Jamie spent 4 hours a day playing video games for three weeks. How many hours did he play during three weeks

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

there are 7 days in a week so u mutiply they 3 weeks by 7 and you get 21 mutiply that by the 4 hours that he played and your answers will be 84

Answer 2

Answer:

Answer:

84 hours

Step-by-step explanation:

For a week Jamie spent a total of 28 hours (4 hours x 7 days). Since Jamie played for 3 weeks, all you need to do is multiply 28 times 3 = 84. ( 28 hours x 3 weeks)

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How do you find a constant rate of change?

Answers

Answer:

Rate of change is most commonly defined as "the change in y over the change in x", or "how much does y change when x is changed by 1 unit".

Step-by-step explanation:

The volume of a cylinder with a base diameter of 15 centimeters is about 402 cubic centimeters. whats the Height?

Answers

volume of cylinder=area of base times height
area of base=pi times radius^2
diameter=2radius
diameter/2=radius
diameter=15
15/2=radius
7.5=radius

pi=aprox 3.14
3.14 times 7.5^2
3.14 times 56.25
176.625 times height=402
divide both sides by 176.625
height=2.28

the height=2.28 cm

The table below shows the velocity y, in miles per minute, of a toy car at different times x, in minutes:Time (x)
(minutes) 10 20 30 40
Velocity (y)
(miles) 0.2 0.8 0.1 0.4

Part B: What is the value of the slope of the graph of velocity versus time between 10 minutes and 20 minutes, and what does the slope represent? (3 points)

Answers

The value of the slope of the graph of the velocity versus time between 10 minutes and 20 minutes would be .06. I got to this answer by getting the changes in the rise (y) over run (x) of the table:

slope = y2- y1 / x2-x1
= .8-.2 / 20-10 mi / min
= .6 / 10 min
= .06

Then for the follow up question, the slope represents the distance traveled of the toy car (in miles).

A ladder 39 ft long leans against a vertical wall. If the lower end is being moved away from the wall at the rate of 4 ft/sec, how fast is the height of the top changing (this will be a negative rate) when the lower end is 15 feet from the wall?

Answers

Answer:

-5/3 ft/sec

Step-by-step explanation:

In this question, we are asked to calculate the rate at which the height of the top of a ladder is changing given that the lower end is being dragged at a particular rate.

Please check attachment for complete solution and step by step explanation.

Answer:

The rate of change of height, dy / dt = -1.667 ft/s

Step-by-step explanation:

Solution:-

- The length of the ladder, L = 39 ft

- The foot of the ladder is moved away from wall at a rate, dx/dt = 4ft/s

Find:-

how fast is the height of the top changing (this will be a negative rate) when the lower end is 15 feet from the wall?

Solution:-

- We will first draw a right angle triangle, with vertical height of the ladder to be"y" and distance of the foot of the ladder and the wall to be "x".

- Then express the length "L" in terms of x and y using pythagorean theorem:

L^2 = x^2 + y^2

y^2 = 39^2 - x^2

- Taking height of the ladder as the dependent variable and distance of the foot of the ladder from wall as independent variable.

- Formulate a differential equation from the given expression above in terms of "dy/dt" and "dx/dt". Perform implicit differential of the computed expression "d/dt":

2y*dy/dt = -2x*dx/dt

dy / dt = -(x/y)*dx/dt

- Where, dy / dt : The change in height of the ladder.

- The height of the ladder at x = 15 ft is:

$y = √(39^2 - x^2) = √(39^2 - 15^2) = 36$