Answer:
A metropolitan area network is one step up from a local area network in geographical range.
Explanation:
A metropolitan area network is one step up from a local area network in geographical range.
A network is a group of devices connected together for communication. Networks can be classified according to the area they cover, A metropolitan area network is smaller than a wide area network but larger than a local area network.
A local area network consist of computers network in a single place. A group of LAN network form a metropolitan network
A metropolitan network is a network across a city or small region. A group of MAN form a wide area network.
Explanation:
A binary number is converted to hexadecimal number by making a group of 4 bits from the binary number given.Start making the group from Least Significant Bit (LSB) and start making group of 4 to Most Significant (MSB) or move in outward direction.If the there are less than 4 bits in last group then add corresponding zeroes to the front and find the corresponding hexadecimal number according to the 4 bits.For example:-
for this binary number 100111001011011.
100 11100101 1011
There is one bits less in the last group so add 1 zero(0) to it.
0100 1110 0101 1011
4 E 5 B
100111001011011 = 4E5B
101011.1010
0010 1011 . 1010
2 B A
=2B.A
Answer:
A. To ensure that management and the team has a clear picture of the state of the project
Explanation:
hope this helps!
Answer:
A
Explanation:
-------time
time.sleep(3)
Answer:
import
Explanation:
If this is python, you'll have to import the time module.
Answer:
Given Data:
Clock rate of P1 = 4 GHz
Clock rate of P2 = 3 GHz
Average CPI of P1 = 0.9
Number of Instructions = 5.0E9 = 5 × 10^9
Clock rate of P2 = 3 GHz
Average CPI of P2 = 0.75
Number of Instructions = 1.0E9 = 10^9
To find: If the computer with largest clock rate has the largest performance?
Explanation:
Solution:
As given in the question, clock rate of P1 = 4 GHz which is greater than clock rate of P2 = 3 GHz
According to the performance equation:
CPU Time = instruction count * average cycles per instruction/ clock rate
CPU Time = I * CPI / clock rate
Where instruction count refers to the number of instructions.
Performance of P1:
CPU Time (P1) = 5 * 10^9 * 0.9 / (4 * 10^9)
= 5000000000 * 0.9 / 4000000000
= 4500000000 / 4000000000
= 1.125s
Performance of P2:
CPU Time (P2) = 10^9 * 0.75/ (3 * 10^9)
= 750000000 / 3000000000
= 0.25s
So the Performance of P2 is larger than that of P1,
performance (P2) > performance (P1)
0.25 is better than 1.125
But clock rate of P1 was larger than P2
clock rate of P1 > clock rate of P2
4 GHz > 3 GHz
So this is a misconception about P1 and P2.
It is not true that computer with the largest clock rate as having the largest performance.
Answer:
I'm not exactly sure on what the question is, but from reading it, I determined that you'll be creating 2 different designs using Inkscape/Photoshop. I'm leaving 2 of my designs in here for you to use on your project. Unknown on what to do about the design that wasn't created in an image-editing program.
Answer:
The c# program for the scenario is given below.
using System;
public class Program2 {
double total = 0;
static void Main() {
Program2 ob = new Program2();
Console.WriteLine("Enter total energy used in kilo watts ");
int p;
p = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("Enter type of customer ");
char t;
t = Convert.ToChar(Console.ReadLine());
ob.bill_calculator(p, t);
Console.WriteLine("Total charge for " + p + " kilo watts electricity for " + t + " customers is " + ob.total);
}
public void bill_calculator(int e, char c)
{
int first=500, second = 800;
double chg_one = 0.12, chg_two=0.15, chg_three = 0.16, chg_four = 0.20;
if(c == 'R')
{
if(e <= 500)
{
total = (e * chg_one);
}
else if(e > 500)
{
total = ( first * chg_one);
total = total + ((e-first) * chg_two);
}
}
if(c == 'B')
{
if(e <= 800)
{
total = (e * chg_three);
}
else if(e > 800)
{
total = ( first * chg_three);
total = total + ((e-second) * chg_four);
}
}
}
}
OUTPUT
Enter total energy used in kilo watts
1111
Enter type of customer
B
Total charge for 1111 kilo watts electricity for B customers is 142.2
Explanation:
The program takes user input for the type of customer and the amount of electric current used by that customer.
The two input values decide the rate at which total charge is calculated.
For residential customers, charges are divided into slabs of 500 or less and more than 500.
Alternatively, for business customers, charges are divided into slabs of 800 or less and more than 800.
User input is taken in main function.
Charges are calculated in the bill_calculator method which takes both user input as parameters.
If else block is used to calculate the charges.
No input validation is implemented as it is not mentioned in the question.
All code is written inside the class. An object is created of the class.
The methods outside main() are called using the object of the class.