What type of angle is <CEB?
Answers
Answer:
obtuse angle
Step-by-step explanation:
m(<CEA)=m(<BED)=88 (vertically opposite angles)
So m(<CEB)+m(<AED)=360-(88+88)=182
m(<CEB)=m(<AED)= 182÷2=92
Related Questions
What is the value of the expression below when c - 5 and d - 4 (c is to the second power)?6c2-5d+8
Pls help me with this question!!!
3 2/3+ 5 1/2 .....................???
{x-3y=24}{3x+Y=12}Solve each of the following linear systems by eliminating
1.56%
56.25%
0.56%
Answers
x% of $16 is $25
x% * 16 = 25
x/100 * 16 = 25
x = 25 * 100 / 16
x = 156.25%
156.25% - 100% = 56.25%
The correct result would be 56.25%.
Answers
Step-by-step explanation:
To make the function f(x) = {sin(1/x), x ≠ 0; k, x = 0} continuous at x = 0, we need to find the value of k that ensures the limit of f(x) as x approaches 0 exists and is equal to k.
First, let's find the limit of sin(1/x) as x approaches 0:
lim(x -> 0) sin(1/x)
This limit does not exist because sin(1/x) oscillates wildly as x gets closer to 0. Therefore, in order for the function to be continuous at x = 0, we need to choose k such that it compensates for the oscillations of sin(1/x) as x approaches 0.
A suitable choice for k is 0 because the limit of sin(1/x) as x approaches 0 is undefined, and setting k = 0 ensures that f(x) becomes a continuous function at x = 0.
So, the correct choice is:
d. None (k = 0)
Final answer:
The value of k that would make the function f(x) = sin(1/x) when x ≠0 and f(x) = k when x=0 continuous at x=0 doesn't exist. This is because the limit of sin(1/x) as x approaches 0 is undefined, hence the function cannot be made continuous at x = 0 for any value of k.
Explanation:
To find the value of k that makes the function continuous at x=0, we can apply the definition of continuity, which states that a function, f(x), is continuous at a certain point, x0, if three conditions are met:
- the function is defined at x0
- the limit as x approaches x0 of f(x) exists
- the limit as x approaches x0 of f(x) is equal to f(x0)
In the case of the function f(x) = sin(1/x), the value for x = 0 is undefined, but we've been given that f(0) = k. To make the function continuous at x = 0, the value of k should ideally be equal to the limit of sin(1/x) as x approaches 0.
However, as x approaches 0, sin(1/x) oscillates between -1 and 1, making the limit non-existent. Because the limit does not exist, the function is not continuous at x=0 no matter the chosen value of k. Therefore, the correct answer is (d) None.
Learn more about Limits and Continuity here:
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Answers
Let y = the tens digit
x+2y=12
x=2y
x+y=12 substitute x for 2y to get:
(2y)+y=12 add like terms to get:
3y=12
3y=12 divide both sides by 3 to get:
y=4
x+y=12 substitute y for 4 to get:
x+4=12 subtract 4 from both sides to get:
x=8
so if x=ones
and y=tens
then the answer is 48
So we have two equations:
t = 2o (1)
t+o = 12 (2)
Subtract (2) from (1) and we get o = 12-2o
Now solve for o:
3o = 12
o = 4
Now plug in (1) or (2) and we have t = 8
Therefore our number is 10t + o = 84
Answers
Answer:
CP = 6
Step-by-step explanation:
The length of segment BC is given by the Pythagorean theorem:
AC² = AB² +BC²
(√61)² = 5² + BC² . . . . . fill in the given numbers
61 -25 = BC² = 36 . . . . .subtract 25
BC = 6 . . . . . . . . . . . . . . take the square root
Since the center of the circle is on AB and is tangent to BC, it must pass through point B. That is, segment BC of length 6 is one of the tangent lines from point C. The other one, to point P, must be the same length, so ...
CP = 6
Answers
Answers
Answer:
y= -6x+23
Step-by-step explanation:
perpendicular: opposite signs and reciprocal
m= 1/6 and y-intercept = 23
y= -6x+23