The path of the water in a pond fountain can be modeled by y=-0.1x^2+2.8x , where x and y are measured in feet. The x -axis represents the surface of the pond. Find the width of the path at the surface of the pond and the height of the path.Width: ___ ft
Height: ___ ft
The path of the water in a pond fountain can - 1

Answers

Answer 1
Answer:

Answer:

the width of the path at the surface of the pond is 14 feet, and the height of the path above the surface of the pond is 19.6 feet.

Step-by-step explanation:

To find the width of the path at the surface of the pond, we need to find the x-coordinate of the vertex of the parabola y = -0.1x^2 + 2.8x. The x-coordinate of the vertex can be found using the formula:

x = -b/2a

where a = -0.1 and b = 2.8. Substituting these values, we get:

x = -2.8 / 2(-0.1) = 14

So the width of the path at the surface of the pond is 14 feet.

To find the height of the path, we need to find the y-coordinate of the vertex of the parabola y = -0.1x^2 + 2.8x. The y-coordinate of the vertex is given by:

y = f(x) = -0.1(x - h)^2 + k

where (h,k) is the vertex of the parabola. To find the vertex, we can use the formula:

h = -b/2a and k = f(h)

Substituting a = -0.1 and b = 2.8, we get:

h = -2.8 / 2(-0.1) = 14

k = f(14) = -0.1(14)^2 + 2.8(14) = 19.6

So the vertex of the parabola is (14, 19.6), which means the maximum height of the path above the surface of the pond is 19.6 feet.

Therefore, the width of the path at the surface of the pond is 14 feet, and the height of the path above the surface of the pond is 19.6 feet.


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The table shows the distances and times that four people ran. Without making any calculations, who ran the fastest?

Answers

Answer:

b is the answer very sure

Step-by-step explanation:

Answer:

Betsy

Step-by-step explanation:

UwU

triangle NOP is similar to triangle QRS. Find the measure of Side SQ. Round your answer to the nearest tenth if necessary

Answers

The measure of side SQ from the given similar triangles is 40.9 units.

What are similar triangles?

Two triangles are similar if the angles are the same size or the corresponding sides are in the same ratio. Either of these conditions will prove two triangles are similar.

Given that, triangle NOP is similar to triangle QRS.

Since the triangles are similar,

NP/SQ = NQ/QR

10/SQ = 13/53.2

13SQ=532

SQ=532/13

SQ=40.9 units

Therefore, the measure of side SQ is 40.9 units.

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Answer:

Step-by-step explanation:

Professors often attempt to determine if the submissions by the students are genuine or copied off the web sources. The program that performs this task is only 95 % accurate in correctly identifying a genuine submission and 80% accurate in correctly identifying copies. Based on the past statistics, 15% of the student turned in copied work. If a work is identified as a copy by the program, what is the probability that it is indeed a sample of copied work.

Answers

Answer:

0.7385 = 73.85% probability that it is indeed a sample of copied work.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = (P(A \cap B))/(P(A))

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Identified as a copy

Event B: Is a copy

Probability of being identified as a copy:

80% of 15%(copy)

100 - 95 = 5% of 100 - 15 = 85%(not a copy). So

P(A) = 0.8*0.15 + 0.05*0.85 = 0.1625

Probability of being identified as a copy and being a copy.

80% of 15%. So

P(A \cap B) = 0.8*0.15 = 0.12

What is the probability that it is indeed a sample of copied work?

P(B|A) = (P(A \cap B))/(P(A)) = (0.12)/(0.1625) = 0.7385

0.7385 = 73.85% probability that it is indeed a sample of copied work.

1) Between which two integers does the square root of 48 lie? *

Answers

Answer:

6 and 7

Step-by-step explanation:

I think you mean 'the sq rt of 48 lies between what 2 integers.'

The answer is 6 and 7.

Lori ran 4.63 miles last weekend and 5.876 miles this weekend. How many miles did she run in all?

Answers

Answer:

10.506

Step-by-step explanation:

its just adding and math lol- if u dont trust it look it at a calculator- hope this helped!!<3

he ran 6,339 in total

a total of 442 tickets were sold for the school play. They were either adult tickets or student tickets. There were 58 fewer

Answers

Complete Question:

A total of 442 tickets were sold for the school play. They were either adult tickets or student tickets. There were 58 fewer

There were 58 fewer student tickets sold than adult tickets.  How many adult tickets were sold?

Answer:

250 adults tickets

Step-by-step explanation:

Given

Represent Adult with A and Children with C

Total = 442

A = C + 58

Required

Find A

Since the ticket were either bought by A or C; then

A + C = Total

This gives:

A + C = 442

Substitute C + 58 for A

C + 58 + C = 442

Collect Like Terms

C + C = 442 - 58

2C = 384

Divide through by 2

C = 192

Recall that:

A = C + 58

A = 192 + 58

A = 250

Hence, 250 adults bought the ticket

There were 192 adult tickets and 250 student tickets sold for the school play, totaling 442 tickets.

  • Let's denote the number of adult tickets sold as "A" and the number of student tickets sold as "S." According to the information provided, we have two equations:
  • A + S = 442 (since a total of 442 tickets were sold).
  • A = S - 58 (since there were 58 fewer adult tickets than student tickets).
  • Now, we can use a system of equations to solve for A and S. We can substitute the value of A from the second equation into the first equation:
  • (S - 58) + S = 442
  • Combine like terms:
  • 2S - 58 = 442
  • Add 58 to both sides:
  • 2S = 442 + 58
  • 2S = 500
  • Now, divide by 2 to solve for S:
  • S = 500 / 2
  • S = 250
  • So, there were 250 student tickets sold.
  • Now, we can find the number of adult tickets (A) using the second equation:
  • A = S - 58
  • A = 250 - 58
  • A = 192
  • Therefore, 192 adult tickets and 250 student tickets were sold for the school play.

Complete question should be:

How many adult tickets and student tickets were sold for the school play if a total of 442 tickets were sold, and there were 58 fewer adult tickets than student tickets?

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