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What is 82 degrees below 0

Answers

Answer 1

Answer:

Answer:

-82°

Step-by-step explanation:

If we go 82° below 0, that means that instead of increasing by 82, we are decreasing by 82.

If we decrease to a number below 0, it becomes a negative number.

For example: If we decrease 10° from 0, we'd be at -10°.

Likewise, if we decrease 2° from 0, we'd be at -2°.

Following this pattern, if we decrease 82° from 0, we'd be at -82°.

Hope this helped!

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The planet Mars has two moons – Phobos and Deimos. Phobos has a mass of 10.8 × 1015 kilograms, and Deimos has a mass of 2.0 × 1015 kilograms. How much greater is the mass of Phobos than the mass of Deimos?

An object weighs 1 pound on earth weighs about 1/15 pounds on Pluto. If a man weighs 240 pounds on earth how many pounds would he weigh on Pluto?

Answers

Answer:

16 I believe. 240 divided by 15 is 16.

Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = 9x? – 36X?The graph of f(x) = x2 is widened.
The graph of f(x) = x2 is shifted right 4 units.
The graph of f(x) = x? is shifted down 36 units.
The graph of f(x) = x2 is reflected over the x-axis.

Answers

Answer: C. The graph of f(x)= x2 is shifted down 36 units

Step-by-step explanation:

Answer:

it's c

Step-by-step explanation:

A triangle has a base of 16 inches and a height of 18 1 8 inches. What is its area?

Answers

Answer:

144 in²

Step-by-step explanation:

area of a triangle = 1/2 * base * height

area = 1/2 * 16 * 18

area = 144 in²

Final answer:

The area of a triangle with a base of 16 inches and a height of 18 1/8 inches is 145 square inches.

Explanation:

The area of a triangle can be calculated using the formula: Area = 1/2 * base * height. In this case, the given base is 16 inches and the height is 18 1/8 inches.

To calculate: Area = 1/2 * 16 inches * 18 1/8 inches. Because 1/2 of 16 is 8, we can simplify this to Area = 8 inches * 18 1/8 inches.

Now, multiply 8 by 18 1/8 to find the area. The area of the triangle is 145 square inches.

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A community pool office two types of memberships monthly and annual memberships. At the beginning of the year the ratio of monthly annual memberships is 10 to 3. However the pool offered an incentive to have members move the annual membership. After the incentive the ratio is 5 to 8. If there are 50 monthly members after the incentive and how many monthly members were there before?

Answers

Answer:

The number of monthly memberships before the incentive was 100

Step-by-step explanation:

Remember that

The total memberships after the incentive is equal to the total memberships before the incentive

step 1

Find out the annual memberships after the incentive

Let

x -----> monthly memberships after the incentive

y -----> annual memberships after the incentive

we know that

-----> equation A

substitute the value of x in equation A

step 2

Find out the total memberships after the incentive

step 3

Find out the monthly members before the incentive

Let

x -----> monthly memberships before the incentive

y -----> annual memberships before the incentive

we know that

-----> equation A

-----> equation B

substitute equation A in equation B and solve for x

therefore

The number of monthly memberships before the incentive was 100

Final answer:

Initially, there were 100 monthly members at the community pool, before the incentives were offered.

Explanation:

We start with the information that the ratio of monthly to annual memberships was initially 10 to 3, and then became 5 to 8. After the incentive, we're told there are now 50 monthly members.

To solve this problem, we set up a proportion. Since each part of the new ratio equals 10 members (50 monthly members/5 parts = 10 members per part), we can infer that before the incentive there were 10*10=100 monthly members.

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Find an equation for the line parallel to 3x-5y=2 with y-intercept (0,1/5). Write the answer in slope-intercept form.

Answers

y= 3x/5 - 2/5 .i think

A city has two water towers. One tower holds 7.35 x 10 with an exponent of 5, gallons of water and the other tower holds 9.78x 10 with an exponent of 5, gallons of water. What is the combined water capacity of the two towers?

Answers

The combined capacity of the two tower would be 17.13 x 10^5 gallons of water.

How does scientific notations work?

We just ignore the 10^5, because the two numbers have the same exponent and repeat it on the result of the normal sum between the numbers.

But, for example,

5 x 10^4 + 5 x 10^5

We need to equal the exponents to do the sum without having to multiply all those tens;

5 x 10^4 + 50 x 10^4

= 55 x 10^4

or 0.5 x 10^5 + 5 x 10^5

= 5.5 x 10^5

Now returning to the question;

7.35 + 9.78 = 17.13

17.13 x 10^5

7.35 x 10^5 = 735,000

9.78 x 10^5 = 978,000

735,000 + 978,000 = 1,713,000

Or: 1713 x 10^3 or 17.13 x 10^5

The combined capacity of the two tower would be 17.13 x 10^5 gallons of water.

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Sum with scientific notation. We just ignore the 10^5, because the two numbers have the same exponent and repeat it on the result of the normal sum between the numbers.

But, for example, if we had:

-> 5 x 10^4 + 5 x 10^5

We would need to equal the exponents to do the sum without having to multiply all those tens.

5 x 10^4 + 50 x 10^4
= 55 x 10^4

or 0.5 x 10^5 + 5 x 10^5
= 5.5 x 10^5

*They are the same results.

Now returning to the question:

-> 7.35 + 9.78 = 17.13
-> 17.13 x 10^5

You can prove it yourself:

-> 7.35 x 10^5 = 735,000

-> 9.78 x 10^5 = 978,000

-> 735,000 + 978,000 = 1,713,000

Or: 1713 x 10^3 or 17.13 x 10^5

Answer: The combined capacity of the two tower is 17.13 x 10^5 gallons of water.

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