Answers
Answer:
The woman's distance from the right end is 1.6m = (8-6.4)m.
The principles of moments about a point or axis running through a point and summation of forces have been used to calculate the required variable.
Principle of moments: the sun of clockwise moments must be equal to the sun of anticlockwise moments.
Also the sun of upward forces must be equal to the sun of downward forces.
Theses are the conditions for static equilibrium.
Explanation:
The step by step solution can be found in the attachment below.
Thank you for reading this solution and I hope it is helpful to you.
Related Questions
If you want to play a tune on wine glasses, you’ll need to adjust the oscillation frequencies by adding water to the glasses. This changes the mass that oscillates (more water means more mass) but not the restoring force, which is determined by the stiffness of the glass itself. If you need to raise the frequency of a par- ticular glass, should you add water or remove water?
Find the force on a 5 pС charge in a place where the electric field is 400 N/C.
You know that you sound better when you sing in the shower. This has to do with the amplification of frequencies that correspond to the standing-wave resonances of the shower enclosure. A shower enclosure is created by adding glass doors and tile walls to a standard bathtub, so the enclosure has the dimensions of a standard tub, 0.75 m wide and 1.5 m long. Standing sound waves can be set up along either axis of the enclosure. What are the lowest two frequencies that correspond to resonances on each axis of the shower? These frequencies will be especially amplified. Assume a sound speed of 343 m/s.
A uniform, 4.5 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its upper edge. A 1.3 kg raven flying horizontally at 4.5 m/s flies into this door at its center and bounces back at 2.5 m/s in the opposite direction. (a) What is the angular speed of the gate just after it is struck by the unfortunate raven? (b) During the collision, why is the angular momentum conserved but not the linear momentum?
b. Wavelength of the wave?
c. Write down a mathematical expression for the wave, substituting numbers for the variables
Answers
Answer:
(a) The speed of the wave, v is 4.2 m/s
(b) Wavelength of the wave, λ is 0.35 m
(c) mathematical expression of the wave, Y = 0.036sin(5.71πx - 24πt)
Explanation:
Given;
tension on the string, T = 15 N
Linear density, μ = 0.85 kg/m
amplitude of the wave, A = 3.6 cm = 0.036 m
frequency of the wave, f = 12 Hz
(a) The speed of the wave, v is calculated as;
(b) Wavelength of the wave, λ
v = fλ
λ = v / f
λ = 4.2 / 12
λ = 0.35 m
(c) mathematical expression of the wave;
45 N
450 N
450 kg
10N
Answers
Answer:
450N
Explanation:
weight= m*g
weight=45*10
weight=450N
Answers
The distance for both Parts A and B are given in the question.
A balloon drifts 140m toward the west in 45s.
The wind suddenly changes and the balloon flies 90m toward the east in the next 25s.
To find the total distance, we can just add.
140 + 90 = 230m
Best of Luck!
B. 1700 Hz, 5100 Hz
C. 3400 Hz, 6800 Hz
D. 3400 Hz, 10,200 Hz
Answers
Answer:
B. 1700 Hz, 5100 Hz
Explanation:
Parameters given:
Length of ear canal = 5.2cm = 0.052 m
Speed of sound in warm air = 350 m/s
The ear canal is analogous to a tube that has one open end and one closed end. The frequency of standing wave modes in such a tube is given as:
f(m) = m * (v/4L)
Where m is an odd integer;
v = velocity
L = length of the tube
Hence, the two lowest frequencies at which a dog will have increased sensitivity are f(1) and f(3).
f(1) = 1 * [350/(4*0.052)]
f(1) = 1682.69 Hz
Approximately, f(1) = 1700 Hz
f(3) = 3 * [350/(4*0.052)]
f(3) = 5048 Hz
Approximately, f(3) = 5100 Hz
Answers
Answer:
A. Weak forces
Explanation:
The fundamental forces responsible for beta decay is the weak force. Weak forces are among the four fundamental forces of universe the electromagnetic, gravitational and strong forces. The weak forces are responsible for the decaying. The fundamental work of weak forces is covert neutron into proton and electron into neutrino. weak forces operate at very low distances as low as fermi meter.
Answer:
The answer is
dark energy force.
hope this helps u stay safe
Explanation:
Answers
Answer:
69.69 g
Explanation:
Evaporation of water will take out latent heat of vaporization. Let the mass of water be m and latent heat of vaporization of water be 2260000 J per kg
Heat taken up by evaporating water
= 2260000 x m J
Heat lost by body
= mass x specific heat of body x drop in temperature
60 x 3500 x .750 ( specific heat of human body is 3.5 kJ/kg.k)
= 157500 J
Heat loss = heat gain
2260000 m= 157500
m = .06969 kg
= 69.69 g
Final answer:
Approximately 78 grams of water would need to evaporate from a 60.0-kg person to lower their body temperature by 0.750ºC. This calculation is based on the principles of thermodynamic heat transfer and the specific body temperature, latent heat of water vaporization, and specific heat capacity of the human body.
Explanation:
To calculate the amount of water mass from an individual's body that would need to evaporate to reduce their body temperature, we can use the principle of thermodynamic heat transfer. The basic equation is Q = mLv, where Q is the heat absorbed or lost, m is the mass, and Lv is the latent heat of vaporization.
In this case, knowing that at body temperature of 37.0°C, the latent heat of water vaporization (Lv) is approximately 2430 kJ/kg, we substitute these numbers. Given our desire to reduce body temperature by 0.750°C in a 60 kg human, we first calculate the amount of heat to dissipate (Q) using Q = mcΔT, where c is the specific heat capacity of the human body (roughly equivalent to that of water, 4.184 kJ/kg°C), m is the mass, and ΔT is the change in temperature.
The calculation is as follows:
Q = (60 kg)(4.184 kJ/kg°C)(0.750°C) = ~189 kJ
Next, we substitute Q into the Q = mLv equation to determine the mass m:
m = Q / Lv = 189 kJ / 2430 kJ/kg = 0.078 kg, or 78 grams
Hence, around 78 grams of water would need to evaporate from a 60.0-kg person to lower their body temperature by 0.750ºC.
Learn more about Heat Transfer here:
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