CHEMISTRY COLLEGE

What is an acronym for the rainbow colors?I just want to know if anybody else knows this.

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Answer 1

Answer:

Answer:

ROYGBIV or Roy G

Explanation:

Thanks for the points!

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Describe the classification of the R group OF AMINO ACID GIVE THE THE EXAMPLES OF EACH CLASS

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nonpolar amino acids: glycine, alanine, valine, leucine, isoleucine
polar amino acids: serine, threonine, cysteine, asparagine, glutamine
positively charged (basic) amino acids: lysine, arginine, histidine
negatively charged (acidic) amino acids: aspartic acid, glutamic acid

Is my answer right? How many millilitres of 1.33 mol L−1 H2SO4(aq) are required to completely neutralize 49.3 mL of 0.830 mol L−1 KOH(aq) ?

I got 15.4 once and now I got 61.4? Are they correct? if so, which one?

Answers

Final answer:

To neutralize the KOH solution, we need 61.4 mL of 1.33 mol L−1 H2SO4(aq).

Explanation:

To find the volume of the H2SO4 solution needed to neutralize the KOH solution, we can use the equation:

Mole of H2SO4 = Molarity of KOH x Volume of KOH

First, calculate the moles of KOH:
Moles of KOH = Molarity of KOH x Volume of KOH = 0.830 mol/L x (49.3 mL / 1000 mL) = 0.04089 mol

Since H2SO4 is a diprotic acid and KOH is a strong base, the reaction will be:
H2SO4 + 2 KOH -> K2SO4 + 2 H2O

Therefore, the ratio between the moles of H2SO4 and KOH is 1:2. This means that twice the moles of KOH will be needed to neutralize the H2SO4. Calculate the moles of H2SO4 needed:
Moles of H2SO4 needed = 2 x Moles of KOH

= 2 x 0.04089 mol

= 0.08178 mol

Finally, calculate the volume of the H2SO4 solution needed:
Volume of H2SO4 = Moles of H2SO4 / Molarity of H2SO4 = 0.08178 mol / 1.33 mol/L

= 0.0614 L

= 61.4 mL

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Use molecular orbital theory to determine whether f22+ is paramagnetic or diamagnetic.

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We have to know whether F₂²⁺ is paramagnetic or diamagnetic.

F₂²⁺ is paramagnetic.

If number of unpaired electron in any species is equal to zero, the species is diamagnetic and the species contains unpaired electrons, then the species is paramagnetic.

The magnetic property can be explained using molecular orbital theory.

Total number of electron present in F₂²⁺ is equal to 16 (i.e, 9+9-2). From the molecular orbital electronic configuration, number of electrons present in pi orbitals present is equal to 2.

So, F₂²⁺ is paramagnetic.

Answer : $F_2^(2+)$ is paramagnetic.

Explanation :

According to the molecular orbital theory, the general molecular orbital configuration will be,

$(\sigma_(1s)),(\sigma_(1s)^*),(\sigma_(2s)),(\sigma_(2s)^*),[(\pi_(2p_x))=(\pi_(2p_y))],(\sigma_(2p_z)),[(\pi_(2p_x)^*)=(\pi_(2p_y)^*)],(\sigma_(2p_z)^*)$

As there are 9 electrons present in fluorine.

The number of electrons present in $F_2^(2+)$ molecule = 2(9) - 2 = 16

The molecular orbital configuration of $F_2^(2+)$ molecule will be,

$(\sigma_(1s))^2,(\sigma_(1s)^*)^2,(\sigma_(2s))^2,(\sigma_(2s)^*)^2,(\sigma_(2p_z))^2,[(\pi_(2p_x))^2=(\pi_(2p_y))^2],[(\pi_(2p_x)^*)^1=(\pi_(2p_y)^*)^1],(\sigma_(2p_z)^*)^0$

Paramagnetic compounds : They have unpaired electrons.

Diamagnetic compounds : They have no unpaired electrons that means all are paired.

The number of unpaired electron in molecule is, 2. So, this is paramagnetic. That means, more the number of unpaired electrons, more paramagnetic.

Thus, is paramagnetic.

A chemist titrates 60.0 mL of a 0.1935 M benzoic acid (HC (H5CO2) solution with 0.2088 M KOH solution at 25 °C. Calculate the pH at equivalence. The pKg of benzoic acid is 4.20.

Answers

Answer:

pH at the equivalence point is 8.6

Explanation:

A titulation between a weak acid and a strong base, gives a basic pH at the equivalence point. In the equivalence point, we need to know the volume of base we added, so:

mmoles acid = mmoles of base

60 mL . 0.1935M = 0.2088 M . volume

(60 mL . 0.1935M) /0.2088 M = 55.6 mL of KOH

The neutralization is:

HBz + KOH ⇄ KBz + H₂O

In the equilibrum:

HBz + OH⁻ ⇄ Bz⁻ + H₂O

mmoles of acid are: 11.61 and mmoles of base are: 11.61

So in the equilibrium we have, 11.61 mmoles of benzoate.

