Round the following whole number to the nearest thousand.
9474

Answers

Answer 1
Answer:

Answer:

9,000

Step-by-step explanation:

9474

Locate the thousands place:

9474

Check the number to the right:

9474

If the number is greater than or equal to 5, we round up. If the number is less than or equal to 4, we round down.

Since there is a '4', we round down.

9474 ≈ 9000

Hope this helps.


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Simplify the expression. -14 x 8 x 1/4 + (-22) a. –50 b. –138 c. –470 d. –6
What is the given equation in logarithmic form of 7^4=2,401?
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Find the GCF of 4x^2 y and 6xy^3

Two similar polygons have areas of 16 square inches and 64 square inches. The ratio of a pair of corresponding sides is 1/4. a. True
b. False

Answers

Your answer is A. True.

Hope this helps.


Which two numbers add up to 5 and multiply to -45 ?

Answers

we have x+y=5
xy=-45
solve
x+y=5
subtract x from both sides
y=-x+5
subsiute -x+5 for y in second equaiton
x(-x+5)=-45
-x^2+5x=-45
add 2x^2-5x to both sides
0=x^2-5x-45
use quadratic equation which is
if you have 0=ax^2+bx+c then x=\frac{-b+ \sqrt{b^(2)-4ac} }{2a} or \frac{-b- \sqrt{b^(2)-4ac} }{2a}
sbsitute
1x^2-5x-45
a=1
b=-5
c=-45
subsitute
\frac{-(-5)+ \sqrt{-5^(2)-4(1)(-45)} }{2(1)}
(5+ √(25-(-180)) )/(2)
(5+ √(25+180) )/(2)
(5+ √(205) )/(2)
or\frac{5- \sqrt{} }{2} or aprox x=-4.65891 or 9.65891, so the 2 numbers would be those answers for x



In this problem, y = c₁eˣ + c₂e⁻ˣ is a two-parameter family of solutions of the second-order DE y'' − y = 0. Find a solution of the second-order IV P consisting of this differential equation and the given initial conditions. y(-1) = 4, y'(-1) = -4.

Answers

Answer:

y=4e^(-(x+1)) will be the solutions.

Step-by-step explanation:

The given equation is y=C_(1)e^(x)+C_(2)e^(-x)

Therefore, for x = -1

4=C_(1)e^(-1)+C_(2)e^(1) ------(1)

Now y'(-1) = -4

y'(x) = C_(1)e^(x)-C_(2)e^(-x) = -4

C_(1)e^(-1)-C_(2)e^(1) = -4 -----(2)

By adding equation (1) and (2)

2C_(1)e^(-1)=0

C_(1)=0

From equation (1),

4=0+C_(2)e^(1)

C_(2)=4e^(-1)

By placing the values in the parent equation

y = 4e^(-1)* e^(-x)

y = 4e^(-(x+1))

Which terms and 45p4q have a GCF of 9p3? Check all that apply. 18p3r
27p4q
36p3q6
63p3
72p3q6

Answers

Answer:

 18p^3r

and  63p^3

Step-by-step explanation:

We have to check which term and 45p^4q has GCF  9p^3

GCF of  18p^3r   and  45p^4q= 9p^3

GCF of  27p^4q   and  45p^4q= 9p^4q

GCF of  36p^3q^6   and  45p^4q= 9p^3q

GCF of  63p^3   and  45p^4q= 9p^3

GCF of  72p^3q^6   and  45p^4q= 9p^3q

Hence, the correct answer is:

  18p^3r

and  63p^3

18p^3r and 63p^3 are the answer

which of the following expressions is equivalent to 20 - 4/5 x > (the > has a line under it) 16?

Answers

20-(4)/(5)x\geq16\ \ \ \ |both\ sides\ -20\n\n-(4)/(5)x\geq-4\ \ \ \ |both\ sides\ :(-(5)/(4)) < 0\ then\ change\

What is 3/5 minus 1/4?

Answers

7/20 since 3/5 is 12/20 and 1/4 is 5/20
first get a common denominator, 5 and 4 share 20 as a least common denominator. next, multiply the tops to match the bottom. 12/20 – 5/20 = 7/20