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A 1.7 kg model airplane is flying north at 12.5 m/s initially, and 25 seconds later is observed heading 30 degrees west of north at 25 m/s. What is the magnitude of the average net force on the airplane during this time interval?

Answers

Answer 1

Answer:

Average net force = 0.62 N

Explanation:

We are given;

Mass; m = 1.7 kg

Initial velocity; u = 12.5 m/s

Final velocity; v = 25 m/s

time; t = 25 seconds

Now, we are told that the final velocity was 30° west of North. So, resolving this velocity along the horizontal gives;

v = 25 cos 30°

Now, using Newton's first equation of motion gives;

v = u + at

Where a is acceleration

Plugging in the relevant values gives;

25 cos 30° = 12.5 + 25a

21.6506 - 12.5 = 25a

a = (21.6506 - 12.5)/25

a = 0.3660 m/s²

Now, magnitude of the average net force would be; F = ma

F = 1.7 × 0.366

F ≈ 0.62 N

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The gravitational force law, deduced by Newton in the 1660's, is remarkably similar to Coulomb's law. Recall that the universal law of gravitation states that the magnitude of the gravitational force between two masses M1 and M2 separated by a distance R is given by the following equation:________. F = G (M1 x M2) / R2
G = 6.67 x 10-11 Nm2/kg2
a. Calculate the value of the gravitational force between an electron (mass = 9.11 x 10-31 kg) and a proton (mass is 1836 times greater than the mass of an electron) if the two particles are separated by 3.602 nanometers. (1 nanometer or 1 nm = 1 x 10-9 m)
F= ______ N
b. The force created in the above question is:
1. repulsive
2. attractive

Answers

Answer:

a. $F=7.83* 10^(-51) N$

b.Attractive

Explanation:

We are given that

$F=(GM_1M_2)/(R^2)$

$G=6.67* 10^(-11) Nm^2/kg^2$

Mass of an electron, $M_1=9.11* 10^(-31) kg$

Mass of proton, $M_2=1836* 9.11* 10^(-31) kg$

Distance between electron and proton,R= $3.602nm=3.602* 10^(-9) m$

$1nm=10^(-9) m$

a.Substitute the values then we get

$F=(6.67* 10^(-11)* 9.11* 10^(-31)* 1836* 9.11* 10^(-31))/((3.602* 10^(-9))^2)$

$F=7.83* 10^(-51) N$

b.We know that like charges repel to each other and unlike charges attract to each other.

Proton and electron are unlike charges therefore, the force between proton and electron is attractive.

Which correctly describes how the energy of a wave on the electromagnetic spectrum depends on wavelength and frequency?A.
Energy decreases with decreasing wavelength and decreasing frequency.
B.
Energy increases with decreasing wavelength and increasing frequency.
C.
Energy increases with decreasing wavelength and decreasing frequency.
D.
Energy decreases with increasing wavelength and increasing frequency.

Answers

Answer:

B. Energy increases with decreasing wavelength and increasing frequency.

Explanation:

What occurs when a light wave enters a substance and its speed suddenly slowsdown?
refraction
Olightening
Oreflection
the vacuum effect

Answers

Final answer:

Refraction occurs when a light wave enters a substance and its speed suddenly slows down.

Explanation:

When a light wave enters a substance and its speed suddenly slows down, it undergoes a phenomenon known as refraction. Refraction occurs due to the change in speed and direction of light as it passes from one medium to another with a different refractive index. The change in speed causes the light wave to bend, resulting in a change in its path.

Learn more about Refraction here:

brainly.com/question/32684646

A flat loop of wire consisting of a single turn of cross-sectional area 7.80 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 3.30 T in 1.00 s. What is the resulting induced current if the loop has a resistance of 1.20 ?

Answers

Answer:

Explanation:

Area of crossection, A = 7.80 cm²

Initial magnetic field, B = 0.5 T

Final magnetic field, B' = 3.3 T

Time, t = 1 s

resistance of the coil, R = 1.2 ohm

The induced emf is given by

$e=(d\phi)/(dt)=A(B' - B)/(t)$

where, Ф is the rate of change of magnetic flux.

e = 7.80 x 10^-4 x (3.3 - 0.5) / 1

e = 2.184 mV

i = e/R

i = 2.184/1.2

i = 1.82 mA

If gear a rotates with a constant angular acceleration of aa = 90 rad>s2, starting from rest, determine the time required for gear d to attain an angular velocity of 600 rpm. Also, find the number of revolutions of gear d to attain this angular velocity. Gears a, b, c, and d have radii of 15 mm, 50 mm, 25 mm, and 75 mm, respectively.

Answers

solution:

$Given: (let a = alpha)aA = 90 rad/s^2(wd) = 600 rpm = 62.831 rad/s(w0) = 0 rpmra = .015 mrb = .05 mrc = .025 mrd = .075aB = aA*(ra/rb) = 90 * (.015/.05)aB = 27 rad/s^2aC = aB, Therefore aC = 27 rad/s^2aD = aC*(rc/rb) = 27 * (.025/.075)aD = 9 rad/s^2$

If a freely falling object were somehow equipped with a speedometer, its speedreading would increase each second by
a) about 15 m/s.
b) a rate that depends on its initial speed.
c) a variable amount.
d) about 5 m/s.
e) about 10 m/s.

Answers

Answer:

e) about 10 m/s

Explanation:

Acceleration due to gravity is nominally* 9.8 m/s². That means the change in velocity each second is ...

(9.8 m/s²)(1 s) = 9.8 m/s ≈ 10 m/s

_____

* This is the value expected to be used in the solution of many math and physics problems. The standard value of 'g' on Earth is defined as 9.80665 m/s². It varies from place to place and with altitude. At any given place, it may also vary with time as a result of changes in mass distribution within the Earth.

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