MATHEMATICS COLLEGE

Хf(x)
Use the table of values to find the function's values.
If x = 0, then f(0) =
If f(x) = 27, then x =
33
-3 -2
17
0
-15
N
-7
3
27

Answers

Answer 1
Answer:

For our particular data set, the value of the function f(x) is -2 when x = 0 (or f(0) = -2), and the value of x is 3 when f(x) = 27.

From the provided data, we see that we have specific values of x that correspond to certain values of the function f(x). Therefore, our goal is to find the value of f(x) when x = 0, and to find the value of x when f(x) = 27.

We start by finding the function value f(0). Looking at our data, we find an entry where x = 0, we observe that its corresponding f(x) value is -2. Thus, the value of the function f(x) is -2 when x = 0, so we have f(0) = -2.

Next, we're tasked with finding the value of x when f(x) = 27. To do this, we flip our perspective and look for entries in our data where f(x) = 27. After searching, we see an entry where f(x) equals to 27, and in this entry, the corresponding x value is 3. Therefore, when f(x) = 27, the value of x is 3.

In conclusion, for our particular data set, the value of the function f(x) is -2 when x = 0 (or f(0) = -2), and the value of x is 3 when f(x) = 27.

For more such question on function visit:

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Answer 2
Answer:

Answer:

If x = 0, then f(0) = -15

If f(x) = 27, then x = 3

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Is 12c + 24 equivalent to 3c + (4 +8)??

Answers

Answer:

No

Step-by-step explanation:

For example: c=1

12c + 24 =  12×1 + 24 = 36

3c + 12 = 3×1 + 12 = 15

Equivalent means equal in value. So it's not giving equal value.

A vehicle designed to operate on a drag strip accelerates from zero to 30m/s while undergoing a straight line path displacement of 45m. What is the vehicle's acceleration if its value may b assumed to be constant? A.2.0m/s
B.5.0m/s
C.10m/s
D.15m/s​

Answers

The vehicle's acceleration if its value may b assumed to be constant is 10 m/s. Therefore, option C is the correct answer.

Given that, a vehicle designed to operate on a drag strip accelerates from zero to 30m/s while undergoing a straight line path displacement of 45m.

What is an acceleration?

Acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction-or change both.

Here, Δx = 45 m, v₀ = 0 m/s and v = 30 m/s

Using the formula v² = v₀² + 2aΔx

(30 m/s)² = (0 m/s)² + 2b (45 m)

b = 10 m/s

The vehicle's acceleration if its value may b assumed to be constant is 10 m/s. Therefore, option C is the correct answer.

Learn more about the acceleration here:

brainly.com/question/12550364.

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Answer:

C. 10 m/s²

Step-by-step explanation:

Given:

Δx = 45 m

v₀ = 0 m/s

v = 30 m/s

Find: a

v² = v₀² + 2aΔx

(30 m/s)² = (0 m/s)² + 2a (45 m)

a = 10 m/s²

From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many different random samples of 4 students can be selected?

Answers

Answer:

Step-by-step explanation:

3

The​ point-slope form of the equation of a nonvertical line with slope, m, that passes through the point (x1,y1) is...?a. Ax+By=c

b. y-y1=m(x-x1)

c. y1=mx1+b

d. Ax1+by1=C

e. y=mx+b

f. y1-y=m(x-x1)

Please explain why, if you can. Thanks! :)

Answers

The equation of the line, in point-slope form, is given by:

y - y_1 = m(x - x_1)

Option b.

-----------------------------------------

The equation of a line, in point-slope form, is given by:

y - y_1 = m(x - x_1)

In which

  • m is the slope.
  • The point is (x_1,y_1).
  • Nonvertical line means that m \neq 0
  • Thus, the correct option is given by option b.

A similar problem is given at brainly.com/question/24144915

Answer:

  b. y-y1 = m(x-x1)

Step-by-step explanation:

It's a matter of definition. There are perhaps a dozen useful forms of equations for a line. Each has its own name (and use). Here are some of them.

  • slope-intercept form: y = mx + b
  • point-slope form: y -y1 = m(x -x1)
  • two-point form: y = (y2-y1)/(x2-x1)(x -x1) +y1
  • intercept form: x/a +y/b = 1
  • standard form: ax +by = c
  • general form: ax +by +c = 0

Adding y1 to the point-slope form puts it in an alternate form that is useful for getting to slope-intercept form faster: y = m(x -x1) +y1. I use this when asked to write the equation of a line with given slope through a point, with the result in slope-intercept form.

radio station KROQ broadcast in all directions to a distance of 40 miles how many square miles are in the stations broadcast area

Answers

\bf \textit{area of a circle}\n\n A=\pi r^2~ \begin{cases} r=radius\n[-0.5em] \hrulefill\n r=40 \end{cases}\implies A=\pi (40)^2\n\n\n A=1600\pi \implies A\approx \stackrel{mi^2}{5026.5}

A portfolio has average return of 13.2 percent and standard deviation of returns of 18.9 percent. Assuming that the portfolioi's returns are normally distributed, what is the probability that the portfolio's return in any given year is between -43.5 percent and 32.1 percent? A. 0.950
B. 0.835
C. 0.815
D. 0.970

Answers

Answer:

B. 0.835

Step-by-step explanation:

We can use the z-scores and the standard normal distribution to calculate this probability.

We have a normal distribution for the portfolio return, with mean 13.2 and standard deviation 18.9.

We have to calculate the probability that the portfolio's return in any given year is between -43.5 and 32.1.

Then, the z-scores for X=-43.5 and 32.1 are:

z_1=(X_1-\mu)/(\sigma)=((-43.5)-13.2)/(18.9)=(-56.7)/(18.9)=-3\n\n\nz_2=(X_2-\mu)/(\sigma)=(32.1-13.2)/(18.9)=(18.9)/(18.9)=1\n\n\n

Then, the probability that the portfolio's return in any given year is between -43.5 and 32.1 is:

P(-43.5<X<32.1)=P(z<1)-P(z<-3)\n\nP(-43.5<X<32.1)=0.841-0.001=0.840
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