.

Endothermic Reactions

Endothermic reactions are reactions that absorb heat from the surroundings to the system. This is the case when more energy is absorbed to break the bonds than is released to form the bonds. Endothermic reactions can be identified in the lab by observing if the reaction vessel becomes cooler as the reaction proceeds.

Exothermic Reactions

When the amount of energy released during bond formation is greater than the amount of energy absorbed during bond breaking, a net release of energy to the surroundings takes place and the reaction is exothermic. Exothermic reactions can be identified when the reaction vessel becomes hot as the reaction progresses.

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Keywords: Endothermic, Exothermic, Enthalpy


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How many atoms does 6H2O contain

Answers

Answer:

two atoms of oxygen. For H2O, there is one atom of oxygen and two atoms of hydrogen.

Which of the following acids (listed with pKa values) and their conjugate base would form a buffer with a pH of 8.10?(A) HC7H5O2, pKa = 4.19
(B) HF, pKa = 3.46
(C) HClO, pKa = 7.54
(D) HCN, pKa = 9.31
(E) HClO2, pKa = 1.96

Answers

Answer:

The buffer of pH 8.10 will be formed by the HClO having pKa value of 7.54.

Explanation:

Buffer is defined as the substance that can withstand the changes in the solution due to addition of acid or base. Buffer acts to neutralize the small amounts of acids or base when added.

Buffer is composed of two parts:

A weak acid and its conjugate base and a weak base with its conjugate acid.

According to the Bronsted-Lowry theory,acids are the substances that release \text {H^(2) }\text H^(+) , whereas the substances that accept bases.

Similarly, when an acid loses a proton (\text H^(+))\text {H^(2) }\text {H^(+) }, it is converted into the conjugate base, such that the conjugate acid-base pair of HClO is \text {H}^(+)/\text{ClO}^(-).

The buffer range for a substance is either one unit more or one unit less than the pKa value of the given substance. Thus, to obtain the pH value of 8.10, the acid with pKa value of 7.54 will be selected. The pH range of \text {H}^(+)/\text{ClO}^(-)will have the buffer range between 6.54 and 8.54. Thus, pH of 8.10 will be formed by

Hence, rest of the options are incorrect because the buffer range for given acids will not be close the given value of pH as 8.10.

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Answer:

(C) HClO, pKa = 7.54

Explanation:

A buffer is a solution that can resist abrupt changes in pH when acids or bases are added. It is formed by two components:

  • A weak acid and its conjugate base.
  • A weak base and its conjugateacid.

In this case, acid and base are defined according to Bronsted-Löwry theory, which states that acids are substances that release H⁺ and bases are substances that accept H⁺. Therefore, when an acid loses an H⁺ transforms into its conjugated base. For example, HF/F⁻ is a conjugate acid-base pair.

In buffers, when an acid is added, it reacts with the base to diminish its amount:

F⁻ + H⁺ ⇄ HF

Also in buffers, when a base is added, it reacts with the acid to diminish its amount:

HF + OH⁻ = F⁻ + H₂O

The optimum pH range of work of a buffer system (known as buffer range) is between 1 unit less and 1 unit more of pH than its pKa.

So, the buffer formed by HClO/ClO⁻ works optimally in the pH range 6.54-8.54. Since pH = 8.10 is in that interval, this would be the optimal choice.

Calculate the moles of benzoic acid (C6H5COOH) in a 55.66 g sample of benzoic acid

Answers

Molar mass of Benzoic Acid =122.1gmol
−1
Morality of Ba(OH)
2=0.120mol/L2E6H5COOH+Ba(OH) 2→2H2+Ba(C6​H5COO) 2
​From the given Molar mass, we find the number of moles of Benzoic acid and Barium
hydrocide.
Moles of Benzoic acid = MolarMass
GivenMass​= 122.10.2=0.00163 Moles
Moles of Ba(OH) 2= 20.00163=0.000815
Now, Morality of Ba(OH)
2= LitreofSolutionmolesofsolute=0.120M is required 1 Litre,
So 0.000815M is required in
0.1201 ×0.000815 =0.00679=6.

