I need help i will give the brainliest
i need help i will give the brainliest - 1

Answers

Answer 1
Answer:

Answer:

the answers are

13) -6

14) 6

15) -5

16) 3

17) 14

18) -4

19) -15

20) 4

21) 5

22) -12


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both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. how high would this water rise if it were poured into the empty wide cylinder

Answers

The height of the water when poured into the empty wide cylinder is;

Option A; To the 7¹/₃ mark

Formula for volume of a cylinder is;

V = πr²h

where;

r is radius

h is height

We are told that water is poured into the wide cylinder up to the 4th mark. Thus, for the wide cylinder, h = 4. Thus;

V_wide = 4πR²

Similarly, we are told that water is poured into the narrow cylinder up to the 6th mark. Thus, for the narrow cylinder, h = 6. Thus;

V_narrow = 6πr²

Now, the volume of the water will be the same since it was the same quantity that was poured. Thus;

V_wide = V_narrow

4πR² = 6πr²

⇒ R²/r² = 6/4

simplifies to get; R²/r² = ³/₂

Now both cylinder were emptied and water poured rises to the 11th mark for the narrow cylinder. Thus;

πR²H = 11πr²

R²/r² = 11/H

Earlier, we saw that R²/r² = ³/₂. Thus;

11/H = ³/₂

H = 22/3

H =  7¹/₃

The complete question is;

Attached are the drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

A) To the 7¹/₃ mark

B)To the 8th mark

C) To the 7¹/₂mark

D)To the 9th mark

E) To the 11th mark  

Read more at; brainly.com/question/16760517

Answer:

COMPLETE QUESTION:

To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark

e)To the 11th mark

ANSWER : Option D (To the 7 1/3 mark)

Step-by-step explanation:

First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e

Volume of cylinders

π x R² x 4 = πxr²x 6

R²/r² = 6/4

after both cylinder were emptied

π x R² x h = π x r² x 11

R²/r² = 6/4 = 11/h

h = (4 x 11) /6 = 22/3 = 7 1/3 mark

Therefore, the height of the water in the wide cylinder is 7 1/3

W divided by 3 minus 5 equals 7


what is w ?

Answers

Answer:

w=36

Step-by-step explanation:

Your welcome

A line is drawn through the points (-2, 6) and (-4, -2). What is the y-coordinate of the point where this line intersects the y-axis? Pls explain!

Answers

The y intercept is 14. 

We can get this by solving for the line using the points given. First we need to find the slope. 

m(slope) = y1 - y2/x1 - x2
m = 6 - - 2/-2 - -4
m = 8/2
m = 4

Then we can find the y-intercept using slope intercept form with either given point and our newly found slope. 

y=mx + b
6 = 4(-2) + b
6 = -8 + b
14 = b

Answer:

14

Step-by-step explanation:

How do I find the lateral surface area

Answers


To find the lateral surface area of a pyramid, you can find the area of each triangle, A = 1/2bh or A = 1/2lw, then multiply by the number of triangles, which would be based on the number of sides of the base; or you can take half the perimeter and multiply by the slant height.

Answer:

200

Step-by-step explanation:

4 · 10 = 40 ( 10 is base for this one )

40 · 10 = 400 ( 10 is slant height for this one )

(400)/(2) = 200

Which fraction is bigger 7/36, or 4/9

Answers

Answer:

4/9 is bigger

Step-by-step explanation:

For the 1st fraction, since 9 × 4 = 36,

4/9 = 4 × 4

        9 × 4 = 16/36

Likewise, for the 2nd fraction, since 36 × 1 = 36,

7/36= 7 × 1

        36 × 1 = 7/36

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

16/36> 7/36 or 4/9 > 7/36

7/36 is bigger
7 goes into 36 5 times
and 4 goes in 9 only 4 times

The cost of having a package delivered has a base fee of $10.80. Every pound over 5 lbs cost an additional $0.41 per pound. Write an equation that expresses the cost C in terms of w, the total weight in pounds of a package weighing over 5 lbs. a. C = 10.8w + 0.41 c. C = 0.41(w - 5) + 10.8 b. C = 0.41w + 10.8 d. C = 0.41w + 12.85

Answers

Answer:

c. C = 0.41(w - 5) + 10.8

Explanation:

(w - 5) will represent the number of pounds over 5. For example, for a weight of 6 pounds, 6-5 = 1 is the number of pounds over 5.

The cost is $0.41 for each pound over 5, so that cost can be represented by ...

... 0.41(w - 5)

This charge is in addition to the base charge of $10.80, so the total cost will be ...

... C = 0.41(w - 5) + 10.80