La altura vertical máxima alcanzada es de 31,88 m.
Tenemos la siguiente información de la pregunta;
Velocidad inicial = 25 m/s
Velocidad final = 0 m/s (a la altura máxima)
tiempo empleado = 3,5 minutos (el tiempo empleado para subir y bajar es igual).
Usando la ecuación;
v^2 = u^2 - 2gh
Dado que v = 0
u^2 = 2gh
h = tu^2/2g
h = (25)^2/2 *9.8
h = 31,88 m
Obtenga más información sobre las ecuaciones de movimiento: brainly.com/question/8898885
The subject of this question is kinematics. The ball reached a height of 65.1 meters.
To determine the height that the ball reached, we can use the kinematic equation for vertical motion:
Final height = Initial height + Initial vertical velocity * Time + (1/2) * Acceleration * Time^2
In this case, the initial height is the height of the building, the initial vertical velocity is 25 m/s, the time is 7 seconds, and the acceleration is -9.8 m/s^2. Plugging in these values, we get:
Final height = 0 + 25 * 7 + (1/2) * (-9.8) * 7^2 = 0 + 175 - 240.1 = -65.1.
Since the ball is at ground level, the height it reached is the negative of the calculated value, so the correct answer is 65.1 m.
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Answer:.
Required velocity = 6.26ms^-1
Explanation:
Given,
Distance, s = 450m
Time, t = 2 sec
Step 1. We obtain the distance covered within the given time under gravitational acceleration, g = 9.8ms^-2
S = ut + (1/2)gt^2. :; u = 0
: S = (1/2)gt^2
=(1/2) (9.8)(2^2)
= 19.6m
Step 2 :
We obtain the velocity using the formula.
V^2 = u^2 + 2gs.
Where u is initial velocity, v is final/ required velocity
Again u = 0
: V^2 = 2 (9.8)(19.6)
= 39.2
: V = 6.26ms^-1
Answer:
The acceleration of the ball is 200 m/s^2
Answer:
A
Explanation:
200 m/s squared
Answer:
Use proportions to find the scale of the first photo, then use that scale and other given information to fill in the equation
S=f/(H-h)
Where:
S = scale of the photo
f = focal length of the camera (in feet)
H = flying height
h = average elevation
Answer:
no
Explanation:
Faisal will finish the race in ...
(72 m)/(6 m/s) = 12 s
In order to beat Faisal, Edward's average speed in those 12 seconds must exceed ...
(100 m)/(12 s) = 8 1/3 m/s
To achieve that average speed, Edward's acceleration must be ...
(8 1/3 m/s -6 m/s)/(12 s/2) = 7/18 m/s² ≈ 0.3889 m/s²
Accelerating at only 0.2 m/s², Edward will not beat Faisal.
_____
Additional comment
When acceleration is uniform, the average speed is reached halfway through the period of acceleration.
2)(b) If you throw your 1.08-kg boot with an average force of 391 N, and the throw takes 0.576 s (the time interval over which you apply the force), what is the magnitude of the force that the boot exerts on you? (Assume constant acceleration.)
391 N
3)(c) How long does it take you to reach shore, including the short time in which you were throwing the boot?
Just number 3
Answer:
1a) The direction to throw the boot is directly away from the closest shore.
2b) The magnitude of the force that the thrown boot exerts on the engineer = 391 N
3c) Time taken to reach shore = 8.414 s
Explanation:
1a) Newton's third law of motion explains that for every action, there is an equal and opposite reaction.
The force generated by throwing the boot in one direction is exerted back on the engineer as recoil in the opposite direction.
Hence, the best direction to throw the boot is opposite the direction that the engineer intends to move towards.
2b) Just as explained in (1a) above, the force exerted in one direction always has a reaction of the same magnitude in the opposite direction.
Hence, the force exerted by the boot on the engineer is equal to the force exerted by the engineer on the boot = 391 N.
3c) For this part, we analyze the total motion of the engineer.
The force exerted by the boot on the engineer initially accelerates the engineer until the engineer reaches a constant velocity dictated the impulse of the initial force (since impulse is equal to change in momentum), this constant velocity then takes the engineer all the way to shore, since the ice surface is frictionless.
The weight of the engineer = W = 588 N
W = mg
Mass of the engineer = (W/g) = (588/9.8) = 60 kg
Force exerted on the engineer by the thrown boot = F = 391 N
F = ma
Initial acceleration of the engineer = (F/m) = (391/60) = 6.52 m/s²
We can then calculate the distance covered during this acceleration
X₁ = ut + ½at₁²
u = initial velocity of the engineer = 0 m/s (the engineer was initially at rest)
t₁ = time during which the force acts = 0.576 s
a = acceleration during this period = 6.52 m/s²
X₁ = 0 + 0.5×6.52×0.576² = 1.08 m
For the second part of the engineer's motion, the velocity becomes constant.
So, we first calculate this constant velocity
Impulse = Change in momentum
F×t = mv - mu
F = Force causing motion = 391 N
t = time during which the force acts = 0.576 s
m = mass of the engineer = 60 kg
v = final constant velocity of the engineer = ?
u = initial velocity of the engineer = 0 m/s
391 × 0.576 = 60v
v = (391×0.576/60) = 3.7536 m/s.
The distance from the engineer's initial position to shore is given as 30.5 m
The engineer covers 1.08 m during the time the force causing motion was acting.
The remaining distance = X₂ = 30.5 - 1.08 = 29.42 m
We can then calculate the time taken to cover the remaining distance, 29.42 m at constant velocity of 3.7536 m/s
X₂ = vt₂
t₂ = (X₂/v) = (29.42/3.7536) = 7.838 s
Time taken to reach shore = t₁ + t₂ = 0.576 + 7.838 = 8.414 s
Hope this Helps!!!
Answer:
1. Scalar
2.Vector
3. Scalar
4. Vector
5.Scalar
6.Scalar
7.Vector
8.Vector
9.Scalar
10.Scalar
11.Scalar
12. Vector
13.Scalar
Explanation:
Scalar refers to magnitude, and Vectors include magnitude with directions.