Compare and contrast the characteristics of metals and nonmetals.

Answers

metals are hard and no metals are liquid

4. Oxygenating myoglobin. The myoglobin content of some human muscles is about 8 g kg 1. In sperm whale, the myoglobin content of muscle is about 80 g kg 1 . (a) How much O 2 is bound to myoglobin in human muscle and in sperm whale muscle? Assume that the myoglobin is saturated with O 2, and that the molecular weights of human and sperm whale myoglobin are the same. Berg, Jeremy M.. Biochemistry (p. 213). W. H. Freeman. Kindle Edition.

Answers

Answer:

0.01454 grams of oxygen is present per kilogram of human muscle.

0.1454 grams of oxygen is present per kilogram of sperm whale muscle.

Explanation:

Given : The myoglobin is fully saturated with oxygen gas.

Moles of myoglobin = Moles of oxygen gas

Molecular mass of myoglobin = 17,600 g/mol

(assumed same fro whale and human )

Myoglobin content in humans = 8 g/kg

Mole of molyoglobin in human muscles per kg :(8 g/kg)/(17,600 g/mol)

Mass of oxygen present in per kg of human muscle:

Moles of oxygen gas × 32g/mol :

(8 g/kg)/(17,600 g/mol)* 32 g/mol=0.01454 g/kg of human muscle

Myoglobin content in whales= 80 g/kg

Mole of molyoglobin in whale muscles per kg :(80 g/kg)/(17,600 g/mol)

Moles of myoglobin = Moles of oxygen gas

Mass of oxygen present in per kg of sperm whale muscle:

Moles of oxygen gas × 32g/mol :

(80 g/kg)/(17,600 g/mol)* 32 g/mol=0.1454 g/kg of whale muscle

Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you the substance is a pure substance or a mixture, if you can. • Sample A is a solid yellow cube with a total mass of 50.0 g. The cube is put into a beaker filled with 250. mL of water. The cube collapses into a small pile of orange powder at the bottom of the beaker. When this powder is filtered out, dried and weighed, it has a total mass of 29.9 g. If the experiment is repeated with 500. mL of water, the powder that's left over has a mass of 10.0 g. Sample B is 100. g of a coarse grey powder with a faint unpleasant smell. 15. mg of the powder are put into a very thin tube and heated. The powder begins melting at 66.2 °C.The temperature stays constant as the powder slowly melts. After the last of the powder melts, the temperature starts to rise again, eventually reaching 76.0 °C. O pure substance Is sample A made from a pure substance or a mixture? x ? mixture If the description of the substance and the outcome of the experiment isn't enough to decide, choose "can't decide. (can't decide) O pure substance Is sample B made from a pure substance or a mixture? If the description of the substance and the outcome of bstance and the outcome of the experiment isn't enough to decide, choose "can't decide." mixture (can't decide)

Answers

Answer and Explanation: Sample A is a mixture. Solubility is characteristics of each substance, which means a substance can be distinguished from other substances and can be useful to separate mixtures.

In Sample A, when is added different volumes of water, the resulting powder has different mass. This means there are more than one substance forming the yellow cube. Therefore, sample A is a mixture.

Sample B is a puresubstance. Each substance has its own melting point. Whe na pure substance reaches its melting point, temperature is constant until all of that substance is melted. In sample B, temperature is stable at 66.2°C and then, after all the powder is melted, it rises again. Therefore, sample B is a pure substance.

Final answer:

Sample A is a mixture based on the experiment result, while the nature of Sample B is inconclusive.

Explanation:

The result of the experiment with sample A indicates that it is a mixture. When the solid yellow cube is put into water, it collapses into a small pile of orange powder. The mass of the powder that is left over depends on the amount of water used. This suggests that the cube is composed of different substances that can be separated by filtration.

On the other hand, the result of the experiment with sample B is inconclusive, so we can't decide whether it is a pure substance or a mixture. Heating the coarse grey powder causes it to melt at a constant temperature, but there is a temperature increase after the last of the powder melts. This could indicate that the powder is a pure substance with a melting point range, or it could suggest the presence of impurities.

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