A student conducts an experiment to see how music affects plant growth. The student obtains four identical plants. Each one is potted in the same type of soil and receives the sameamount of sunlight and water each day. Plant A listens to classical music for three hours each day. Plant B listens to rock music for three hours each day. Plant C listens to country
music for three hours each day. Plant D does not listen to any music at all.
1. Based on the experiment in the scenario, which visual aid would be most helpful in showing the change in the plants' heights over time?
O A. A line graph
O B. A pie chart
OC. A bar graph
O D. A timeline
Answers
Answer:
A. A line graph
Explanation:
You use line graphs to track changes over time. Line graphs are better when the changes are small. They are also more useful when you want to compare changes over the same period for more than one group, for example, plants exposed to music and a control group.
B is wrong. A pie chart is best for comparing parts of a whole.
C is wrong. You can use a bar graph to track changes over time, but small changes are harder to spot.
D is wrong. You use a timeline to mark important points in time, for example, when you are deciding the times when you must complete various stages of a project.
Which of the charts below do you think is more helpful in showing the change in plant height over time?
Related Questions
Order the materials from causing the greatest refraction to causing the least refraction.A water, air, oilB air, water, oilC oil, water, airD none of the above
Which molecule is most polar? A) CH3CHOB)CO2C)CH3ClD)C2H6E)NONE
A 3.25 L solution is prepared by dissolving 285 g of BaBr2 in water. Determine the molarity.
Compare Dalton’s and Democritus’ ideas.
Answers
Answer:
34 g
Explanation:
Let's consider the following balanced equation.
N₂ + 3 H₂ → 2 NH₃
The theoretical mass ratio of N₂ to H₂ is 28g N₂ : 6g H₂ = 4.6g N₂ : 1g H₂.
The experimental mass ratio of N₂ to H₂ is 100g N₂ : 6g H₂ = 16.6g N₂ : 1g H₂.
As we can see, hydrogen is the limiting reactant.
According to the task, we 6 g of H₂ react completely, 34 g of ammonia are produced.
Answers
Final answer:
In a reaction where two moles of C3H8 react with an excess of oxygen, the ∆H would be -4400 kJ, double the ∆H value when only one mole is reacted.
Explanation:
The given reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, has a ∆H of –2200 kJ. This represents the energy change for the reaction involving one mole of C3H8. When two moles of C3H8 react, the ∆H will be double that of the given ∆H. Therefore, when two moles of C3H8 react with excess oxygen, the ∆H would be -4400 kJ. This is because the ∆H for a reaction is directly proportional to the amount of substance reacted, hence when two moles of C3H8 are reacted, the ∆H is doubled.
Learn more about Chemical Reactions here:
#SPJ12
Answers
Iodine value is a measure of the degree of unsaturation in fats and oils. It is essentially the number of grams of iodine consumed by 100 g of fat. If the iodine number is in the range of 0-70 then it is a fat, any value above 70 is considered an oil.
Formula:
Iodine number = (ml of 0.1 N Thiosulphate blank- ml of 0.1N thiosulphate test) * 12.7 *100/1000* wt of sample
vol of thiosulphate required to titrate test sample (given oil) = 1 ml
wt of sample = 0.2 g
Information on the volume of thiosulphate required to titrate the blank solution is essential for calculation.
Iodine number = (X-1.0) * 12.7 * 100/1000* 0.2 = (X-1.0)*6.35
Answers
Answer:
6.321 × 10^22
Explanation:
Mass of Oxygen =
3.36
g
Molar mass of oxygen (
O
2
) = 16 x 2 =
32
g
m
o
l
−
Total molecules in oxygen = Mass in grams/Molar mass x
N
A
=
3.36
32
x
6.02
x
10
23
=
6.321
x
10
22
Note:
N
A
(Avagadro's number) =
6.02
x
10
23
Hope it helps...
Answers
Explanation:
Therefore the ratio is 3:3
Answers
m = pVol
p : copper density
Vol: volume
Vol = Al
A: area
L: length
m = p * A * L
L = m/p*A
To find the total resistance
Rtotal = R per Km * L/1000
Actually I think the question is missing the copper density.