[Bz⁻] = 11.61 mmoles / (volume acid + volume base)

[Bz⁻] = 11.61 mmoles / 60 mL + 55.6 mL = 0.100 M

The conjugate strong base reacts:

Bz⁻ + H₂O ⇄ HBz + OH⁻ Kb

0.1 - x x x

(We don't have pKb, but we can calculate it from pKa)

14 - 4.2 = 9.80 → pKb → 10⁻⁹'⁸ = 1.58×10⁻¹⁰ → Kb

Kb = [HBz] . [OH⁻] / [Bz⁻]

Kb = x² / (0.1 - x)

As Kb is so small, we can avoid the quadratic equation

Kb = x² / 0.1 → Kb . 0.1 = x²

√ 1.58×10⁻¹¹ = [OH⁻] = 3.98 ×10⁻⁶ M

From this value, we calculate pOH and afterwards, pH (14 - pOH)

- log [OH⁻] = pOH → - log 3.98 ×10⁻⁶ = 5.4

pH = 8.6

Final answer:

To calculate the pH at equivalence in a titration, we need to consider the concentration of the excess strong base in the solution. First, we calculate the moles of the acid and the base, then we find the moles of the excess base. Using this information, we can find the concentration of the excess base and subsequently calculate pOH. Finally, we can convert pOH to pH using the pH + pOH = 14 relationship.

Explanation:

pH at the equivalence point in a titration can be determined by considering the concentration of the excess strong base present in the reaction mixture. In this case, the excess strong base is KOH. We can calculate [OH-] using the stoichiometry of the reaction and the given concentrations. Then, we can find the pOH using the formula -log[OH-]. Finally, we can convert pOH to pH using the pH + pOH = 14 relationship.

Given:

Volume of benzoic acid solution (HC (H5CO2)): 60.0 mL
Concentration of benzoic acid solution: 0.1935 M
Concentration of KOH solution: 0.2088 M

Step 1: Determine the amount of benzoic acid (HC (H5CO2)) in moles:

moles of HC (H5CO2) = volume (L) × concentration (M) = 0.0600 L × 0.1935 M = 0.01161 mol

Step 2: Determine the amount of KOH in moles:

moles of KOH = volume (L) × concentration (M) = 0.0600 L × 0.2088 M = 0.01253 mol

Step 3: Determine the amount of excess KOH in moles:

moles of excess KOH = moles of KOH - moles required for neutralizing HC (H5CO2) = 0.01253 mol - 0.01161 mol = 9.2 × 10-4 mol

Step 4: Determine the concentration of excess KOH:

concentration of excess KOH = moles of excess KOH / volume (L) = 9.2 × 10-4 mol / 0.0600 L = 0.0153 M

Step 5: Determine the pOH of the solution:

pOH = -log[OH-] = -log(0.0153) ≈ 1.82

Step 6: Determine the pH of the solution:

pH = 14 - pOH = 14 - 1.82 ≈ 12.18

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Which issue is a limitation of using synthetic polymers

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The main issues of using synthetic polymers include toxicity poor biocompatibility etc. Synthetic polymers stay non-degradable for ling time and make the surface polluted.

What are synthetic polymers?

Natural polymers are naturally made substances such as cellulose, starch, glycogen etc. Polymers made by man are called synthetic polymers. Synthetic polymers are diverse and are made through several polymerization techniques.

PVC, polyethylene, polyesters Teflon etc. are very common polymers in daily life. A major class of synthetic polymers include plastics which are major pollutants nowadays.

Most of the synthetic polymers are non-biodegradable and will cause landfill issues. Some them are toxic in nature and might cause several health issues. Blending them with biodegradable polymers is a solution for this.

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Answer: As trash, Synthetic Polymers are not biodegradable. Landfills can easily fill up with synthetic polymers. Plastics can be made into different products. Recycling synthetic polymers is costly.

Explanation: Hope this helps in any way possible!

Nitrogen dioxide is one of the many oxides of nitrogen (often collectively called "") that are of interest to atmospheric chemistry. It can react with itself to form another form of , dinitrogen tetroxide. A chemical engineer studying this reaction fills a flask with of nitrogen dioxide gas. When the mixture has come to equilibrium he determines that it contains of nitrogen dioxide gas. The engineer then adds another of nitrogen dioxide, and allows the mixture to come to equilibrium again. Calculate the pressure of dinitrogen tetroxide after equilibrium is reached the second time. Round your answer to significant digits.

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Answer:

Explanation:

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