−2t^2+t+28=0
The solution to the equation -2t^2 + t + 28 = 0 is found by applying the quadratic formula. Upon simplification, the possible values for 't' are 4 and -3.5.
The subject of the question is Mathematics and it is related to the concept of Quadratic Equations. Then, we are given the quadratic equation -2t^2 + t + 28 = 0 and asked to solve for 't'. We can solve quadratic equations using quadratic formula which is given by -b ± √(b^2 - 4ac) / 2a.
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A. 26.12
B. 18.06
C. 36.12
D. 13.06
The answer is the option A: A. 26.12
The explanation is shown below:
1. As you need the perimeter, you can divide the figure into three triangles (as you can see in the figure attached) to calculate the length of the diagonal lines, which would be the hypotenuses of the triangles.
2. You must apply the Pythagorean Theorem to calculate the hypotenuse of each triangle:
- Red triangle (The legs are 3 and 4):
- Blue triangle (The legs are 1 and 2):
-Green triangle (The legs are 3 and 5):
3. The figure has is symmetric with respect to the y-axis. So, you can multiply the sum of the hypotenuses obtained by two to calculate the perimeter:
(b) What is the cost of renting the truck has driven 230 miles?