A circular chicken house has an area of 40m². What length of chicken wire is required to fence the house without any wire left over?

Answers

Answer 1

Answer: Good bless you brother I wish I can help you

Related Questions

Scrieti primi doi mmultipli omuni ai numerelor naturale a) 4 si 6 b)6 si 9 raspunsul repede va rog
I have an exam for science edexcel pls help what should i revise its physics help plslslslslsl
Will mark brainliest, 60 points
What is the 100th term in the pattern with the formula n+7
A home security system is designed to have a 99% reliability rate. Suppose that nine homes equipped with this system experience an attempted burglary. Find the probabilities of these events:_________.A. At least one alarm is triggered.B. More than seven alarms are triggered.C. Eight or fewer alarms are triggered.

Can someone help me and can y’all show me how you got the answer

Answers

Answer:

x = -8

Step-by-step explanation:

Step 1: Write equation

1/2x + 13 = 9

Step 2: Solve for x

Subtract 13 on both sides: 1/2x = -4
Multiply both sides by 2: x = -8

Step 3: Check

Plug in x to verify it's a solution.

1/2(-8) + 13 = 9

-4 + 13 = 9

9 = 9

Answer:

-8

Step-by-step explanation:

you use inverse operation

meaning opposite signs

subtract -13 from 13 cross it out

subtract 13 from 9

you get 1/2x=-4

divide 1/2 on both sides

-4 divided by 1/2 =-8

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must have a volume of 4640 cubic feet. The hemispherical ends cost twice as much per square foot of surface area as the sides. Find the dimensions that will minimize the cost. (Round your answers to three decimal places.)

Answers

The dimensions that minimize the cost of building the tank are $r\approx 6.5ft \text{ and } h \approx 26.0ft$ .

Let

$h=\text{the height of the cylindrical sides}\nr=\text{the radius of the hemispheres and the cylindrical sides}$

and

$T=\text{the total cost}\nu_c=\text{the unit cost of building the cylindrical sides}\nu_h=\text{the unit cost of building the hemispherical surfaces}$

and

$S_c=\text{the surface area of the cylinder}\n=2\pi rh\n\nS_h=\text{the total surface area of both hemispheres}\n=4\pi r^2$

Therefore,

$T=u_cSc+u_hSh$

From the question

$u_h=2u_c$

The total cost becomes

$T=u_cSc+2u_cSh\n=2u_c \pi rh+8u_c \pi r^2$

We need to eliminate $h$ . The volume from the question gives a way out

$4640=(4)/(3)\pi r^3 +\pi r^2h\n\nh=(4640)/(\pi r^2)-(4r)/(3)$

substitute into the formula for total cost gives, after simplifying

$T=(16u_c\pi r^2)/(3)+(9280u_c)/(r^2)$

differentiating with respect to $r$ , we get

$(dT)/(dr)=(32)/(3)u_c\pi r-(9280u_c)/(r^2)$

at extrema

$(dT)/(dr)=0\n\n\implies (32)/(3)u_c\pi r=(9280u_c)/(r^2)\n\nr=\sqrt[3]{(870)/(\pi)}\approx 6.5ft$

To confirm that $r$ is a minimum value, carry out the second derivative test

$(d^2T)/(dr^2)=(32u_c\pi)/(3)+(18560)/(r^3)$

substituting $r=\sqrt[3]{(870)/(\pi)}$ , we get that $(d^2T)/(dr^2)$ > $0$ , confirming that minimum value

To find $h$ , recall that

$h=(4640)/(\pi r^2)-(4r)/(3)$

substituting $r$ , we get $h\approx 26.0ft$ as the corresponding minimum height

Therefore, $r\approx 6.5ft \text{ and } h \approx 26.0ft$ minimize the total cost of building the tank.

Learn more about minimizing dimensions to reduce costs here: brainly.com/question/19053049

Final answer:

The problem involves finding the dimensions of a cylinder and two hemispheres that minimize the cost to build an industrial tank of a specific volume. This involves setting up equations for the volume and cost, and then using calculus to find the dimensions that minimize the cost.

Explanation:

This problem can be solved using calculus. Let's denote the radius of both the hemispheres and the cylinder as r and the height of the cylinder as h. The total volume of the solid is the sum of the volume of the cylinder and the two hemispheres. Using the formulas for the volumes of a cylinder and hemisphere, we have:

V = (πr²h) + 2*(2/3πr³) = 4640 cubic feet.

The total cost of the material is proportional to the surface area. The surface area of the two hemispheres is twice as expensive as that of the sides of the cylinder, so we have:

Cost = 2*(2πr²) + πrh.

To minimize the cost, we can take the derivative of the Cost function with respect to r and h, set them equal to zero, and solve for r and h.

This problem involves calculus, the volume of cylinders and spheres, and optimization, which are topics covered in high school mathematics.

Learn more about Mathematics Optimization Problems here:

brainly.com/question/32199704

#SPJ11

HELP ASAPThe highest Common Factor of two prime numbers is 1. *

Is that true or false???

Answers

Answer:

True

Step-by-step explanation:

For example:

HCF of 2 and 3 is 1

Answer:

true

Also i need help with

brainly.com/question/24136412?answeringSource=feedPublic%2FhomePage%2F1

WILL GIVE BRAINLIEST FOR THE RIGHT ANSWER!!!

Answers

ANSWE,LET two numbers be A and B then

A+B=52

A-B=14....linear equation in 2 variable

adding 2 eqns

2A=66... dividing both side by 2

A=33

and put A=33 in eqn A+B=52

B=52-33

B=19.

SO. LARGER NUMBER=33

Smaller number=19

Need help due 3 minutes!!!!!

Answers

Answer:

in standered form -

3x²+4x−14=0

Step-by-step explanation:

Hope this helps :)

A rectangle is shown. The length of the rectangle is labeled as 8 cm, and the width is labeled as 6 cm. What will be the perimeter and the area of the rectangle below if it is enlarged using a scale factor of 4.5? (5 points)Perimeter = 46 cm, area = 131.25 cm2
Perimeter = 126 cm, area = 972 cm2
Perimeter = 46 cm, area = 972 cm2
Perimeter = 126 cm, area = 131.25 cm2
Perimeter = 46 cm, area = 131.25 cm2
Perimeter = 126 cm, area = 972 cm2
Perimeter = 46 cm, area = 972 cm2
Perimeter = 126 cm, area = 131.25 cm2

Answers

Answer:

Perimeter = 126 cm, area = 972 cm2

Step-by-step explanation:

Rectangle perimeter:

P = 2(w + l)

Rectangle area:

A = wl

When scaled, the perimeter will change by same factor but the area by the square of same factor.

Applying to the given rectangle

Perimeter:

P = 2(6 + 8)(4.5) = 126 cm

Area:

A = 6*8*4.5² = 972 cm²

Correct choice is B

Answer:

Perimeter = 126cm

Area = 972cm^2

Step-by-step explanation:

6*4.5 = 27

8*4.5 = 36

Perimeter = 27*2+36*2= 126 cm

Area = 27*36 = 972 cm^2

Hope this helped!

Other Questions

A theater has a seating capacity of 750 and charges $3 for children, s5 for students, and $7 for adults. At a certain screening with fll ttendance, there were combined. The receipts totaled $3450. How many children attended the show?

Use a half-angle identity to fifd the exact value of sin 75º

Equation of lines acellus pls help ofooehhenxkdoke

PLZ HELP ME GEOMETRYquestion is below