Which statement correctly compares an atom of an alkali metal with an atom of the alkaline earth metal next to it on the periodic table? aThe alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion. bThe alkali metal atom forms a +2 ion, while the alkaline earth metal atom forms a +1 ion. cThe alkali metal atom has one less shell of electrons than the atom of the alkaline earth metal. dThe alkali metal atom has one more shell of electrons than the atom of the alkaline earth metal.
Answers
All of the elements in Group 1 are alkali metals, and they are all soft in composition. The alkali earth metals that make up the group of two elements are all hard by nature. Their melting points are low. The correct option is A.
All alkali metals have one electron in their outermost shell, but all alkaline earth metals have two outer electrons. This is the main distinction between alkali metals and alkaline earth metals.
Since an alkali metal has one electron in its outermost shell, it will give up this electron in order to become stable, forming a positive ion in the process. Similar to this, since alkali earth metals have two electrons in their outermost shells, they will give up those two electrons in order to become stable, generating +2 ions.
Thus the correct option is A.
To know more about alkali metals, visit;
#SPJ3
Answer:
A) The alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion.
Explanation:
Let's evaluate each answer.
A: The alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion.
This means that the alkali metal atom has to lose 1 valence electron to form a +1 ion while the alkaline earth metal atom has to lose 2 valence electrons to form a +2 ion. This is accurate because alkali metal atoms have 1 valence electron while alkaline earth metal atoms have 2, so the statement is correct.
B: The alkali metal atom forms a +2 ion, while the alkaline earth metal atom forms a +1 ion.
This would mean that the alkali metal atom has to lose 2 valence electrons to form a +2 ion, while the alkaline earth metal has to lose 1 valence electron to form a +1 ion. This is incorrect because alkali metal atoms only have 1 valence electron and will become a +1 ion when losing that electron, while alkaline earth metals have 2 valence electrons and will form a +2 ion upon losing them.
C: The alkali metal atom has one less shell of electrons than the atom of the alkaline earth metal.
This would mean that the alkali metal atom would be located one period higher up than the alkaline earth metal atom. This is untrue, because the question states that the alkali metal atom is located directly next to the alkaline earth metal atom, so they have the same amount of electron shells.
D: The alkali metal atom has one more shell of electrons than the atom of the alkaline earth metal.
This would mean that the alkali metal atom would be located one period lower on the periodic table than the alkaline earth metal atom. Similar to the previous statement, this is untrue because the question states that they are located directly next to each other, or on the same period.
(Also, I just took this quiz and e2020 says it's right.)
Related Questions
The pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl is ________.
Research some ways in which scientists and engineers have harnessed and currently use the energy in fossil fuels to benefit society. Think about how these methods involve a chemical reaction, and explain how energy is conserved. Describe one method of using fossil fuels for energy, and state one advantage and disadvantage about this method. In your replies to others' comments, state whether you agree or disagree with the advantages and disadvantages they list and explain your reasoning. Hint: Consider what happens to fossil fuels (such as coal, natural gas, and petroleum) when they are burned.
Which of the following is true for the quantum mechanical atomic model? A. Atoms absorb or emit electrons from the nucleus when they interact with electromagnetic radiation. B. Every atom absorbs all wavelengths of light energy or electromagnetic radiation. C. Electrons give off electromagnetic radiation when they jump from a high to a low energy level. D. Electrons are perfectly evenly distributed throughout the atom.
What is an acronym for the rainbow colors?I just want to know if anybody else knows this.
Answers
Answer:
ΔHrxn = 193107.69 J/mol
Explanation:
ΔHrxn = mcΔT
m = mass
c = heat capacity
ΔT = temperature variation
density = m/V
m = density x V
m = 1.00 g/mL x 400.0 mL
m = 400.0 g
ΔHrxn = mcΔT
ΔHrxn = 400 g x 4.184 J/g°C x 6.00 °C
ΔHrxn = 10041.6 J
CaO + 2HCl → CaCl₂ + H₂O
CaO = 56.0774 g/mol
2.90 g CaO = 0.052 mol
400.0 mL of 1.500 mol/L HCl = 0.6 mol HCl
ΔHrxn = 10041.6 J is for 0.052 mol of CaO
ΔHrxn = 193107.69 J is for 1 mol of CaO
Answers
Answer: 1.5 m
Explanation: E=mgh=Fh
30 J = 20 N * h
h = 30/20 = 1.5 m
Answer:
1.5 m
Explanation:
it just is its easy made A on test
Answers
Answer:
The daughter nuclides of these two decay processes are and
.
Explanation:
The beta emission is represented by:
A = (Z + 1) + (n - 1) = is invariant
n: neutron
p: proton
Hence, the daughter nuclide of the beta emission of Ir-192 is:
Now, electron capture is represented by:
A = (Z - 1) + (n + 1) = is invariant
Then, the daughter nuclide of the electron capture of Ir-192 is:
Therefore, the daughter nuclides of these two decay processes are and
.
I hope it helps you!
Answers
Answer:
H2O (water)
N2 (nitrogen)
O3 (ozone)
CaO (calcium oxide)
Explanation:
HOPE IT HELPS
Answers
Answer:
3 > 2> 1
Explanation:
Aromatic compounds undergo electrophilic substitution reaction which passes through a positively charged intermediate to yield the product.
Substituted benzenes may be more or less reactive towards electrophilic aromatic substitution than benzene molecule depending on the nature of the substituent.
Certain substituents increase the ease of reaction of benzene towards aromatic substitution.
If we look at the compounds closely, we will notice that toluene reacts readily with CH3Cl / AlCl3. This is because, the methyl group is electron donating hence it stabilizes the positively charged intermediate produced in the reaction.
Carbonyl compounds are electron withdrawing substituents hence they decrease the magnitude of the positive charge and hence decrease the rate of electrophilic aromatic substitution.