Plz help me I need so much help
Plz help me I need so much help - 1

Answers

Answer 1
Answer:

Answer:

  see below

Step-by-step explanation:

We have to assume that the question is referring to the doubly-shaded length, the one that is 10 bright blue units long.

You can read the overall length of the shaded area as 5/4, from the markings.

For the next part, you need to count the number of units that are shaded bright blue (10) and the number that are shaded blue overall (15). As a fraction of those shaded blue overall, the ones shaded bright blue are 10/15 = 2/3.

So, the length shaded bright blue is 2/3 of the overall length of 5/4. It is represented by the product ...

  \boxed{(2)/(3)*(5)/(4)}


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A type of number that includes rational and irrational numbers is ____

Answers

Answer:

Real number

Step-by-step explanation:

Those are the Real numbers.

Real numbers (R) are the conjoint of Rational Numbers (Q) - those than can be written as a fraction, e.g., 4/3, 80/456, etc. - and Irrational Numbers (I) - those that CAN'T be represented by a fraction, e.g., pi number.

So R = Q ∪ I

How many different 5-person subcommittees can be formed from a club having 12 members

Answers

Given that there are 12 persons, the first choice may be in 12 different ways, the second choice may be in 11 different ways, ther third in 10 different ways, the fourth in 9 different ways and the fith in 8 different ways, for a total of:

12x11x10x9x8 different combinations.

Now you have to take in account that 5x4x3x2 are repetitions. So you have to divide the previos counting by 5x4x3x2.

(12x11x10x9x8)/(5x4x3x2) = 792 different subcommittees.

Also, you can use the formula for combinations: C(m,n) = m! / (n! (m-n)!)

C (12, 5) = 12! / (5!) (12-5)! = [12x11x10x9x8x7!] / [5! 7!] = [12x11x10x9x8]/[5x4x3x2] = 792

Which of the following correctly represents the set of numbers using interval notation?

Answers

(-∞,-2) and [2,5) will be the correct representation of the given number line.

What is the range and domain of a function?

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The domain is for the independent variable while the range is for the dependent variable.

Given a number line with arrows.

If a number is included then it is given in the middle bracket [ ] while if it is not included then it is given in the small bracket ().

Since in the given number line,

The line is coming through -∞ and at 2 not up to

So,

(-∞,-2) will be correct.

Now,

The right-hand sideline is going from 2 to 5(not included)

So,

[2,5) will be correct.

Hence "(-∞,-2) and [2,5) will be the correct representation of the given number line".

For more details about the range and domain of the function,

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Answer:

Option 3

Step-by-step explanation:

-infinity < x< -2 , 5 > x ≥ 2

Round bracket for boundary excluded, and square bracket for boundary included

(-infinity, -2) or [2,5)

A square pyramid has a base with side lengths each measuring 40 inches. The pyramid is 21 inches tall, with a slant height of 29 inches

Answers

For solving of the area of a square pyramid, we can use the formula below:
A=a²+2a sqrt (a²/4 +h²)
where s for the slant height, r for the a/2, where a is the side length and h for the height
Substitute the values, 
A=40²+(2*40) SQRT (40²/4 +21²)
A=3920
The answer is 3920 for the area of the square pyramid.

Answer with explanation:

Base of Pyramid which is in the shape of square ,having length of each side =40 inches

Height of pyramid = 21 inches

Slant height = 29 inches

Surface area of Square Pyramid

= Area of four Triangular faces +Area of Square base

 Relation between Slant height (S), Length of base (B) and Height (H) of pyramid

 S=(√(B^2+4H^2))/(2)

29^2=\sqrt{(40^2)/(4)+21^2}

So,this is a Square pyramid.

Surface area of Pyramid

      =B*(B+2 S)\n\n=B *(B+√(B^2+4H^2))\n\n=40 *(40+√(40^2+4* 21^2))\n\n=40 *(40+√(3364))\n\n=40 *(40+58)\n\n=40 * 98\n\n=3920 square inches

Volume of Pyramid

 =(1* a^2* H)/(3)\n\n=(40^2 * 21)/(3)\n\n=1600 * 7\n\n=11200 cubic inches

Pamela has 4 pink ribbons, 3 green ribbons, and 1 blue ribbon. what fraction of Pamela's ribbons are green?

Answers

The total number of ribbons is 8 because 4 + 3 + 1 is 8
The number of green ribbons is 3
That means that 3 out of the 8 ribbons are green
Answer: 3/8
4 + 3 + 1 = 8
1 of those 8 is green
1/8

The terminal side of an angle θ in standard position passes through the point (3, 1). Calculate the exact values of the six trig functions for angle θ.

Answers

Answer:

sin α = (y)/(r) = (1)/(√(10) )

cos α = (x)/(r) = (3)/(√(10) )

tan α = (y)/(x) = (1)/(3)

cot α = (x)/(y) = (3)/(1)

sec α = (r)/(x) = (√(10) )/(3)

csc α = (r)/(y) = (√(10) )/(1)

Step-by-step explanation:

If the point is given on the terminal side of an angle, then:

Calculate the distance between the point given and the origin:

r = √(x^2+y^2)

Here it is: √(3^2+1^2) = √(9+1) = √(10)

So we have:

x = 3

y = 1

r = √(10)

Now we can calculate all 6 trig, functions:

sin α = (y)/(r) = (1)/(√(10) )

cos α = (x)/(r) = (3)/(√(10) )

tan α = (y)/(x) = (1)/(3)

cot α = (x)/(y) = (3)/(1)

sec α = (r)/(x) = (√(10) )/(3)

csc α = (r)/(y) = (√(10) )/(1)

Final answer:

The question involves calculating the six trigonometric functions (Sin, Cos, Tan, Csc, Sec, Cot) for an angle in standard position with its terminal side passing through point (3,1). We find opposite and adjacent sides from the point's coordinates, the hypotenuse from Pythagoras' theorem, and calculate each ratio accordingly.

Explanation:

In the context of the problem, the point (3,1) specifies the terminal side of angle θ in standard position. This point is effectively the definition of your right triangle's opposite (y) and adjacent (x) sides in the trigonometric calculation, with the hypotenuse (h) obtained from Pythagoras' Theorem (h² = y² + x²). In this case, we get h = sqrt(3² + 1²) = sqrt(10).

The six trigonometric functions are defined as follows for this scenario:

  • Sin θ = y/h = 1/sqrt(10).
  • Cos θ = x/h = 3/sqrt(10).
  • Tan θ = y/x = 1/3.
  • Csc θ = 1/sin θ = sqrt(10).
  • Sec θ = 1/cos θ = sqrt(10)/3.
  • Cot θ = 1/tan θ = 3.

Learn more about Trigonometric Functions here:

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