Iron(II) chloride is added to sodium carbonate. The reaction is described by the balanced equation below. (7 points) FeCl2(aq) + Na2CO3(aq) FeCO3(s) + 2NaCl(aq) i. Write the complete ionic equation from the balanced equation. (3 points) ii. What are the spectator ions in the reaction? (1 point) iii. Write the net ionic equation from the complete ionic equation. (2 points)
Answers
Answer:
Explanation:
FeCl₂(aq) + Na₂CO₃(aq) ⇒ FeCO₃(s) + 2NaCl(aq)
complete ionic equation
Fe⁺²(aq) + 2 Cl⁻(aq) + 2 Na⁺(aq) + CO₃⁻² (aq) ⇒ FeCO₃(s)+ 2 Na⁺(aq) +2Cl⁻(aq)
Spectator ions = Cl⁻(aq) , Na⁺(aq)
Net ionic equation
Fe⁺²(aq) + CO₃⁻² (aq) ⇒ FeCO₃(s).
The Complete ionic equation:
Fe²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + CO₃²⁻(aq) → FeCO₃(s) + 2Na⁺(aq) + 2Cl⁻(aq)
ii. Spectator ions: Na⁺(aq) and Cl⁻(aq)
iii. Net ionic equation:
Fe²⁺(aq) + CO₃²⁻(aq) → FeCO₃(s)
An ionic equation is a chemical equation that shows the dissociation of all soluble ionic compounds into their respective ions in a solution. It represents the species present in their ionic form rather than as complete compounds.
In an ionic equation, only the ions involved in the chemical reaction are shown, while the spectator ions, which do not participate in the reaction, are omitted. This type of equation provides a more focused representation of the chemical reaction occurring between the ions.
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Answers
2 Fe + 3Cl2 + 2 FeCl3
Answers
The percentage yield of the reaction if 23.1 grams of FeCl₃ is created by 10.61g of Fe is 74.9 %.
What is percent yield?
Percent yield of a reaction is the ratio of actual yield to the theoretical yield multiplied by 100.
As per the given balanced reaction, one mole or 55.85 g of Fe is needed to produce 1 mole or 162.2 g of FeCl₃.
Then theoretically, the mass of FeCl₃ which can be produced by 10.61 g of Fe is calculated as follows:
= (10.61 × 162.2) / 55.85
=30.81 g
This is the theoretical yield.
The actual yield is given 23.1. Now the percentage yield is calculated as follows:
Percentage yield = (Actual yield/ heretical yield)×100
= (23.1/30.81)×100
= 74.9 %.
Hence, the percentage yield of the reaction is 74.9 %.
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Answers
Answer:
Concentration of KOH = 1.154 M
Explanation:
In the above reaction, 1 mole of oxalic acid reacts with 2 moles of KOH.
Mass of oxalic acid = 0.604 g
Molecular mass of oxalic acid = 90.03 g/mol
1 mol of oxalic acid reacts with 2 moles of KOH
0.0067 mol of oxalic acid reacts with
Volume of the solution = 27.02 mL = 0.0272 L
No. of mole of KOH = 0.0134 mol
Concentration of KOH = 1.154 M
Answers
Answer:
will i think the 21.0cm
Answers
N' = Ne^(-kt)
with N as the initial amount, k as the decay constant, and N' as the final amount. For decay, 280 days is the time it takes for the initial amount N to decay to 1/2N (half its original mass).
1/2A = Ae^(-280k)
1/2 = e^(-280k)
Solving for k, we will yield
ln(1/2) = -280k
k = ln(2) / 280 day^-1
k ≈ 2.5 × 10^-3 day^-1
Answers
Answer:
7
Explanation:
N-14 has 7
i looked it up ye ur probably gonna get it right
Answer:
7 protons + 7 neutrons!
Explanation: