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A 1.5m wire carries a 7 A current when a potential difference of 87 V is applied. What is the resistance of the wire?

Answers

Answer 1

Answer:

Answer:

$R\approx12.43 \,\, \Omega$

Explanation:

We can use Ohm's Law to find the resistance R of a wire that carries a current I under a given potential difference:

$V=I\,\,R\nR = (V)/(I) \nR=(87)/(7) \nR\approx12.43 \,\, \Omega$

Answer 2

Answer:

Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.

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A 81.0 kg diver falls from rest into a swimming pool from a height of 4.70 m. It takes 1.84 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.

Answers

Explanation:

The given data is as follows.

height (h) = 4.70 m, mass = 81.0 kg

t = 1.84 s

As formula to calculate the velocity is as follows.

$\nu$ = 2gh

= $2 * 9.8 m/s^(2) * 4.70 m$

= 92.12 $s^(2)$

As relation between force, time and velocity is as follows.

F = $(m * \nu)/(t)$

Hence, putting the given values into the above formula as follows.

F = $(m * \nu)/(t)$

= $(81.0 kg * 92.12 s^(2))/(1.84 s)$

= 4055.28 N

Thus, we can conclude that the magnitude of the average force exerted on the diver during that time is 4055.28 N.

Explain why it is dangerous to jump from a fast moving train

Answers

Answer:

When you jump off a train, you jump off a certain height and your downwards (vertical) velocity is zero. But your forward (horizontal) velocity is not. You will hit the ground on split second with your horizontal velocity practically the same as the train.

Explanation:

you be in serious injury.

The hormone glucagon is released by number of different tissues in the body to stabilize blood glucose levels. Which of the following pathways is least ikely to be activated by glucagon in hepatocytes? cells in the pancreas when blood sugar levels are low. It acts on a gluconeogenesis O glycogenolysis O ? oxidation glycolysis

Answers

Answer:

Glycolysis

Explanation:

In human body, glucose levels are regulated by hormones insulin and glucagon, secreted from pancreas. Glucagon from alpha cells and insulin from beta cells of the pancreas. Glucagon are regulated along depending upon the blood sugar levels. During fasting when blood sugar levels are decreased the glucagon levels are increased. Glucagon increases hepatic glucose through glycogenelysis.

So, Glycolysis of glucagon is least likely to be activated by glucagon in hepatocytes

A small child weighs 60 N. If mommy left him sitting on top of the stairs, which are 12 m high, how much energy does the child have!Please help ASAP

Answers

Answer:

6000 joules

Explanation:

I jus learned dis

Answer:6000j

Explanation:

Hope that helps

$\huge{\gray{\sf Question:} }$ A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2 s. Find the acceleration and velocity of the body when the displacement is (a) 5 cm, (b) 3 cm and (c) 0 cm.

Answers

Answer:

$here \: amplitude = 5cm (convert \: to \: si \: unit) = .05m \n t = .2sec \n omega = (2\pi)/(t) \n = (2\pi)/(.2 ) = 10\pi (rad)/(s) \n we \: want \: find \: a \: and \: v \n we \: know \: that \: a = - {omega}^(2) x \n v = omega \sqrt{ {r}^(2) - {x}^(2) } \n(1)x = .05m \n a = - {10\pi}^(2) * .05 = - 5 {\pi}^(2) \frac{m}{ {s}^(2) } \n v = 10\pi \sqrt{ {.05}^(2) - {.05}^(2) } = 0 \n 2)x = 3cm = .03m \n a = {(10\pi)}^(2) * .03 = - 3 {\pi}^(2) \frac{m}{ {s}^(2) } \n v = 10\pi \sqrt{ {.05}^(2) - {.03}^(2) } = 10\pi * .04 = .4\pi (m)/(s) \n 3)x = 0 \n a = - {(10\pi)}^(2) * 0 = 0 \n v = 10\pi * \sqrt{ {.05}^(2) - {0}^(2) } = - 10\pi * .05 = .5\pi (m)/(s) \n thank \: you$

Answer:

ANSWER

A = 5 cm = 0.05 m

T = 0.2 s

ω=2π/T=2π/0.2=10πrad/s

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A child is sitting on the outer edge of a merry-go-round that is 18 m in diameter. if the merry-go-round makes 5.9 rev/min, what is the velocity of the child in m/s?

Answers

Answer: The velocity of the kid is 5.6 m/s

Explanation: Ok, the velocity of the kid will be:

v = w*r

where r is the radius, and w is the frequency.

We know that the diameter is 18m, and the diameter is equal to two times the radius. So r = 18m/2 = 9m

Now, we know that the circumference of a circle is equal to c = 2pi*r, so each revolution has this length, if the kid does 5.9 revolutions in one minute, then the kid spins at v = 5.9*2pi*9m/min

But we want to write this in meters per second, this means that we need to divide it by 60.

v = (5.9*2pi*9/60)m/s = 5.56 m/s

Velocity of the child= 20008.1 m/s

Explanation;

diameter= 18 m

the linear velocity v is given by

v= r ω

r= radius=18/2= 9 m

ω= 5.9 rev/ min = 5.9 rev/min* [2π rad/ 1 rev] *[60 s/ 1 min]=2223.1 rad/s

so V= 9 (2223.1)

V= 20008.1 m/s

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