Can someone plz tell me how to solve this step by step
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Answers

Answer 1
Answer:

Answer:

Explanation:

T=2π√l/g

to solve this for l we have to remove the square root in order to finish square root we have to take square on both side so the equation become

T²=4π²l/g

multiplying g on both side

T²g=4π²l

now dividing 4π² on both side

T²g/4π²=l

so l=T²g/4π²


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A sample of gold has a mass of 38.6 grams and a volume of 2 cm3. What is the density of gold

Answers

The density of the sample of gold whose mass is 38.6 grams and with a volume of 2 cm³ is 19300 kg/m

Density: This can be defined as the ratio of mass and velocity. The S.I unit of density is kg/m³.

The question above can be solved using the formula below

D = m/V.................... Equation 1

Where D = density of the sample of gold, m = mass of gold, V = volume of gold.

From the question,

Given: m = 38.6 g, = 0.0386 kg, V = 2 cm³ = 0.000002 m³

Substitute these values into equation 1

D = 0.0386/0.000002

D = 19300 kg/m³

Hence the density of the sample of gold is 19300 kg/m³

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Answer:

19.3 g/cm^3

Explanation:

The density of a material is given by

\rho = (m)/(V)

where

m is the mass of the sample

V is its volume

for the sample of gold in this problem,

m = 38.6 g

V=2 cm^3

Substituting into the formula, we find the density of gold:

\rho = (38.6)/(2)=19.3 g/cm^3

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Answer;

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Explanation;

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Answers

Answer:

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Explanation:

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