What are the steps to solving this limit?
What are the steps to solving this limit? - 1

Answers

Answer 1
Answer:

Answer:

lim(x---->0) = -5

Step-by-step explanation:

first: sin(x-π/2)= -cosx

so the equation will be :

lim(x---->0) = [-6cos(ax)-1}/cosx

solve :

lim(x---->0) =  [-(6cos(a(0))-1}/cos(0)

cos0=1

lim(x---->0)=(-(6(1)-1)/1

lim(x---->0)=-6+1/1

lim(x---->0)=-5


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How do i identify the slope,y intercept,x intercept, and zero on a graph

Answers

To find the slope of a line, you need to find the change in x over the change in y, or rise over run. You can do this by taking two points and using the formula (y_(2) -y_(1))/(x_(2) -x_(1)).

To find the y-intercept, find where the graph touches the y-axis.

To find the x-intercept, find where the graph touches the x-axis.

Zeroes on a graph are the same as its x-intercepts.

Simplify this expression 1x/18x

Answers

Wouldn't it be 1/18x?????

Answer: 1/18

Step-by-step explanation: The x's basically cancel each other out so all that is left is the 1 and the 18

Write a linear equation to represent the line shown on the graph

Answers

The linear equation representing the line passing through the points (0, 4) and (2, -2) is y=−3x+4.

Here, we have to write a linear equation that represents the line passing through the points (0, 4) and (2, -2), we can use the point-slope form of a linear equation:

y - y_1 = m(x- x_1)

where:

m is the slope of the line,

(x_1,y_1)is one of the given points on the line.

Given the points (0, 4) and (2, -2),

let's calculate the slope m:

m= −2−4/ 2−0

 = −6/2

 =−3.

Now, use the point-slope form with the point (0, 4):

y−4=−3(x−0).

Simplify the equation:

y−4=−3x.

Add 4 to both sides:

y=−3x+4.

So, the linear equation representing the line passing through the points (0, 4) and (2, -2) is y=−3x+4.

To learn more on equation click:

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Answer:

y=-3x+4

Step-by-step explanation:

it's negative bc the slope is going from left to right. you just have to do rise over run to find the slope.

NEED HELP ASAP WILL GIVE BRAINLIEST AND 15 POINTS
1/3x + 3 - 5/6x = -15

Answers

 \bold{Hello!}\n\bold{Your~Answer~Is~Below!}

______________________________

 \bold{Solution~Steps:}

1.)~Combine~(1)/(3)m~and~-(5)/(6)m:

  • \bold{(1)/(3)m+-(5)/(6)m=-(1)/(2)m }
  • \bold{You~could~also~solve~this~by~turning~the~fractions~into~decimals.}

2.)~Subtract~3~from~both~sides:

  • \bold{3-3=Cancels~Out}
  • \bold{-15-3=-18}
  • \bold{We~do~the~opposite~of~what~we~see:+3,~meaning~we~subtract.}

3.)~Multiply~both~sides~by -2:

  • \bold{-(1)/(2)m} × \bold{-2=Cancels~Out}
  • \bold{-18} × \bold{-2=36}
  • \bold{The-2~is~from-(1)/(2)m.~Since~it's~dividing~we~do~the~opposite~and~multiply~by~-2.}

______________________________

 \bold{Answer:}

  • \bold{m=38}

______________________________

 \bold{Hope~this~helps,}\n\bold{And~best~of~luck!}\n\n\bold{~~~~~-TotallyNotTrillex}

The perimeter of a rectangular room is 32m.The length of a diagonal is 8m more than than the width.Find the dimensions of the room.

Answers

Answer: 12m by 4m.

Step-by-step explanation: You are looking for the dimensions of the room here, also known as the length and width.

Let’s make width equal to x since we don’t know what the value is. Length is going to be x + 8 since the diagonal is 8m MORE than the width.

w = x

l = x + 8

Use the equation for the perimeter.

P = 2l + 2w

Plug in your values:

32 = 2(x + 8) + 2(x)

Now, solve for x! First start by distributing the 2:

32 = 2x + 16 + 2x

Next, add like terms:

32 = 4x + 16

Subtract 16 from both sides:

16 = 4x

Divide by 4 on both sides:

4 = x

Now we have x, but remember, x is equal to the width. We just solved for width so now we need length.

l = x + 8

Plug in your x and solve:

l = 4 + 8

l = 12

Your length is 12m and your width is 4m, therefore, the dimensions of the rectangular room are 12m by 4m.

Find the coordinates of the vertices after the given transformation. Reflection across x=-2. W(-4,-4)

Answers

Answer:

To reflect a point across the vertical line x = -2, we can use the formula:

(x, y) → (2c - x, y)

where c is the x-coordinate of the line of reflection. In this case, c = -2. Let's apply this formula to the point W(-4, -4):

W' = (2(-2) - (-4), -4)

= (-4 + 4, -4)

= (0, -4)

Therefore, after the reflection across x = -2, the coordinates of W(-4, -4) become W'(0, -4).

Step-by-step explanation: