During the lunch break a deli sold 36 large sodas. If the ratio of large sodas sold to small sodas sold was 4:1, how many sodas were sold?

Answers

Answer 1

Answer: 36/x = 4/1 4x=36 x=9 + 36 = 45

Answer 2

Answer: Since for every small soda 4 large sodas were sold U divide 36 by 4. You get 9 so that is the total of small sodas. Then add 9 and 36 and get 45 total sodas. :) hope this helped

2/3

Step-by-step explanation:

$Let \:the \: unknown \: fraction \: be \: x\n\n(5)/(3) -x = 1\n\n(5)/(3)-x=1\n\n\mathrm{Subtract\:}(5)/(3)\mathrm{\:from\:both\:sides}\n\n(5)/(3)-x-(5)/(3)=1-(5)/(3)\n\n(5)/(3)-x-(5)/(3)=-x\n\n1-(5)/(3)=-(2)/(3)\n-x=-(2)/(3)\n\nx=(2)/(3)\n$

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each student can choose two electives. Which expression represents the probability that a student chooses an art elective and a history elective?

Answers

Answer:

$(^3C_1* ^4C_1)/(^(12)C_2)$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1* ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^(12)C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$

$=(^3C_1* ^4C_1)/(^(12)C_2)$

Which is the required expression.

Answer: Hello!

we have:

3 art electives

4 history electives

5 computer electives

which adds to a total of 12.

If the selection is random, each elective has the same probability.

The probability of selecting an art electives is the quotient between the number of art electives and the total number of electives:

3/12

suppose that this event is true, now we need to see the probability of choosing also a history elective;

We do the same process as before, we have 4 history electives and, because we already selected 1 in the previous step, we have a total of 11 electives:

the probability now is 4/11.

Now we want to calculate the joint probability of bot events is equal to the product of their probabilities; this is:

p= (3/12)*(4/12) = (4*3)/(11*12) = 12/(11*12) = 1/11

But there is also the case where the selection is in the other order (first history and second art) so the probability is equal to

2*1/11 = 2/11

Josephine noticed that out of 10 e-mails she received, 7 were advertisements. What can she predict about the number of advertisements she will receive in the next 100 e-mails?

Answers

Josephine will receive approximately 70 advertisements in the next 100 e-mails she receives.

What is the probability?

The possibility of an event in time is known as probability in mathematics. How frequently does the incidence occur over the course of a specific time period, in plain English?

If Josephine received 7 advertisements out of 10 e-mails, then we can say that the probability of receiving an advertisement in a single e-mail is 7/10 or 0.7.

Assuming that the probability of receiving an advertisement in an e-mail remains the same for all e-mails, we can use this probability to make a prediction about the number of advertisements she will receive in the next 100 e-mails.

The expected number of advertisements in 100 e-mails can be calculated by multiplying the probability of receiving an advertisement in a single e-mail by the total number of e-mails:

Expected number of advertisements = probability of an advertisement x total number of e-mails

= 0.7 x 100

= 70

Therefore, based on the given information, we can predict that Josephine will receive approximately 70 advertisements in the next 100 e-mails she receives.

To learn more about the probability;

brainly.com/question/11234923

#SPJ3

She can expect 70 to be ads since there is 10 times more emails so 7 times 10 is 70 so 70 ads

Write 9 and 250 thousandths as a mixed number

Answers

9 and 250 thousandths written as a mixed number is as much as 9 250/1000. We can simplify it, so we'll get:

9 25/100

Or even:

9 1/4

I hope it will help you :)

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